結果

問題 No.2692 How Many Times Reached?
ユーザー kikueplkikuepl
提出日時 2024-02-13 18:24:03
言語 C++14
(gcc 12.3.0 + boost 1.83.0)
結果
AC  
実行時間 2 ms / 2,000 ms
コード長 4,284 bytes
コンパイル時間 1,056 ms
コンパイル使用メモリ 107,720 KB
実行使用メモリ 6,676 KB
最終ジャッジ日時 2024-02-24 20:13:38
合計ジャッジ時間 2,394 ms
ジャッジサーバーID
(参考情報)
judge13 / judge16
このコードへのチャレンジ
(要ログイン)

テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 2 ms
6,676 KB
testcase_01 AC 2 ms
6,676 KB
testcase_02 AC 2 ms
6,676 KB
testcase_03 AC 2 ms
6,676 KB
testcase_04 AC 2 ms
6,676 KB
testcase_05 AC 2 ms
6,676 KB
testcase_06 AC 1 ms
6,676 KB
testcase_07 AC 2 ms
6,676 KB
testcase_08 AC 2 ms
6,676 KB
testcase_09 AC 1 ms
6,676 KB
testcase_10 AC 2 ms
6,676 KB
testcase_11 AC 2 ms
6,676 KB
testcase_12 AC 2 ms
6,676 KB
testcase_13 AC 2 ms
6,676 KB
testcase_14 AC 2 ms
6,676 KB
testcase_15 AC 1 ms
6,676 KB
testcase_16 AC 2 ms
6,676 KB
testcase_17 AC 1 ms
6,676 KB
testcase_18 AC 2 ms
6,676 KB
testcase_19 AC 2 ms
6,676 KB
testcase_20 AC 2 ms
6,676 KB
testcase_21 AC 2 ms
6,676 KB
testcase_22 AC 2 ms
6,676 KB
testcase_23 AC 2 ms
6,676 KB
testcase_24 AC 2 ms
6,676 KB
testcase_25 AC 2 ms
6,676 KB
testcase_26 AC 2 ms
6,676 KB
testcase_27 AC 2 ms
6,676 KB
testcase_28 AC 2 ms
6,676 KB
testcase_29 AC 2 ms
6,676 KB
testcase_30 AC 2 ms
6,676 KB
testcase_31 AC 2 ms
6,676 KB
testcase_32 AC 2 ms
6,676 KB
testcase_33 AC 2 ms
6,676 KB
testcase_34 AC 2 ms
6,676 KB
testcase_35 AC 2 ms
6,676 KB
testcase_36 AC 2 ms
6,676 KB
testcase_37 AC 2 ms
6,676 KB
testcase_38 AC 2 ms
6,676 KB
testcase_39 AC 2 ms
6,676 KB
testcase_40 AC 2 ms
6,676 KB
testcase_41 AC 2 ms
6,676 KB
testcase_42 AC 2 ms
6,676 KB
testcase_43 AC 2 ms
6,676 KB
testcase_44 AC 2 ms
6,676 KB
testcase_45 AC 2 ms
6,676 KB
testcase_46 AC 2 ms
6,676 KB
権限があれば一括ダウンロードができます
コンパイルメッセージ
main.cpp: In function 'std::ostream& operator<<(std::ostream&, std::map<T, S>&)':
main.cpp:99:16: warning: structured bindings only available with '-std=c++17' or '-std=gnu++17' [-Wc++17-extensions]
   99 |     for (auto &[key, val] : mp)
      |                ^

ソースコード

diff #

#include <algorithm>
#include <iostream>
#include <iomanip>
#include <limits.h>
#include <map>
#include <math.h>
#include <numeric>
#include <queue>
#include <set>
#include <sstream>
#include <string>
#include <utility>
#include <vector>
#include <stack>
#include <complex>

using namespace std;
#define rep(i, n) for (int i = 0; i < n; i++)
#define rep1(i, n) for (int i = 1; i < n + 1; i++)
#define rev(i, n) for (int i = n - 1; i >= 0; i--)
#define all(A) A.begin(), A.end()
#define itr(A, l, r) A.begin() + l, A.begin() + r
#define debug(var) cout << #var << " = " << var << endl;
typedef long long ll;

