q=int(input())
s=set([2])
def f(n):
    for i in s:
        if n%i==0:
            return 
    s.add(n)
    return True
i=3
p=10**5+2
while i<=p:
    f(i)
    i+=2

for i in range(q):
    a=int(input())
    k=0
    while a!=1:
        if a in s:
            k+=1
            break
        t=True
        for j in s:
            if a%j==0:
                k+=1
                a//=j
                t=False
            if k>3:
                break
        if k>3:
            break
        if t:
            a=1
            k+=1
    if k==3:
        print("Yes")
    else:
        print("No")