#include #include #include #include #include #include #include #include #include #include #include #include #include #include using namespace std; using ll = long long; auto range(int n) { return views::iota(0, n); } template ostream& operator<<(ostream& os, const pair& p){ return os << "{" << p.first << ", " << p.second << "}"; } template ostream& operator<<(ostream& os, const vector& obj) { os << "{"; for (const auto& e : obj) os << e << ", "; return os << "}"; } template ostream& operator<<(ostream& os, const set& obj) { os << "set{"; for (const auto& e : obj) os << e << ", "; return os << "}"; } template ostream& operator<<(ostream& os, const map& obj) { os << "map{"; for (const auto& e : obj) os << e << ", "; return os << "}"; } #ifdef ONLINE_JUDGE #define dump(expr) ; #else #define dump(expr) { cerr << "\033[33m#L" << __LINE__ << ": " << expr << "\033[39m" << endl; } #endif const int mod = 1000000007; struct mint { ll x; mint(ll x_ = 0) : x((x_ % mod + mod) % mod) {} mint operator-() const { return mint(-x); } mint &operator+=(const mint &a) { if ((x += a.x) >= mod) x -= mod; return *this; } mint &operator-=(const mint &a) { if ((x += mod - a.x) >= mod) x -= mod; return *this; } mint &operator*=(const mint &a) { (x *= a.x) %= mod; return *this; } mint operator+(const mint &a) const { mint res(*this); return res += a; } mint operator-(const mint &a) const { mint res(*this); return res -= a; } mint operator*(const mint &a) const { mint res(*this); return res *= a; } mint pow(ll t) const { if (!t) return 1; mint a = pow(t >> 1); a *= a; if (t & 1) a *= *this; return a; } mint inv() const { return pow(mod - 2); } mint &operator/=(const mint &a) { return (*this) *= a.inv(); } mint operator/(const mint &a) const { mint res(*this); return res /= a; } friend ostream &operator<<(ostream &os, const mint &m) { os << m.x; return os; } friend istream &operator>>(istream &is, mint &m) { is >> m.x; return is; } }; // code is from noya2 // sum[ i in [0,n) ] floor( (a * i + b) / m ) template T floor_sum(T n, T m, T a, T b){ if (n <= 0) return 0; T ans = 0; while (true){ T da = a / m; ans += (n >> 1) * ((n - 1) | 1) * da; a -= da * m; T db = b / m; ans += n * db; b -= db * m; T y_max = a * n + b; if (y_max < m) break; T dy_max = y_max / m; n = dy_max; b = y_max - dy_max * m; swap(m, a); } return ans; } ll solve() { int n, m; cin >> n >> m; vector as(n), bs(m); for (int i : range(n)) cin >> as[i]; for (int i : range(m)) cin >> bs[i]; mint res = 0; map, mint> memo; for (ll a : as) for (ll b : bs) { if (!memo.count({a, b})) { memo[{a, b}] = floor_sum(b + 1, b, a, 0LL); } res += mint(2) * memo[{a, b}]; /* for (int k = 1; k <= b; ++k) { res += mint(2) * ((ll)a * k / b); } */ } return res.x; } int main() { cout << fixed << setprecision(12); cout << solve() << endl; }