#include #include using namespace std; using namespace atcoder; istream &operator>>(istream &is, modint &a) { long long v; is >> v; a = v; return is; } ostream &operator<<(ostream &os, const modint &a) { return os << a.val(); } istream &operator>>(istream &is, modint998244353 &a) { long long v; is >> v; a = v; return is; } ostream &operator<<(ostream &os, const modint998244353 &a) { return os << a.val(); } istream &operator>>(istream &is, modint1000000007 &a) { long long v; is >> v; a = v; return is; } ostream &operator<<(ostream &os, const modint1000000007 &a) { return os << a.val(); } typedef long long ll; typedef vector> Graph; typedef pair pii; typedef pair pll; #define FOR(i,l,r) for (int i = l;i < (int)(r); i++) #define rep(i,n) for (int i = 0;i < (int)(n); i++) #define all(x) x.begin(), x.end() #define rall(x) x.rbegin(), x.rend() #define my_sort(x) sort(x.begin(), x.end()) #define my_max(x) *max_element(all(x)) #define my_min(x) *min_element(all(x)) template inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; } template inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; } const int INF = (1<<30) - 1; const ll LINF = (1LL<<60) - 1; const int MOD = 998244353; const int MOD2 = 1e9+7; const double PI = acos(-1); vector di = {1,0,-1,0}; vector dj = {0,1,0,-1}; #ifdef LOCAL # include # define debug(...) debug_print::multi_print(#__VA_ARGS__, __VA_ARGS__) #else # define debug(...) (static_cast(0)) #endif int main(){ cin.tie(0); ios_base::sync_with_stdio(false); ll N; cin >> N; map mp; mp[1] = 0; queue Q; Q.push(1); while(!Q.empty()){ ll x = Q.front(); Q.pop(); if(2 * x + 1 <= N && mp.find(2 * x + 1) == mp.end()){ mp[2 * x + 1] = x; Q.push(2 * x + 1); } if(3 * x + 1 <= N && mp.find(3 * x + 1) == mp.end()){ mp[3 * x + 1] = x; Q.push(3 * x + 1); } } if(mp.find(N) == mp.end()){ cout << endl; } else{ vector ans; ll now = N; while(now != 1){ if((now - 1) % 2 == 0 && mp[now] == (now - 1) / 2){ ans.push_back('A'); now = (now - 1) / 2; } else if((now - 1) % 3 == 0 && mp[now] == (now - 1) / 3){ ans.push_back('B'); now = (now - 1) / 3; } else { cout << endl; return 0; } } reverse(all(ans)); rep(i, (int)ans.size()) cout << ans[i]; cout << endl; } }