#include <iostream>
#include <vector>
#include <string>

using namespace std;
using ll = long long;

int main () {
    int N, Q; cin >> N >> Q;
    string s; cin >> s;

    int D = 0, R = 0;
    for (auto c : s) {
        if (c == 'D') D++;
        if (c == 'R') R++;
    }

    if (D == 0) {
        for (int i = 0; i < Q; i++) {
            int H, W, P; cin >> H >> W >> P;
            cout << (P + W) % N << "\n";
        }
        return 0;
    }

    if (R == 0) {
        for (int i = 0; i < Q; i++) {
            int H, W, P; cin >> H >> W >> P;
            cout << (P + H) % N << "\n";
        }
        return 0;
    }

    // 両方向でダブリング -> 短い方を採用

    const int MAX = 32;
    vector<vector<ll>> dp_R(N + 1, vector<ll>(MAX)), dp_D(N + 1, vector<ll>(MAX));
    // dp_R[i][j] := カウンタiからスタートして、(カウンタiは踏む)右に2^jマス進んだ後にいるマス(modなし)

    {
        int l = 0, r = 0;
        while (l < N) {
            if (r < l) r = l;

            while (true) {
                if (s[r % N] == 'R') break;
                r++;
            }

            dp_R[l][0] = r + 1;
            l++;
        }
    }

    {
        int l = 0, r = 0;
        while (l < N) {
            if (r < l) r = l;

            while (true) {
                if (s[r % N] == 'D') break;
                r++;
            }

            dp_D[l][0] = r + 1;
            l++;
        }
    }

    for (int j = 0; j < MAX - 1; j++) {
        for (int i = 0; i < N; i++) {
            dp_R[i][j + 1] = dp_R[dp_R[i][j] % N][j] - (dp_R[i][j] % N) + dp_R[i][j];
            dp_D[i][j + 1] = dp_D[dp_D[i][j] % N][j] - (dp_D[i][j] % N) + dp_D[i][j];
        }
    }

    for (int i = 0; i < Q; i++) {
        int H, W, P; cin >> H >> W >> P;

        ll h = P;
        ll w = P;

        for (int j = 0; j < MAX; j++) {
            if (0 < (H & (1LL << j))) {
                h = dp_D[h % N][j];
            }
        }

        for (int j = 0; j < MAX; j++) {
            if (0 < (W & (1LL << j))) {
                w = dp_R[w % N][j];
            }
        }

        cout << min(h, w) % N << "\n";
    }
}