#include #include using namespace std; using namespace atcoder; istream &operator>>(istream &is, modint &a) { long long v; is >> v; a = v; return is; } ostream &operator<<(ostream &os, const modint &a) { return os << a.val(); } istream &operator>>(istream &is, modint998244353 &a) { long long v; is >> v; a = v; return is; } ostream &operator<<(ostream &os, const modint998244353 &a) { return os << a.val(); } istream &operator>>(istream &is, modint1000000007 &a) { long long v; is >> v; a = v; return is; } ostream &operator<<(ostream &os, const modint1000000007 &a) { return os << a.val(); } typedef long long ll; typedef vector> Graph; typedef pair pii; typedef pair pll; #define FOR(i,l,r) for (int i = l;i < (int)(r); i++) #define rep(i,n) for (int i = 0;i < (int)(n); i++) #define all(x) x.begin(), x.end() #define rall(x) x.rbegin(), x.rend() #define my_sort(x) sort(x.begin(), x.end()) #define my_max(x) *max_element(all(x)) #define my_min(x) *min_element(all(x)) template inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; } template inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; } const int INF = (1<<30) - 1; const ll LINF = (1LL<<62) - 1; const int MOD = 998244353; const int MOD2 = 1e9+7; const double PI = acos(-1); vector di = {1,0,-1,0}; vector dj = {0,1,0,-1}; #ifdef LOCAL # include # define debug(...) debug_print::multi_print(#__VA_ARGS__, __VA_ARGS__) #else # define debug(...) (static_cast(0)) #endif using mint = modint998244353; int main(){ cin.tie(0); ios_base::sync_with_stdio(false); int N, M, k; cin >> N >> M >> k; vector dp(M * N); dp[0] = 1; rep(i, M * N)FOR(j, 1, 7) if(i + j < (M * N)) dp[i + j] += dp[i]; debug(dp); vector ep(6, vector(N * M + 6)); rep(k, 6){ ep[k][N * M + k] = 1; for(int v = N * M + k; v >= 0; v--){ for(int j = 1; j <= 6; j++){ if(v - j >= 0 && v - j < N * M) ep[k][v - j] += ep[k][v]; } } } rep(i, k){ int C; cin >> C; mint ans = 0, acc = 0; acc = 0; rep(k, 6) acc += ep[k][C]; debug(dp[C], acc); ans += acc * dp[C]; acc = 0; rep(k, 6) acc += ep[k][C + N]; debug(dp[C + N], acc); ans += acc * dp[C + N]; acc = 0; rep(k, 6) acc += ep[k][C + N]; debug(dp[C], dp[N], acc); ans -= acc * dp[C] * dp[N]; cout << ans << endl; } }