#include "bits/stdc++.h"

#include <stdio.h>
#include <math.h>

#include "atcoder/all"
#include <float.h>

//#include <boost/multiprecision/cpp_int.hpp>
//using namespace boost::multiprecision;

using namespace std;
using namespace atcoder;

#ifdef _MSVC_LANG
inline int getchar_unlocked() { return getchar(); }
#endif

using ll = long long;
using ull = unsigned long long;
using mint = modint998244353;
using mint2 = modint1000000007;
const double eps = 1e-9;

#define REP(i, n) for (ll i = 0; i < ll(n); ++i)
#define REPI(i, init, n) for (ll i = init; i < ll(n); ++i)
#define REPD(i, init) for (ll i = init; i >=0; --i)
#define REPDI(i, init, n) for (ll i = init; i >=n; --i)
#define REPE(i, c) for (const auto& i : c)
#define TCASE() ll _ttt; cin >> _ttt; while(_ttt--)

using vl = vector<ll>; using vvl = vector<vl>; using vvvl = vector<vvl>;
#define VLI(a, n) vector<ll> a; a.assign(n, 0); for(auto& x : a) cin >> x;
#define DLI(a, n) deque<ll> a; a.assign(n, 0); for(auto& x : a) cin >> x;
#define VSI(a, n) vector<string> a; a.assign(n, ""); for(auto& x : a) cin >> x;
#define VVLI(a, n, m, init) vector<vector<ll>> a(n); for(auto& x : a) x.assign(m, init);
using vd = vector<double>; using pl = pair<ll, ll>; using vpl = vector<pl>;

struct uv { ll u; ll v; ll c; };
#define VUVI(a, n) vector<uv> a; a.assign(n, {0, 0, 1}); for(auto& x : a) {cin >> x.u >> x.v; x.u--; x.v--;}
#define VUVCI(a, n) vector<uv> a; a.assign(n, {0, 0, 0}); for(auto& x : a) {cin >> x.u >> x.v >> x.c; x.u--; x.v--;}
vvl to_edge(const ll n, const vector<uv>& v) { vvl ret(n); for (auto& x : v) ret[x.u].push_back(x.v); return ret; }
vvl to_edge_d(const ll n, const vector<uv>& v) { vvl ret(n); for (auto& x : v) { ret[x.u].push_back(x.v); ret[x.v].push_back(x.u); } return ret; }

template <class T = long long> using pql = priority_queue<T>;
template <class T = long long> using pqg = priority_queue<T, vector<T>, greater<T>>;
using vm = vector<mint>; using vvm = vector<vm>;

ostream& operator<<(ostream& os, const mint& v) { os << v.val(); return os; }
void yn(bool f) { std::cout << (f ? "Yes" : "No") << endl; };
template<class T> void ov(const T& v) { for (auto it = v.begin(); it != v.end(); it++) { if (it != v.begin()) cout << " "; cout << *it; } };
template<> void ov(const vm& v) { for (auto it = v.begin(); it != v.end(); it++) { if (it != v.begin()) cout << " "; cout << it->val(); } };

const ll llhuge = 1LL << 62; //十分でかいが多少足しても溢れない数値
auto gmax(const auto& a, const auto& b) { return a > b ? a : b; };
auto gmin(const auto& a, const auto& b) { return a < b ? a : b; };
bool chmin(auto& a, const auto& b) { const auto olda = a; a = gmin(a, b); return olda != a; }
bool chmax(auto& a, const auto& b) { const auto olda = a; a = gmax(a, b); return olda != a; }
template<class T> void mysort(T& v) { std::sort(begin(v), end(v)); };
template<class T, class U> void mysort(T& v, U pr) { std::sort(begin(v), end(v), pr); };
template<class T> void myrev(T& v) { std::reverse(begin(v), end(v)); };
template<class T, class K = T::key_type, class V = T::mapped_type> [[nodiscard]] V myat(const T& mp, const K& key) { return mp.find(key) == mp.end() ? V() : mp.at(key); }
long long ceil(const long long a, const long long b) { return (a + b - 1) / b; }

//二分探索でf(t)を満たす整数tを返す
//ng < ok ならtは最小値 ng > ok ならtは最大値
template <class F>
ll bs(ll ng, ll ok, F f) {
	while (abs(ok - ng) > 1) {
		ll mid = (ok + ng) / 2;

		if (f(mid)) ok = mid;
		else ng = mid;
	}
	return ok;
}

int main() {
	cin.tie(nullptr);
	ios::sync_with_stdio(false);

	ll n, q;
	cin >> n >> q;
	string s;
	cin >> s;

	ll dc = 0;
	ll rc = 0;
	REP(i, n) {
		if (s[i] == 'D') dc++;
		else rc++;
	}

	string ss = s + s;
	vector<pl> sum(n * 2 + 1, { 0, 0 });
	REP(i, n * 2) {
		sum[i + 1].first = sum[i].first + (ss[i] == 'D' ? 1 : 0);
		sum[i + 1].second = sum[i].second + (ss[i] == 'R' ? 1 : 0);
	}

	REP(i, q) {
		ll ans = 0;
		ll h, w, p;
		cin >> h >> w >> p;
		if (h > dc && w > rc) {
			ll lpc = min(h / dc, w / rc);
			ans += lpc * n;
			h -= lpc * dc;
			w -= lpc * rc;
		}

		ans += bs(0, n, [&](ll x) {
			if (x < 0) return false;
			ll th = sum[x+p].first - sum[p].first;
			ll tw = sum[x+p].second - sum[p].second;
			return th >= h || tw >= w;
		});

		cout << (ans + p) % n << endl;
	}
}