#pragma GCC optimize("Ofast") #include using namespace std; typedef long long int ll; typedef unsigned long long int ull; mt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count()); ll myRand(ll B) { return (ull)rng() % B; } inline double time() { return static_cast(chrono::duration_cast(chrono::steady_clock::now().time_since_epoch()).count()) * 1e-9; } template struct static_modint { using mint = static_modint; int x; static_modint() : x(0) {} static_modint(int64_t y) : x(y >= 0 ? y % mod : (mod - (-y) % mod) % mod) {} mint& operator+=(const mint& rhs) { if ((x += rhs.x) >= mod) x -= mod; return *this; } mint& operator-=(const mint& rhs) { if ((x += mod - rhs.x) >= mod) x -= mod; return *this; } mint& operator*=(const mint& rhs) { x = (int) (1LL * x * rhs.x % mod); return *this; } mint& operator/=(const mint& rhs) { return *this = *this * rhs.inv(); } mint pow(long long n) const { mint _x = *this, r = 1; while (n) { if (n & 1) r *= _x; _x *= _x; n >>= 1; } return r; } mint inv() const { return pow(mod - 2); } mint operator+() const { return *this; } mint operator-() const { return mint() - *this; } friend mint operator+(const mint& lhs, const mint& rhs) { return mint(lhs) += rhs; } friend mint operator-(const mint& lhs, const mint& rhs) { return mint(lhs) -= rhs; } friend mint operator*(const mint& lhs, const mint& rhs) { return mint(lhs) *= rhs; } friend mint operator/(const mint& lhs, const mint& rhs) { return mint(lhs) /= rhs; } friend bool operator==(const mint& lhs, const mint& rhs) { return lhs.x == rhs.x; } friend bool operator!=(const mint& lhs, const mint& rhs) { return lhs.x != rhs.x; } friend ostream &operator<<(ostream &os, const mint &p) { return os << p.x; } friend istream &operator>>(istream &is, mint &a) { int64_t t; is >> t; a = static_modint(t); return (is); } }; const unsigned int mod = 998244353; using modint = static_modint; modint mod_pow(ll n, ll x) { return modint(n).pow(x); } modint mod_pow(modint n, ll x) { return n.pow(x); } int main(){ cin.tie(nullptr); ios::sync_with_stdio(false); ll c,y; cin >> c >> y; vector v = {10000, 5000, 2000, 1000, 500}; vector cnt(5); ll cur = 0; for (int i = 0; i < 5; ++i) { cnt[i] = y/v[i]; y %= v[i]; } cur = y/100; if (cur >= c) { cout << "no exchange" << endl; } else { ll uo = cnt[0]*20 + cnt[1]*10 + cnt[2]*4 + cnt[3]*2 + cnt[4]; if (cur+uo*5 < c) { cout << "can't exchange" << endl; } else { ll need = (c-cur+4)/5; cur += need*5; cout << cur << endl; } } }