#include<bits/stdc++.h>
#define pt printf(">>>")
#define mid (((l)+(r))/2)
using namespace std;
typedef long long ll;
typedef long double ld;
const ll N=1e6+10,inf=1e18+10,mod=1e9+7;
ll n,k,x[N];
int main(){
	cin >> n >> k;
	ll now=-inf,ans=0;
	for(ll i=1;i<=n;i++){
		cin >> x[i];
		if(x[i]-now>=k)ans++,now=x[i];
	}
	cout << ans;
	return 0;
}