結果

問題 No.2709 1975 Powers
ユーザー coindarwcoindarw
提出日時 2024-03-31 14:17:02
言語 C++23
(gcc 12.3.0 + boost 1.83.0)
結果
WA  
実行時間 -
コード長 5,518 bytes
コンパイル時間 5,446 ms
コンパイル使用メモリ 310,048 KB
実行使用メモリ 406,144 KB
最終ジャッジ日時 2024-03-31 14:17:28
合計ジャッジ時間 24,295 ms
ジャッジサーバーID
(参考情報)
judge13 / judge15
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 154 ms
46,968 KB
testcase_01 AC 153 ms
46,968 KB
testcase_02 AC 442 ms
146,688 KB
testcase_03 AC 689 ms
251,648 KB
testcase_04 AC 1,068 ms
377,736 KB
testcase_05 WA -
testcase_06 WA -
testcase_07 AC 234 ms
71,544 KB
testcase_08 WA -
testcase_09 WA -
testcase_10 AC 245 ms
73,592 KB
testcase_11 WA -
testcase_12 WA -
testcase_13 WA -
testcase_14 AC 439 ms
245,632 KB
testcase_15 WA -
testcase_16 WA -
testcase_17 WA -
testcase_18 WA -
testcase_19 WA -
testcase_20 WA -
testcase_21 WA -
testcase_22 TLE -
testcase_23 -- -
testcase_24 -- -
testcase_25 -- -
testcase_26 -- -
権限があれば一括ダウンロードができます

ソースコード

diff #

#include <bits/stdc++.h>

#include <atcoder/all>

using ll = long long;
using lll = __int128_t;
#define rep(i, n) for (int i = 0, i##_len = (n); i < i##_len; ++i)
#define reps(i, n) for (int i = 1, i##_len = (n); i <= i##_len; ++i)
#define rrep(i, n) for (int i = ((int)(n)-1); i >= 0; --i)
#define rreps(i, n) for (int i = ((int)(n)); i > 0; --i)
#define rep2(i, s, n) for (int i = (s); i < (int)(n); i++)
#define repc2(i, s, n) for (int i = (s); i <= (int)(n); i++)
#define length(v) ((int)(v).size())
constexpr int inf = 2'000'000'000;
constexpr ll linf = 4'000'000'000'000'000'000, M7 = 1'000'000'007, M9 = 998'244'353;
#define all(v) begin(v), end(v)
#define rall(v) rbegin(v), rend(v)
using namespace std;
using namespace atcoder;

// clang-format off
#define Vec(type, ...) __make_vec<type>(__VA_ARGS__)
template <class T> vector<T> __make_vec(size_t a) {return vector<T>(a);}template <class T, class... Ts>
auto __make_vec(size_t a, Ts... ts) {return vector<decltype(__make_vec<T>(ts...))>(a, __make_vec<T>(ts...));}
#define VecI(init, type, ...) __make_vecI<type, init>(__VA_ARGS__)
template <class T, T init>vector<T> __make_vecI(size_t a) {return vector<T>(a, init);}
template <class T, T init, class... Ts>
auto __make_vecI(size_t a, Ts... ts) {return vector<decltype(__make_vecI<T, init>(ts...))>(a, __make_vecI<T, init>(ts...));}

template <typename T, typename U>inline ostream& operator<<(ostream& os, const pair<T, U>& p) noexcept {return os << p.first << " " << p.second;}
inline ostream& operator<<(ostream& os, const modint& m) noexcept { return os << m.val(); }
template <int M>inline ostream& operator<<(ostream& os, const static_modint<M>& m) noexcept { return os << m.val(); }

