/*               ∧∧∩               ( ゚∀゚)/ キタ━━━━━━(゚∀゚)━━━━━━!!!!             ⊂   ノ  ゆっくり見てってね!!!!!!!!              (つ ノ     o          (ノ      \      ☆              |      o           (⌒ ⌒ヽ   /     ☆     \  (´⌒  ⌒  ⌒ヾ   /       ('⌒ ; ⌒   ::⌒  )      (´     )     ::: ) /   ☆─ (´⌒;:    ::⌒`) :;  ) */ #include #include using namespace std; using namespace atcoder; #define rep(i, s, n) for(int i=s; i std::istream &operator>>(std::istream&is,std::vector&v){for(T &in:v){is>>in;}return is;} template std::ostream &operator<<(std::ostream&os,const std::vector&v){for(auto it=std::begin(v);it!=std::end(v);){os<<*it<<((++it)!=std::end(v)?" ":"");}return os;} // 回文かどうかの判定 bool iskaibun(string s){ll k = s.size();rep(i,0,k/2){if(s[i]!=s[k-1-i]){return false;}}return true;} template void chmax(T& a, T b) { if (a < b) a = b; } template void chmin(T& a, T b) { if (a > b) a = b; } // 余りが正になるような割り方 ll floor(ll x, ll m) { ll r = (x % m + m) % m; return (x - r) / m; } #define mod 998244353 using mint = modint998244353; int op(int a, int b) {return max(a, b);} int e() {return 0;} int mapping(int f, int x) {return (f == 1e9 ? x : f);} int composition(int f, int g) {return (f == 1e9 ? g : f);} int id() {return 1e9;} #define int ll signed main() { cin.tie(nullptr); cout << fixed << setprecision(10); ios::sync_with_stdio(false); int n, p, q; cin >> n >> q >> p; vector s(n); cin >> s; sort(all(s)); vector a(n, 1), b(n, 1), c(n, 1), d(n, 1); rep(i, 0, n) { vector ta(q, -1), tb(q, -1), tc(q, -1), td(q, -1); rep(j, 0, s[i]) { a[i] *= 10; a[i] %= q; if(ta[a[i]] == -1) ta[a[i]] = j; else { rep(k, 0, q) if((s[i]-ta[a[i]])%(j-ta[a[i]]) == ta[k]) { a[i] = k; break; } } } rep(j, 0, s[i]) { b[i] *= 9; b[i] %= q; if(tb[b[i]] == -1) tb[b[i]] = j; else { rep(k, 0, q) if((s[i]-tb[b[i]])%(j-tb[b[i]]) == tb[k]) { b[i] = k; break; } } } rep(j, 0, s[i]) { c[i] *= 7; c[i] %= q; if(tc[c[i]] == -1) tc[c[i]] = j; else { rep(k, 0, q) if((s[i]-tc[c[i]])%(j-tc[c[i]]) == tc[k]) { c[i] = k; break; } } } rep(j, 0, s[i]) { d[i] *= 5; d[i] %= q; if(td[d[i]] == -1) ta[d[i]] = j; else { rep(k, 0, q) if((s[i]-td[d[i]])%(j-td[d[i]]) == td[k]) { d[i] = k; break; } } } } cout << a << endl << b << endl << c << endl << d << endl; vector> l(n, vector(q, 0)), r(n, vector(q, 0)); rep(i, 0, n) rep(j, i+1, n) { l[j][(a[i]+b[j])%q]++; //if(j == 2) cout << "a:j" << a[i]+b[j] << endl; } rep(i, 0, n) rep(j, i+1, n) { rep(k, 0, i+1) { r[k][(c[i]+d[j])%q]++; } } //cout << a << endl << b << endl << c << endl << d << endl; ll ans = 0; rep(i, 0, n-1) { rep(j, 0, q) ans += r[i+1][(q+p-j)%q] * l[i][j]; } cout << ans << endl; }