結果

問題 No.2709 1975 Powers
ユーザー kaityo_17kaityo_17
提出日時 2024-03-31 14:24:27
言語 C++14
(gcc 12.3.0 + boost 1.83.0)
結果
AC  
実行時間 827 ms / 2,000 ms
コード長 2,937 bytes
コンパイル時間 4,318 ms
コンパイル使用メモリ 232,596 KB
実行使用メモリ 66,036 KB
最終ジャッジ日時 2024-03-31 14:24:42
合計ジャッジ時間 15,042 ms
ジャッジサーバーID
(参考情報)
judge10 / judge13
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 94 ms
66,032 KB
testcase_01 AC 94 ms
66,032 KB
testcase_02 AC 99 ms
66,032 KB
testcase_03 AC 460 ms
66,036 KB
testcase_04 AC 701 ms
66,036 KB
testcase_05 AC 505 ms
66,036 KB
testcase_06 AC 220 ms
66,036 KB
testcase_07 AC 95 ms
66,032 KB
testcase_08 AC 214 ms
66,036 KB
testcase_09 AC 510 ms
66,036 KB
testcase_10 AC 93 ms
66,032 KB
testcase_11 AC 105 ms
66,032 KB
testcase_12 AC 124 ms
66,032 KB
testcase_13 AC 545 ms
66,036 KB
testcase_14 AC 152 ms
66,032 KB
testcase_15 AC 162 ms
66,032 KB
testcase_16 AC 417 ms
66,036 KB
testcase_17 AC 95 ms
66,032 KB
testcase_18 AC 133 ms
66,032 KB
testcase_19 AC 688 ms
66,036 KB
testcase_20 AC 97 ms
66,032 KB
testcase_21 AC 207 ms
66,036 KB
testcase_22 AC 802 ms
66,036 KB
testcase_23 AC 822 ms
66,036 KB
testcase_24 AC 795 ms
66,036 KB
testcase_25 AC 804 ms
66,036 KB
testcase_26 AC 827 ms
66,036 KB
権限があれば一括ダウンロードができます

ソースコード

diff #

#include <bits/stdc++.h>
#include <atcoder/all>
#define rep(i,a,n) for(ll i = a; i < n; i++)
#define yes (cout << "Yes" << endl)
#define YES (cout << "YES" << endl)
#define no (cout << "No" << endl)
#define NO (cout << "NO" << endl)
#define pb push_back
#define pf push_front
#define mp make_pair
#define fi first
#define se second
#define all(a)  (a).begin(),(a).end()
using namespace std;
using namespace atcoder;
using ll = long long;
using ull = unsigned long long;
using vi = vector<int>;
using vd = vector<double>;
using vs = vector<string>;
using vl = vector<long long>;
using vvi = vector<vector<int>>;
using Graph = vector<vector<int>>;
const int mod = 998244353;
const int MOD = 1000000007;
const int dx[4] = {-1,0,1,0};
const int dy[4] = {0,1,0,-1};
ll chmin(ll a,ll b) {
    if(a < b) return a;
    else return b;
}
void O(vector<int> v) {
    rep(i,0,v.size()) {
        cout << v[i] << " ";
    }
    cout << endl;
}
void O(vector<string> v) {
    rep(i,0,v.size()) cout << v[i] << endl;
    cout << endl;
}
void O(int a) {
    cout << a << endl;
}
void O(ll a) {
    cout << a << endl;
}
void O(string s) {
    cout << s << endl;
}
struct unionfind {
  vector<int> data;
  unionfind(int size) : data(size, -1) { }
  bool unite(int x, int y) {
    x = root(x); y = root(y);
    if (x != y) {
      if (data[y] < data[x]) swap(x, y);
      data[x] += data[y]; data[y] = x;
    }
    return x != y;
  }
  bool same(int x, int y) {
    return root(x) == root(y);
  }
  int root(int x) {
    return data[x] < 0 ? x : data[x] = root(data[x]);
  }
  int size(int x) {
    return -data[root(x)];
  }
};
ll gcd(ll a, ll b) {
	a = abs(a); b = abs(b);
	if (a < b)swap(a, b);
	while (b) {
		ll r = a % b; a = b; b = r;
	}
	return a;
}
//x,yがax+by=gcd(a,b)の解になる x,yが格納
ll extgcd(ll a, ll b, ll& x, ll& y) {
	ll d = a;
	if (b != 0) {
		d = extgcd(b, a % b, y, x);
		y -= (a / b) * x;
	}
	else {
		x = 1; y = 0;
	}
	return d;
}
ll pow(ll a,ll b) {
    ll ans = 1;
    rep(i,0,b) ans *= a;
    return ans;
}

int main() {
    ll n,p,q;
    cin >> n >> p >> q;
    ll a[n];
    rep(i,0,n) {
        cin >> a[i];
        
    }
    sort(a,a + n);

    ll ten[2000006],nine[2000006],seven[2000006],five[2000006];
    ten[0] = 1;
    nine[0] = 1;
    seven[0] = 1;
    five[0] = 1;
    rep(i,1,2000006) {
        ten[i] = (ten[i - 1] * 10) % p;
        nine[i] = (nine[i - 1] * 9) % p;
        seven[i] = (seven[i - 1] * 7) % p;
        five[i] = (five[i - 1] * 5) % p;
    }
    //rep(i,0,p) cout << i << " " << ten[i] << " " << nine[i] << " " << seven[i] << " " << five[i] << endl;
    ll ans = 0;
    rep(i,0,n) rep(j,i + 1,n) rep(k,j + 1,n) rep(l,k + 1,n) {
        ll now = ten[a[i]] + nine[a[j]] + seven[a[k]] + five[a[l]];
        now %= p;
        if(now == q) {
            ans++;
            //cout << a[i] << " " << a[j] << " " << a[k] << " " << a[l] << now << endl;
        }

    }
    cout << ans << endl;
}


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