#include<bits/stdc++.h>
#include <atcoder/all>
using namespace std;using namespace atcoder;using vst = vector<string>;using ll = long long;
using ld = long double;using pll = pair<ll,ll>;using vll = vector<ll>;using vvll = vector<vll>;
using vpll = vector<pll>;
#define rep(i, n) for (ll i = 0; i < n; i++)
#define repp(i,k,n) for (ll i = k; i < n; i++)
#define per(i,s,e) for(ll i = s; i >= e; i--)
#define all(v) v.begin(),v.end()
#define no() {cout << "No" << endl; return 0;}
#define yes(){cout << "Yes" << endl;return 0;}
#define yesno(a) a ? cout << "Yes" << endl : cout << "No" << endl
#define YESNO(a) a ? cout << "YES" << endl : cout << "NO" << endl
#define MODD 998244353LL
#define MOD 1000000007LL
#define UNOmap unordered_map
#define UNOset unordered_set
#define ASC(T) T,vector<T>,greater<T>
#define join(G,a,b) G[a].push_back(b);G[b].push_back(a);
#define PB(a,b) a.push_back(b)
template<class... T>void in(T&... a){(cin >> ... >> a);}
template<class T, class... Ts>void out(const T& a, const Ts&... b){cout << a;((cout << ' ' <<  b), ...);cout << '\n';}
void vin(vll &v){for(ll i = 0; i < (ll)v.size(); i++)in(v[i]);}
void vout(vll &v){for(ll i = 0; i < (ll)v.size(); i++) cout << v[i] << ' ';cout << "\n";}
ll INF = 1LL << 62;

// #include<boost/multiprecision/cpp_int.hpp>
// using namespace boost::multiprecision;

// using mint = modint998244353;
// using mint = modint1000000007;
// using mint = modint;


// cout << fixed << setprecision(15);
//----------------------------------------------



int main(){
  ll N,P,Q;
  in(N,P,Q);
  vll A(N);
  vin(A);
  ll ans = 0;
  
  vvll p(2e6+9,vll(4));
  ll p10,p9,p7,p5;
  p10 = 1;
  p9 = 1;
  p7 = 1;
  p5 = 1;
  rep(i,2e6+9){
    p[i][0] = p10%P;
    p[i][1] = p9%P;
    p[i][2] = p7%P;
    p[i][3] = p5%P;
    p10 *= 10;
    p9 *= 9;
    p7 *= 7;
    p5 *= 5;
  }
  
  rep(i,N){
    rep(j,i){
      rep(k,j){
        rep(l,k){
          ll d = A[i];
          ll c = A[j];
          ll b = A[k];
          ll a = A[l];
          ll cur = 0;
          cur += p[a][0];
          cur += p[b][1];
          cur += p[c][2];
          cur += p[d][3];
          cur %= P;
          if(cur == Q) ans++;
        }
      }
    }
  }
  out(ans);
}