#include #include using ll = long long; using ull = unsigned long long; #define rep(i, n) for(int i = 0; i < (int)(n); i++) #define REP(i, m, n) for(int i = (int)(m); i < (int)(n); i++) using namespace std; using namespace atcoder; using mint = modint998244353; const int inf = 1000000007; const ll longinf = 1ll << 60; int main() { ios::sync_with_stdio(false); cin.tie(0); cout.tie(0); int n, m; cin >> n >> m; vector> p(n), q(m); rep(i, n) { cin >> p[i].first >> p[i].second; p[i].second++; } rep(i, m) { cin >> q[i].first >> q[i].second; q[i].second++; } int k; cin >> k; vector a(k); rep(i, k) cin >> a[i]; sort(p.begin(), p.end()); sort(q.begin(), q.end()); rep(i, n - 1) { if(p[i].second > p[i + 1].first) { rep(i, k) cout << "1 "; cout << endl; return 0; } } rep(i, m - 1) { if(q[i].second > q[i + 1].first) { rep(i, k) cout << "1 "; cout << endl; return 0; } } vector ans(k); rep(i, m) { rep(j, k) { ll l = 2 * a[j] - q[i].second + 1, r = 2 * a[j] - q[i].first + 1; int _idx = lower_bound(p.begin(), p.end(), make_pair(l, r)) - p.begin(); _idx -= 2; rep(ii, 5) { int idx = ii + _idx; if(idx < 0 || idx >= n) continue; if(max(p[idx].first, l) < min(p[idx].second, r)) { ans[j] = 1; } } } } rep(i, k) cout << ans[i] << " \n"[i + 1 == k]; return 0; }