q=int(input())
s=set([2])
def f(n):
    for i in s:
        if n%i==0:
            return 
    s.add(n)
i=3
p=10**5+1
while i<=p:
    f(i)
    i+=2
for i in range(q):
    a=int(input())
    k=0
    while a!=1:
        if a in s:
            k+=1
            break
        for j in s:
            if a%j==0:
                k+=1
                a//=j
                break
        if k>3:
            break
    if k==3:
        print("Yes")
    else:
        print("No")