結果

問題 No.663 セルオートマトンの逆操作
ユーザー ningenMeningenMe
提出日時 2020-05-01 01:03:08
言語 C++17
(gcc 12.3.0 + boost 1.83.0)
結果
AC  
実行時間 4 ms / 2,000 ms
コード長 3,546 bytes
コンパイル時間 2,458 ms
コンパイル使用メモリ 208,408 KB
実行使用メモリ 6,944 KB
最終ジャッジ日時 2024-06-01 05:07:22
合計ジャッジ時間 3,389 ms
ジャッジサーバーID
(参考情報)
judge4 / judge2
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 2 ms
6,812 KB
testcase_01 AC 2 ms
6,944 KB
testcase_02 AC 2 ms
6,940 KB
testcase_03 AC 2 ms
6,944 KB
testcase_04 AC 2 ms
6,944 KB
testcase_05 AC 2 ms
6,944 KB
testcase_06 AC 2 ms
6,940 KB
testcase_07 AC 2 ms
6,940 KB
testcase_08 AC 2 ms
6,940 KB
testcase_09 AC 2 ms
6,940 KB
testcase_10 AC 2 ms
6,940 KB
testcase_11 AC 2 ms
6,944 KB
testcase_12 AC 2 ms
6,944 KB
testcase_13 AC 2 ms
6,940 KB
testcase_14 AC 2 ms
6,940 KB
testcase_15 AC 2 ms
6,944 KB
testcase_16 AC 2 ms
6,944 KB
testcase_17 AC 2 ms
6,940 KB
testcase_18 AC 2 ms
6,940 KB
testcase_19 AC 2 ms
6,944 KB
testcase_20 AC 2 ms
6,940 KB
testcase_21 AC 2 ms
6,944 KB
testcase_22 AC 3 ms
6,944 KB
testcase_23 AC 3 ms
6,944 KB
testcase_24 AC 4 ms
6,940 KB
testcase_25 AC 4 ms
6,940 KB
testcase_26 AC 4 ms
6,940 KB
testcase_27 AC 2 ms
6,944 KB
testcase_28 AC 2 ms
6,944 KB
権限があれば一括ダウンロードができます

ソースコード

diff #

#include <bits/stdc++.h>
using namespace std;
using ll = long long;

#define ALL(obj) (obj).begin(),(obj).end()
#define SPEED cin.tie(0);ios::sync_with_stdio(false);

template<class T> using PQ = priority_queue<T>;
template<class T> using PQR = priority_queue<T,vector<T>,greater<T>>;

constexpr long long MOD = (long long)1e9 + 7;
constexpr long long MOD2 = 998244353;
constexpr long long HIGHINF = (long long)1e18;
constexpr long long LOWINF = (long long)1e15;
constexpr long double PI = 3.1415926535897932384626433L;

template <class T> vector<T> multivector(size_t N,T init){return vector<T>(N,init);}
template <class... T> auto multivector(size_t N,T... t){return vector<decltype(multivector(t...))>(N,multivector(t...));}
template <class T> void corner(bool flg, T hoge) {if (flg) {cout << hoge << endl; exit(0);}}
template <class T, class U>ostream &operator<<(ostream &o, const map<T, U>&obj) {o << "{"; for (auto &x : obj) o << " {" << x.first << " : " << x.second << "}" << ","; o << " }"; return o;}
template <class T>ostream &operator<<(ostream &o, const set<T>&obj) {o << "{"; for (auto itr = obj.begin(); itr != obj.end(); ++itr) o << (itr != obj.begin() ? ", " : "") << *itr; o << "}"; return o;}
template <class T>ostream &operator<<(ostream &o, const multiset<T>&obj) {o << "{"; for (auto itr = obj.begin(); itr != obj.end(); ++itr) o << (itr != obj.begin() ? ", " : "") << *itr; o << "}"; return o;}
template <class T>ostream &operator<<(ostream &o, const vector<T>&obj) {o << "{"; for (int i = 0; i < (int)obj.size(); ++i)o << (i > 0 ? ", " : "") << obj[i]; o << "}"; return o;}
template <class T, class U>ostream &operator<<(ostream &o, const pair<T, U>&obj) {o << "{" << obj.first << ", " << obj.second << "}"; return o;}
template <template <class tmp>  class T, class U> ostream &operator<<(ostream &o, const T<U> &obj) {o << "{"; for (auto itr = obj.begin(); itr != obj.end(); ++itr)o << (itr != obj.begin() ? ", " : "") << *itr; o << "}"; return o;}
void print(void) {cout << endl;}
template <class Head> void print(Head&& head) {cout << head;print();}
template <class Head, class... Tail> void print(Head&& head, Tail&&... tail) {cout << head << " ";print(forward<Tail>(tail)...);}
template <class T> void chmax(T& a, const T b){a=max(a,b);}
template <class T> void chmin(T& a, const T b){a=min(a,b);}
void YN(bool flg) {cout << (flg ? "YES" : "NO") << endl;}
void Yn(bool flg) {cout << (flg ? "Yes" : "No") << endl;}
void yn(bool flg) {cout << (flg ? "yes" : "no") << endl;}

int main() {
    int N; cin >> N;
    vector<int> A(N);
    for(int i = 0; i < N; ++i) {
        cin >> A[i];
    }
    vector<int> B(8);
    B[0]=B[4]=B[7]=0;
    B[1]=B[2]=B[3]=B[5]=B[6]=1;
    ll ans = 0;
    for(int n = 0; n < (1<<3); ++n){
        auto dp = multivector(N,8,0LL);
        dp[0][n] = (B[n]==A[0]);
        for(int i = 0; i+1 < N; ++i) {
            for(int j = 0; j < (1<<3); ++j) {
                if(A[i]!=B[j]) continue;
                for(int k = 0; k < (1<<3); ++k) {
                    if(A[i+1]!=B[k]) continue;
                    if( ((j>>1)&1) != ((k>>2)&1) ) continue;
                    if( ((j>>0)&1) != ((k>>1)&1) ) continue;
                    (dp[i+1][k] += dp[i][j]) %= MOD; 
                }
            }
        }
        {
            for(int j = 0; j < (1<<3); ++j) {
                if( ((j>>1)&1) != ((n>>2)&1) ) continue;
                if( ((j>>0)&1) != ((n>>1)&1) ) continue;
                (ans += dp[N-1][j]) %= MOD;
            }
        }
    }
    cout << ans << endl;
    return 0;
}
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