def list3(a, b, c, *, val=0):
    return [[[val] * c for _ in range(b)] for _ in range(a)]


N, D, K = map(int, input().split())

dp = list3(N+1, K+1, D+1, val=False)
# dp[i][j][k]
# i : i 番目まで見た
# j : j 個のおかしを選んだ
# k : k 円かかった

dp[0][0][0] = True
a = list(reversed(range(1, N+1)))  # お菓子の値段(辞書順に取るので逆順)
for i in range(N):
    for j in range(K+1):  # j 個買った
        for k in range(D+1):  # k 円使った
            dp[i+1][j][k] |= dp[i][j][k]

            if not dp[i][j][k]: continue
            if j == K: continue
            nk = k + a[i]
            if nk > D: continue
            dp[i+1][j+1][nk] = True

if not dp[N][K][D]:
    print(-1)
    exit()

# DP復元
ans = []
cnt = K
yen = D
for i in reversed(range(1, N+1)):
    if dp[i][cnt][yen]:
        y = a[i-1]
        if yen-y >= 0 and dp[i-1][cnt-1][yen-y]:
            ans.append(N-i+1)
            cnt -= 1
            yen -= y

assert cnt == 0 and yen == 0
print(*ans)