// 入力フォーマットチェック #pragma GCC optimize ( "O3" ) // #pragma GCC target ( "avx" ) #include using namespace std; #define TYPE_OF( VAR ) remove_const::type >::type #define UNTIE ios_base::sync_with_stdio( false ); cin.tie( nullptr ) #define CEXPR( LL , BOUND , VALUE ) constexpr const LL BOUND = VALUE #define ASSERT( A , MIN , MAX ) assert( MIN <= A && A <= MAX ) #define GETLINE( A ) string A; getline( cin , A ) #define QUIT return 0 #define RETURN( ANSWER ) cout << ( ANSWER ) << "\n"; QUIT // 入力フォーマットチェック用 // 余分な改行を許さない // #define CHECK_REDUNDANT_INPUT string VARIABLE_FOR_CHECK_REDUNDANT_INPUT = ""; cin >> VARIABLE_FOR_CHECK_REDUNDANT_INPUT; assert( VARIABLE_FOR_CHECK_REDUNDANT_INPUT == "" ); assert( ! cin ); #define CHECK_REDUNDANT_INPUT string VARIABLE_FOR_CHECK_REDUNDANT_INPUT = ""; getline( cin , VARIABLE_FOR_CHECK_REDUNDANT_INPUT ); assert( VARIABLE_FOR_CHECK_REDUNDANT_INPUT == "" ); assert( ! cin ); // |N| <= BOUNDを満たすNをSから構築 #define STOI( S , N , BOUND ) TYPE_OF( BOUND ) N = 0; { bool VARIABLE_FOR_POSITIVITY_FOR_STOI = true; assert( S != "" ); if( S.substr( 0 , 1 ) == "-" ){ VARIABLE_FOR_POSITIVITY_FOR_STOI = false; S = S.substr( 1 ); assert( S != "" ); } assert( S.substr( 0 , 1 ) != " " ); while( S == "" ? false : S.substr( 0 , 1 ) != " " ){ assert( N < BOUND / 10 ? true : N == BOUND / 10 && stoi( S.substr( 0 , 1 ) ) <= BOUND % 10 ); N = N * 10 + stoi( S.substr( 0 , 1 ) ); S = S.substr( 1 ); } if( ! VARIABLE_FOR_POSITIVITY_FOR_STOI ){ N *= -1; } if( S != "" ){ S = S.substr( 1 ); } } // 1行で入力される変数の個数が適切か確認(半角空白の個数+1を調べる) #define COUNT_VARIABLE( S , VARIABLE_NUMBER ) { int size = S.size(); int count = 0; for( int i = 0 ; i < size ; i++ ){ if( S.substr( i , 1 ) == " " ){ count++; } } assert( count + 1 == VARIABLE_NUMBER ); } int main() { UNTIE; CEXPR( int , bound , 1000 ); GETLINE( S ); CHECK_REDUNDANT_INPUT; COUNT_VARIABLE( S , 5 ); STOI( S , A , bound ); STOI( S , B , bound ); STOI( S , C , bound ); STOI( S , D , bound ); STOI( S , E , bound ); assert( 1 <= A && 1 <= B && 1 <= C && 1 <= D && 1 <= E ); RETURN( D > E ? A - B + C * ( D - E ) : A - B ); }