template <typename T> struct is_static_modint : std::false_type {}; template <int MOD> struct is_static_modint<static_modint<MOD>> : std::true_type {};
template <template <typename...> typename C, typename Number>concept MyContainer = std::is_same_v<C<Number>, std::vector<Number>> || std::is_same_v<C<Number>, std::deque<Number>> || std::is_same_v<C<Number>, std::set<Number>> || std::is_same_v<C<Number>, std::unordered_set<Number>> || std::is_same_v<C<Number>, std::unordered_multiset<Number>> || std::is_same_v<C<Number>, std::multiset<Number>>;
template <typename Number>concept MyNumber = std::is_same_v<Number, int> || std::is_same_v<Number, ll> || std::is_same_v<Number, char> || std::is_same_v<Number, modint> || is_static_modint<Number>::value;
template <template <typename...> typename C, typename Number>concept MyContainerNumber = MyContainer<C, Number> && MyNumber<Number>;
template <template <typename...> typename OutCon, template <typename...> typename InCon, typename Number>concept MyNestedContainerNumber = MyContainer<OutCon, InCon<Number>> && MyContainerNumber<InCon, Number>;
template <template <typename...> typename C, typename Number>requires MyContainerNumber<C, Number>std::ostream& operator<<(std::ostream& os, const C<Number>& t) {auto itr = t.begin();auto end = t.end();if (itr != end) {os << *itr++;for (; itr != end; ++itr) os << ' ' << *itr;}return os;}
template <template <typename...> typename OutCon, template <typename...> typename InCon, typename Number>requires MyNestedContainerNumber<OutCon, InCon, Number>std::ostream& operator<<(std::ostream& os, const OutCon<InCon<Number>>& t) {auto itr = t.begin();auto end = t.end();if (itr != end) {os << *itr++;for (; itr != end; ++itr) os << '\n' << *itr;}return os;}
template <typename T, typename U>istream& operator>>(istream& is, pair<T, U>& p) {return is >> p.first >> p.second;}
template <typename T>istream& operator>>(istream& is, vector<T>& v) {for (auto& e : v) is >> e;return is;}
void inp() {}
template <typename T, typename... Args>void inp(T& a, Args&... args) {cin >> a, inp(args...);}
template <typename T>void inp1(vector<T>& v, int offset = 1, int len = -1) {if (len == -1) len = int(v.size()) - offset;assert(offset >= 0 && len >= 0);for (int i = offset; i < offset + len; ++i) cin >> v[i];}
template <typename T>void oup(const T& a) {cout << a << "\n";}
template <typename T, typename... Args>void oup(const T& a, const Args&... args) {cout << a << " ", oup(args...);}

inline string YESNO(bool cond) { return cond ? "YES" : "NO"; }inline string yesno(bool cond) { return cond ? "yes" : "no"; }inline string YesNo(bool cond) { return cond ? "Yes" : "No"; }
inline auto add1(auto vec, ll offset = 1) {for (auto& e : vec) e += offset;return vec;}
#ifdef ONLINE_JUDGE
#define debug(...)
#else
#define debug(...) cerr << "<" << #__VA_ARGS__ << ">: ", debug_out(__VA_ARGS__)
template <typename T>void debug_out(T t) {cerr << t << "\n";}
template <typename T, typename... Args>void debug_out(T t, Args... args) {cerr << t << ", ";debug_out(args...);}
#endif

#ifdef ONLINE_JUDGE
#define todo(...) static_assert(false)
#else
#define todo(...)
#endif
// clang-format on

int dp[200][5][100000];
int main() {
    ios_base::sync_with_stdio(false);
    cin.tie(NULL);
    ll n, p, q;
    inp(n, p, q);

    vector<int> a(n);

    vector<vector<int>> mod = vector<vector<int>>(4, vector<int>(2000000 + 1));
    vector<int> B = {10, 9, 7, 5};
    rep(i, 4) {
        mod[i][0] = 1;
        reps(j, 2000000) { mod[i][j] = mod[i][j - 1] * B[i] % p; }
    }

    inp(a);

    dp[0][0][0] = 1;

    rep(i, n) rep(j, 5) rep(k, p) {
        dp[i + 1][j][k] += dp[i][j][k];
        if (j == 4) continue;
        int r = (k + mod[j][a[i]]) % p;
        dp[i + 1][j + 1][r] += dp[i][j][k];
    }

    oup(dp[n][4][q]);
    return 0;
}
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