結果

問題 No.2559 眩しい数直線
ユーザー マベマス（mavemas_413）マベマス（mavemas_413）
提出日時 2023-11-26 14:50:34
言語 C++14
(gcc 12.3.0 + boost 1.83.0)
結果
AC  
実行時間 3 ms / 2,000 ms
コード長 3,179 bytes
コンパイル時間 3,661 ms
コンパイル使用メモリ 230,128 KB
実行使用メモリ 6,676 KB
最終ジャッジ日時 2023-11-26 14:50:41
合計ジャッジ時間 4,556 ms
ジャッジサーバーID
（参考情報） 		judge11 / judge15
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 2 ms
6,676 KB
testcase_01 AC 2 ms
6,676 KB
testcase_02 AC 2 ms
6,676 KB
testcase_03 AC 2 ms
6,676 KB
testcase_04 AC 2 ms
6,676 KB
testcase_05 AC 2 ms
6,676 KB
testcase_06 AC 3 ms
6,676 KB
testcase_07 AC 2 ms
6,676 KB
testcase_08 AC 3 ms
6,676 KB
testcase_09 AC 3 ms
6,676 KB
testcase_10 AC 2 ms
6,676 KB
testcase_11 AC 2 ms
6,676 KB
testcase_12 AC 2 ms
6,676 KB
testcase_13 AC 3 ms
6,676 KB
testcase_14 AC 2 ms
6,676 KB
testcase_15 AC 3 ms
6,676 KB
testcase_16 AC 2 ms
6,676 KB
testcase_17 AC 3 ms
6,676 KB
testcase_18 AC 2 ms
6,676 KB
testcase_19 AC 3 ms
6,676 KB
testcase_20 AC 3 ms
6,676 KB
testcase_21 AC 2 ms
6,676 KB
testcase_22 AC 2 ms
6,676 KB
権限があれば一括ダウンロードができます

ソースコード

diff # 

#include<bits/stdc++.h>
#include<atcoder/all>
using namespace std;
using namespace atcoder;
// long long
using ll = long long;
// unsigned long long 
using ull = unsigned long long;
// string 
using str = string;
// long double
using ld = long double;
// pair 
using pll = pair < ll, ll >;
// tuple
using tlll = tuple < ll, ll, ll >;
// vector
template < class T > using v = vector < T >;
using vl = v < ll >;
using vbl = v < bool >;
// priority_queue 
template < class T > using pq = priority_queue < T >;
template < class T > using pqg = priority_queue < T, v < T >, greater < T > >;
// unordered_set
template < class T > using uset = unordered_set < T > ;
// unordered_map
template < class T, class U > using umap = unordered_map < T, U > ;
// rep
#define rep(i, a, b) for(ll i = a; i <= b; i ++)
#define Rep(i, a) for(ll i = 0; i < a; i ++)
#define rrep(i, a, b) for(ll i = a; i >= b; i --)
#define repp(i, a, b, c) for(ll i = a; i <= b; i += c)
// binary search
#define lobo(x, k) lower_bound(x.begin(), x.end(), k) - x.begin()
#define Lobo(x, a, b, k) lower_bound(x + a, x + b + 1, k) - x
#define upbo(x, k) upper_bound(x.begin(), x.end(), k) - x.begin()
#define Upbo(x, a, b, k) upper_bound(x + a, x + b + 1, k) - x;
// snippet
#define eruni(x) x.erase(unique(x.begin(), x.end()), x.end())
#define eb emplace_back
#define mp make_pair
#define mt make_tuple
#define all(x) x.begin(), x.end()
#define rll(x) x.rbegin(), x.rend()
#define sz(x) (ll)x.size()
#define f first 
#define s second 
#define in insert
#define pf push_front
#define p_f pop_front
#define pb push_back
#define p_b pop_back
#define p_p prev_permutation
#define n_p next_permutation
#define led leader
#define print(a) printf("%.20Lf", a);
// function
template < class T > bool chmax(T &a, const T &b) {if (a < b) {a = b; return 1;} return 0;}
template < class T > bool chmin(T &a, const T &b) {if (b < a) {a = b; return 1;} return 0;}
// out
void Yes(bool f = true) {cout << (f ? "Yes" : "No" ) << endl;}
void No(bool f = true) {cout << (f ? "No" : "Yes" ) << endl;}
void YES(bool f = true) {cout << (f ? "YES" : "NO" ) << endl;}
void NO(bool f = true) {cout << (f ? "NO" : "YES" ) << endl;}
template < class T > void out(T a) {cout << a << endl;}
template < class T > void out1(T a) {cout << a << " ";}
template < class T, class U > void out2(T a, U b) {cout << a << " " << b << endl;}
template < class T> void allout(T &a) {
   for(auto x : a) cout << x << " ";
   cout << endl;
}
template < class T > void allout1(T &a) {
   for(auto x : a) cout << x << endl;
}

// modint
using modi = modint998244353;
using mint = modint1000000007;
// constant
const ll md = 998244353;
const ll mo = 1000000007;
const ld pi = acos(-1);
const ll inf = (1LL << 60);
// grid
const pll ar1[4] = { {0, 0}, {1, 0}, {0, 1}, {1, 1} };
const pll ar2[4] = { {-1, 0}, {0, -1}, {1, 0}, {0, 1} };
const pll ar3[8] = { {-1, 0}, {0, -1}, {1, 0}, {0, 1}, {-1, 1}, {1, -1}, {1, 1}, {-1, -1} };

int main(){
   ll n, x, A[1009], B[1009];
   cin >> n >> x;
   rep(i, 1, n) cin >> A[i] >> B[i];
   rep(i, 1, x){
     ll ans = -inf;
     rep(j, 1, n) chmax(ans, max((ll)0, B[j] - abs(i - A[j])));
     out1(ans);
   }
   cout << endl;
}
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