#include<bits/stdc++.h>
#include<atcoder/all>
#define rep(i,n) for(int i=0;i<n;i++)
using namespace std;
using namespace atcoder;
typedef long long ll;
typedef vector<int> vi;
typedef vector<long long> vl;
typedef vector<vector<int>> vvi;
typedef vector<vector<long long>> vvl;
typedef long double ld;
typedef pair<int, int> P;

ostream& operator<<(ostream& os, const modint& a) {os << a.val(); return os;}
template <int m> ostream& operator<<(ostream& os, const static_modint<m>& a) {os << a.val(); return os;}
template <int m> ostream& operator<<(ostream& os, const dynamic_modint<m>& a) {os << a.val(); return os;}
template<typename T> istream& operator>>(istream& is, vector<T>& v){int n = v.size(); assert(n > 0); rep(i, n) is >> v[i]; return is;}
template<typename U, typename T> ostream& operator<<(ostream& os, const pair<U, T>& p){os << p.first << ' ' << p.second; return os;}
template<typename T> ostream& operator<<(ostream& os, const vector<T>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : " "); return os;}
template<typename T> ostream& operator<<(ostream& os, const vector<vector<T>>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : ""); return os;}

template<typename T> void chmin(T& a, T b){a = min(a, b);}
template<typename T> void chmax(T& a, T b){a = max(a, b);}

using mint = modint998244353;

void solve(string s){
	int n = s.size();
	if(n % 2 == 1){
		string t;
		rep(i, n - 1) t += '9';
		solve(t);
		return;
	}
	vector<mint> equal(1 << 10);
	vector<mint> small(1 << 10);
	equal[0] = 1;
	rep(i, n){
		vector<mint> equal_old(1 << 10);
		vector<mint> small_old(1 << 10);
		swap(equal, equal_old);
		swap(small, small_old);
		int num = s[i] - '0';
		rep(bit, 1 << 10){
			for(int x = 0; x < num; x++) small[bit ^ (1 << x)] += equal_old[bit];
			equal[bit ^ (1 << num)] += equal_old[bit];
			if(bit == 1 && i % 2 == 1){
				small[bit ^ (1 << 0)] += small_old[bit];
				for(int x = 1; x <= 9; x++) small[bit ^ (1 << x)] += (small_old[bit] - 1);
			}else{
				for(int x = 0; x <= 9; x++) small[bit ^ (1 << x)] += small_old[bit];
			}
		}
	}
	cout << (equal[0] + small[0] - 1).val() << "\n";
}

int main(){
	string s;
	cin >> s;
	solve(s);
	return 0;
}