#include #define rep(i,a,b) for(int i=(a);i<=(b);++i) #define per(i,a,b) for(int i=(a);i>=(b);--i) #define pii pair #define vi vector #define fi first #define se second #define pb push_back #define ALL(x) x.begin(),x.end() #define sz(x) int(x.size()) #define ll long long using namespace std; const int N = 2e5 + 5; const ll inf = 1e14; int n; vector X,Y; template bool chmin(T &t, const T &f) { if (t > f) { t = f; return true; } return false; } template bool chmax(T &t, const T &f) { if (t < f) { t = f; return true; } return false; } bool solve(ll A,int k,const vi &p){ if(!p.size())return 1; if(k == 0)return 0; ll xs[2] = {-inf,inf},ys[2] = {-inf,inf}; for(int i : p){//the min/max of the upper right corner of the square chmax(xs[0],X[i]),chmax(ys[0],Y[i]); chmin(xs[1],X[i] + A),chmin(ys[1],Y[i] + A); } if(k == 1){ return (xs[0] <= xs[1] && ys[0] <= ys[1]); } rep(a,0,1)rep(b,0,1){ vi nxt; //we cover one corner with the square for(int i : p){ if(xs[a] >= X[i] && X[i] >= xs[a] - A && ys[b] >= Y[i] && Y[i] >= ys[b] - A); else nxt.pb(i); } if(solve(A,k - 1,nxt))return 1; } return 0; } bool chk(ll A){ vi p(n); rep(i,0,n - 1)p[i] = i; return solve(A,3,p); } int main(){ cin.tie(0)->sync_with_stdio(0); cin >> n; X.resize(n),Y.resize(n); rep(i,0,n - 1){ int a,b; cin >> a >> b; //Manhattan distance to Chebyshev X[i] = a + b,Y[i] = a - b; } int L = 0,R = 2e9; while(L < R){ int mid = (L + R) / 2; if(chk(mid))R = mid; else L = mid + 1; } cout << L << endl; return 0; }