#include <bits/stdc++.h>
using namespace std;
using ll = long long;
using ld = long double;
using ull = unsigned long long;
using uint = unsigned;
using pii = pair<int, int>;
using pll = pair<ll, ll>;
template<class T> using pq = priority_queue<T, vector<T>, greater<T>>;
const ll LINF=0x1fffffffffffffff;
const ll MINF=0x7fffffffffff;
const int INF=0x3fffffff;
const int MOD=1000000007;
const int MOD2=998244353;
const ld EPS=1e-9;
const ld PI=3.14159265358979323846;
const ll dx[] = {0, 1, 0, -1, 1, -1, 1, -1};
const ll dy[] = {1, 0, -1, 0, 1, 1, -1, -1};
#define all(x) (x).begin(), (x).end()
#define pb push_back
#define eb emplace_back
#define mp make_pair
#define fi first
#define se second
#define rep(i, n) rep2(i, 0, n)
#define rep2(i, m, n) for (int i = m; i < (n); i++)
#define per(i, b) per2(i, 0, b)
#define per2(i, a, b) for (int i = int(b) - 1; i >= int(a); i--)
#define ALL(c) (c).begin(), (c).end()
#define SZ(x) ((int)(x).size())
#define nep(x) next_permutation(ALL(x))
template <class T>
using V = vector<T>;
template <class T>
using VV = V<V<T>>;
template <class T>
using VVV = V<VV<T>>;
template <class T>
using VVVV = V<VVV<T>>;
template <class T>
using V_p = V<pair<T,T>>;
template <class T>
using n_pq = priority_queue<T>;
template <class T>
using r_pq = priority_queue<T,vector<T>,greater<T>>;
template <class T>ostream &operator<<(ostream &o,const vector<T>&v)
{o<<"{";for(int i=0;i<(int)v.size();i++)o<<(i>0?", ":"")<<v[i];o<<"}";return o;}
template <class T>ostream &operator<<(ostream &o,const deque<T>&v)
{o<<"{";for(int i=0;i<(int)v.size();i++)o<<(i>0?", ":"")<<v[i];o<<"}";return o;}
template <class T>ostream &operator<<(ostream &o,const set<T>&v)
{o<<"{";for(auto i:v)o<<" "<<i;o<<"}";return o;}

ll pow_ll(ll x, ll n) {
    long long ret = 1;
    while (n > 0) {
        if (n & 1) ret *= x;  // n の最下位bitが 1 ならば x^(2^i) をかける
        x *= x;
        n >>= 1;  // n を1bit 左にずらす
    }
    return ret;
}
ll prime_factorize(long long N) {
    // 答えを表す可変長配列
    vector<pair<long long, long long> > res;
    ll ret = 1;

    // √N まで試し割っていく
    for (long long p = 2; p * p <= N; ++p) {
        // N が p で割り切れないならばスキップ
        if (N % p != 0) {
            continue;
        }

        // N の素因数 p に対する指数を求める
        int e = 0;
        while (N % p == 0) {
            // 指数を 1 増やす
            ++e;

            // N を p で割る
            N /= p;
        }
        ll tmp = 1;
        rep(i,e+1) {
            tmp *= p;
        }
        ret *= (tmp-1) / (p-1);
    }

    // 素数が最後に残ることがありうる
    if (N != 1) {
        ret *= (N+1);
    }
    return ret;
}

int main() {
    ll N;
    cin >> N;
    const ll ans = prime_factorize(N);
    if (ans == 2*N) {
        cout << "Yes" << endl;
    }
    else { 
        cout << "No" << endl;
    }

}