template <typename T1, typename T2>
ostream &operator<<(ostream &os, const pair<T1, T2> &p)
{
    os << "(" << p.first << "," << p.second << ")";
    return os;
}

template <typename T1, typename T2>
istream &operator>>(istream &is, pair<T1, T2> &p)
{
    is >> p.first >> p.second;
    return is;
}

template <typename T>
ostream &operator<<(ostream &os, const vector<T> &v)
{
    for (int i = 0; i < (int)v.size(); i++)
    {
        os << v[i] << (i + 1 != (int)v.size() ? " " : "");
    }
    return os;
}

template <typename T>
ostream &operator<<(ostream &os, const vector<vector<T>> &v)
{
    for (int i = 0; i < (int)v.size(); i++)
    {
        os << v[i] << endl;
    }
    return os;
}

template <typename T>
ostream &operator<<(ostream &os, const vector<vector<vector<T>>> &v)
{
    int n = v.size();
    int m = v[0].size();
    int p = v[0][0].size();
    rep(k, p)
    {
        os << "k = " << k << endl;
        rep(i, n)
        {
            rep(j, m)
            {
                os << v[i][j][k];
                if (j < m - 1)
                {
                    os << " ";
                }
                else
                {
                    os << endl;
                }
            }
        }
    }
    return os;
}

template <typename T>
istream &operator>>(istream &is, vector<T> &v)
{
    for (T &in : v)
        is >> in;
    return is;
}

template <typename T, typename S>
ostream &operator<<(ostream &os, map<T, S> &mp)
{
    for (auto &[key, val] : mp)
    {
        os << key << ":" << val << " ";
    }
    cout << endl;
    return os;
}

template <typename T>
ostream &operator<<(ostream &os, set<T> st)
{
    auto itr = st.begin();
    for (int i = 0; i < (int)st.size(); i++)
    {
        os << *itr << (i + 1 != (int)st.size() ? " " : "");
        itr++;
    }
    return os;
}

template <typename T>
ostream &operator<<(ostream &os, multiset<T> st)
{
    auto itr = st.begin();
    for (int i = 0; i < (int)st.size(); i++)
    {
        os << *itr << (i + 1 != (int)st.size() ? " " : "");
        itr++;
    }
    return os;
}

template <typename T>
ostream &operator<<(ostream &os, queue<T> q)
{
    while (q.size())
    {
        os << q.front() << " ";
        q.pop();
    }
    return os;
}

template <typename T>
ostream &operator<<(ostream &os, deque<T> q)
{
    while (q.size())
    {
        os << q.front() << " ";
        q.pop_front();
    }
    return os;
}

template <typename T>
ostream &operator<<(ostream &os, stack<T> st)
{
    while (st.size())
    {
        os << st.top() << " ";
        st.pop();
    }
    return os;
}

template <typename T>
ostream &operator<<(ostream &os, priority_queue<T> pq)
{
    while (pq.size())
    {
        os << pq.top() << " ";
        pq.pop();
    }
    return os;
}

template <typename T>
ostream &operator<<(ostream &os, priority_queue<T, vector<T>, greater<T>> mpq)
{
    while (mpq.size())
    {
        os << mpq.top() << " ";
        mpq.pop();
    }
    return os;
}

int main()
{
    int n;
    cin >> n;
    vector<string> s(n);
    cin >> s;
    int ans = 0;
    rep(i, n)
    {
        map<char, int> mp;
        rep(j, n)
        {
            mp[s[i][j]]++;
        }
        ans += (mp['A'] == n - 1 && mp['.'] == 1);
    }
    rep(i, n)
    {
        map<char, int> mp;
        rep(j, n)
        {
            mp[s[j][i]]++;
        }
        ans += (mp['A'] == n - 1 && mp['.'] == 1);
    }
    map<char, int> mp;
    rep(i, n)
    {
        mp[s[i][i]]++;
    }
    ans += (mp['A'] == n - 1 && mp['.'] == 1);
    mp = {};
    rep(i, n)
    {
        mp[s[n - 1 - i][i]]++;
    }
    ans += (mp['A'] == n - 1 && mp['.'] == 1);
    cout << ans << endl;
}
0