#include #include #include #include #include #include #include #include #include #include #include #include #include #include #include using namespace std; using ll = long long; class range {private: struct I{int x;int operator*(){return x;}bool operator!=(I& lhs){return x ostream& operator<<(ostream& os, const pair& p){ return os << "{" << p.first << ", " << p.second << "}"; } template ostream& operator<<(ostream& os, const vector& obj) { os << "{"; for (const auto& e : obj) os << e << ", "; return os << "}"; } template ostream& operator<<(ostream& os, const set& obj) { os << "set{"; for (const auto& e : obj) os << e << ", "; return os << "}"; } template ostream& operator<<(ostream& os, const map& obj) { os << "map{"; for (const auto& e : obj) os << e << ", "; return os << "}"; } template void take(vector& vec, int n) { vec.resize(n); for (int i = 0; i < n; ++i) cin >> vec[i]; } #ifdef ONLINE_JUDGE #define dump(expr) ; #else #define dump(expr) { cerr << "\033[33m#L" << __LINE__ << ": " << expr << "\033[39m" << endl; } #endif const ll mod = 998244353; struct mint { ll x; mint(ll x_ = 0) : x((x_ % mod + mod) % mod) {} mint operator-() const { return mint(-x); } mint &operator+=(const mint &a) { if ((x += a.x) >= mod) x -= mod; return *this; } mint &operator-=(const mint &a) { if ((x += mod - a.x) >= mod) x -= mod; return *this; } mint &operator*=(const mint &a) { (x *= a.x) %= mod; return *this; } mint operator+(const mint &a) const { mint res(*this); return res += a; } mint operator-(const mint &a) const { mint res(*this); return res -= a; } mint operator*(const mint &a) const { mint res(*this); return res *= a; } mint pow(ll t) const { if (!t) return 1; mint a = pow(t >> 1); a *= a; if (t & 1) a *= *this; return a; } mint inv() const { return pow(mod - 2); } mint &operator/=(const mint &a) { return (*this) *= a.inv(); } mint operator/(const mint &a) const { mint res(*this); return res /= a; } friend ostream &operator<<(ostream &os, const mint &m) { os << m.x; return os; } friend istream &operator>>(istream &is, mint &m) { is >> m.x; return is; } }; // point update, range query segment tree // based on https://maspypy.com/segment-tree-%e3%81%ae%e3%81%8a%e5%8b%89%e5%bc%b71 template struct SegmentTree { // array (xs[0], ..., xs[n - 1]) int n; vector xs; function fun; // fold function (x @ y) T unit; // (unit @ x) = (x @ unit) = x for all x SegmentTree(int n_, function fun_, T unit_) : n(n_), xs(2 * n, unit_), fun(fun_), unit(unit_) {} void build(vector seq) { assert((int)seq.size() == n); for (int i : range(n)) xs[n + i] = seq[i]; for (int i = n - 1; i >= 1; --i) xs[i] = fun(xs[i << 1], xs[(i << 1) | 1]); } void setval(int i, T x) { // xs[i] := x i += n; xs[i] = x; while (i > 1) { i >>= 1; xs[i] = xs[i] = fun(xs[i << 1], xs[(i << 1) | 1]); } } T fold(int l, int r) { // xs[l] @ xs[l + 1] @ ... @ xs[r - 1] l += n; r += n; T vl = unit; T vr = unit; while (l < r) { if (l & 1) { vl = fun(vl, xs[l]); l++; } if (r & 1) { r--; vr = fun(xs[r], vr); } l >>= 1; r >>= 1; } return fun(vl, vr); } }; template SegmentTree sum_segment_tree_factory(int n) { auto fun = [](T a, T b) -> T { return a + b;}; return SegmentTree(n, fun, 0); } namespace solver { int n; vector vs; void read() { cin >> n; take(vs, n); } using RetType = mint; RetType run() { vector> vp(n); for (int i : range(n)) vp[i] = {vs[i], i}; ranges::sort(vp); vector sum1(n), count1(n); { auto seg_sum = sum_segment_tree_factory(n), seg_count = sum_segment_tree_factory(n); for (int i = n - 1; i >= 0; --i) { auto p = vp[i]; sum1[p.second] = seg_sum.fold(0, p.second); count1[p.second] = seg_count.fold(0, p.second); seg_sum.setval(p.second, p.first); seg_count.setval(p.second, 1); } } dump(sum1) dump(count1) vector sum2(n), count2(n); { auto seg_sum = sum_segment_tree_factory(n), seg_count = sum_segment_tree_factory(n); for (int i : range(n)) { auto p = vp[i]; sum2[p.second] = seg_sum.fold(p.second, n); count2[p.second] = seg_count.fold(p.second, n); seg_sum.setval(p.second, p.first); seg_count.setval(p.second, 1); } } mint res = 0; for (int j : range(n)) { mint add = sum1[j] * count2[j] + sum2[j] * count1[j] + mint(vs[j]) * count1[j] * count2[j]; res += add; } return res; } } // namespace template void run(F f) { if constexpr (std::is_same_v) f(); else cout << f() << endl; } int main(int argc, char** argv) { cerr << fixed << setprecision(12); cout << fixed << setprecision(12); int testcase = 1; if (argc > 1) testcase = atoi(argv[1]); while (testcase--) { solver::read(); } run(solver::run); }