#include using namespace std; typedef signed long long ll; #define _P(...) (void)printf(__VA_ARGS__) #define FOR(x,to) for(x=0;x<(to);x++) #define FORR(x,arr) for(auto& x:arr) #define FORR2(x,y,arr) for(auto& [x,y]:arr) #define ALL(a) (a.begin()),(a.end()) #define ZERO(a) memset(a,0,sizeof(a)) #define MINUS(a) memset(a,0xff,sizeof(a)) template bool chmax(T &a, const T &b) { if(a bool chmin(T &a, const T &b) { if(a>b){a=b;return 1;}return 0;} //------------------------------------------------------- ll O[5][34]; ll X[5][34]; ll dp[9][9][34]; const ll mo=998244353; const int NUM_=400001; static ll fact[NUM_+1],factr[NUM_+1],inv[NUM_+1]; ll modpow(ll a, ll n=mo-2) { ll r=1; while(n) r=r*((n%2)?a:1)%mo,a=a*a%mo,n>>=1; return r; } ll comb(ll P_,ll Q_) { if(P_<0 || Q_<0 || Q_>P_) return 0; ll p=1,q=1; Q_=min(Q_,P_-Q_); P_%=mo; for(int i=1;i<=Q_;i++) p=p*P_%mo, q=q*i%mo,P_--; return p*modpow(q,mo-2)%mo; } void solve() { int i,j,k,l,r,x,y; string s; FOR(y,5) FOR(x,34) cin>>O[y][x]; FOR(y,5) FOR(x,34) cin>>X[y][x]; dp[0][0][0]=1; FOR(y,5) FOR(x,34) { for(i=7;i>=0;i--) for(j=1;i+j<=8;j++) { for(int a=0;a+y*j<=4;a++) for(int b=0;b+x*j<=33;b++) { (dp[i+j][a+y*j][b+x*j]+=dp[i][a][b]*comb(O[y][x],j))%=mo; } } } ll ret=0; FOR(y,5) (ret+=dp[8][y][33]*(X[4-y][0]%mo))%=mo; cout<