#include #include #include #include using namespace std; struct cell { int x, y; }; int main() { // step #1. input int N, M, K; cin >> N >> M >> K; vector > A(N, vector(M)); for (int i = 0; i < N; i++) { for (int j = 0; j < M; j++) { cin >> A[i][j]; } } // step #2. compression vector cand(N * M + 1); for (int i = 0; i < N; i++) { for (int j = 0; j < M; j++) { cand[i * M + j] = A[i][j]; } } cand[N * M] = 1'000'000'000; sort(cand.begin(), cand.end()); // step #3. bfs auto bfs = [&](int b) -> int { const int INF = 1012345678; const vector dir = {cell{1, 0}, cell{0, 1}, cell{-1, 0}, cell{0, -1}}; vector > d(N, vector(M, INF)); d[0][0] = (A[0][0] < b ? 1 : 0); deque que; que.push_back(cell{0, 0}); while (!que.empty()) { cell c = que.front(); que.pop_front(); for (int i = 0; i < 4; i++) { cell nc = cell{c.x + dir[i].x, c.y + dir[i].y}; if (0 <= nc.x && nc.x < N && 0 <= nc.y && nc.y < M) { int f = (A[nc.x][nc.y] < b ? 1 : 0); int nd = d[c.x][c.y] + f; if (d[nc.x][nc.y] > nd) { d[nc.x][nc.y] = nd; if (f == 1) { que.push_back(nc); } else { que.push_front(nc); } } } } } return d[N - 1][M - 1]; }; // step #3. binary search int l = 0, r = N * M + 1; while (r - l > 1) { int m = (l + r) / 2; int res = bfs(cand[m]); if (res <= K) { l = m; } else { r = m; } } // step #4. output cout << cand[l] << endl; return 0; }