結果

問題 No.577 Prime Powerful Numbers
コンテスト
ユーザー Ryuhei Mori
提出日時 2017-10-27 19:52:07
言語 C
(gcc 13.3.0)
結果
AC  
実行時間 12 ms / 2,000 ms
コード長 4,062 bytes
コンパイル時間 216 ms
コンパイル使用メモリ 32,256 KB
実行使用メモリ 6,820 KB
最終ジャッジ日時 2024-11-21 21:23:14
合計ジャッジ時間 808 ms
ジャッジサーバーID
（参考情報） 		judge3 / judge2
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 1
other AC * 10
権限があれば一括ダウンロードができます

ソースコード

diff # 

#include <stdio.h>
#include <stdint.h>

typedef unsigned __int128 uint128_t;

void ex_gcd(uint64_t y, uint64_t *b){
  int i;
  uint64_t u, v;
  u = 1; v = 0;
  uint64_t x = 1LL<<63;

  for(i=0;i<64;i++){
    if(u&1){
      u = (u + y) / 2;
      v = v/2 + x;
    }
    else {
      u >>= 1; v >>= 1;
    }
  }

  *b = v;
} 


uint64_t MR(uint128_t x, uint64_t m, uint64_t n){
  uint64_t z = ((uint128_t) ((uint64_t) x * m) * n + x) >> 64;
  return z < n ? z : z - n;
}

uint64_t RM(uint64_t x, uint64_t r2, uint64_t m, uint64_t n){
  return MR((uint128_t) r2 * x, m, n);
}


uint64_t modpow64(uint64_t a, uint64_t k, uint64_t m, uint64_t n, uint64_t one){
  uint64_t r;
  for(r=one;k;k/=2){
    if(k&1) r = MR((uint128_t)r*a, m, n);
    a = MR((uint128_t) a*a, m, n);
  }
  return r;
}

uint32_t modpow32(uint32_t a, uint32_t k, uint32_t n){
  uint32_t r;
  for(r=1;k;k/=2){
    if(k&1) r = (uint64_t)r*a%n;
    a = (uint64_t) a*a%n;
  }
  return r;
}

const uint32_t as32[] = {2, 7, 61};

int is_prime32(uint32_t n){
  int i, j, r;
  uint32_t d;
  if(n <= 1) return 0;
  if(n <= 3) return 1;
  if(!(n & 1)) return 0;
  r = __builtin_ctz(n-1);
  d = (n-1) >> r;
  for(i=0;i<3;i++){
    uint32_t a = as32[i] % n;
    if(a == 0) return 1;
    uint32_t t = modpow32(a, d, n);
    if(t == 1) continue;
    for(j=0;t!=n-1;j++){
      if(j == r-1) return 0;
      t = (uint64_t) t * t % n;
      if(t == 1) return 0;
    }
  }
  return 1;
}


const uint64_t as64[] = {2, 325, 9375, 28178, 450775, 9780504, 1795265022};

int is_prime64(uint64_t n){
  int i, j, r;
  uint64_t d, one, mone, r2, s, m;
  if(n <= 1) return 0;
  if(n <= 3) return 1;
  if(!(n & 1)) return 0;
  if(n < (1L << 32)) is_prime32(n);
  r = __builtin_ctzll(n-1);
  d = (n-1) >> r;
  ex_gcd(n, &m);
  one = -1UL % n + 1;
  mone = n - one;
  r2 = (uint128_t) one * one % n;
  for(i=0;i<7;i++){
    uint64_t a = RM(as64[i], r2, m, n);
    if(a == 0) return 1;
    uint64_t t = modpow64(a, d, m, n, one);
    if(t == one) continue;
    for(j=0;t!=mone;j++){
      if(j == r-1) return 0;
      t = MR((uint128_t) t * t, m, n);
      if(t == one) return 0;
    }
  }
  return 1;
}

uint64_t gcd64(uint64_t x, uint64_t y){
  if(x == 0 || y == 0) return x^y;
  int bx = __builtin_ctzll(x);
  int by = __builtin_ctzll(y);
  int k = (bx < by) ? bx : by;
  x >>= bx;
  y >>= by;
  while(x!=y){
    if(x < y){
      y -= x;
      y >>= __builtin_ctzll(y);
    }
    else {
      x -= y;
      x >>= __builtin_ctzll(x);
    }
  }
  return x << k;
}

int is_power64(uint64_t n, uint64_t p){
  int i;
  uint64_t a[49];
  uint64_t x;
  a[0] = p;
  a[1] = p * p;
  for(i=1; a[i] <= n && a[i] > a[i-1]; i++){
    a[i+1] = a[i] * a[i];
  }
/*
  if(a[--i] == n) return 1;
  while(i){
    if(n % a[i]) return 0;
    n /= a[i];
    while(i > 0 && n < a[--i]) ;
  }
*/
  x = a[--i];
  if(x == n) return 1;
  for(--i; i>=0;--i){
    uint64_t y = x * a[i];
    if(y == n) return 1;
    else if(y < x) return 0;
    else if(y < n) x = y;
  }
  return 0;
}

uint64_t is_primepower64(uint64_t n){
  uint64_t i;
  if(n <= 1) return 0;
  if(!(n&(n-1))) return 2;
  if(!(n&1)) return 0;

  uint64_t s, m, r2, one;
  ex_gcd(n, &m);
  one = -1UL % n + 1;
  r2 = (uint128_t) one * one % n;

  for(i=0;i<1;i++){
    uint64_t y = as64[i]%n;
    uint64_t x = RM(y, r2, m, n);
    uint64_t in = MR((uint128_t)modpow64(x, n, m, n, one), m, n);
    uint64_t inmi = in >= y ? in - y : in + n - y;
    uint64_t p = gcd64(inmi, n);
    if(p == 1) return 0;
    if(is_prime64(p)){
//      while(n % p == 0) n /= p;
//      return n == 1;
      return is_power64(n, p);
    }
    n = p;
    ex_gcd(n, &m);
    one = -1UL % n + 1;
    r2 = (uint128_t) one * one % n;
  }
  return 0;
}


int main(){
  int i, q;

  scanf("%d", &q);
  for(i=0;i<q;i++){
    uint64_t n;
    scanf("%ld", &n);
    if(n<=2) puts("No");
    else if((n&1)==0) puts("Yes");
    else {
      uint64_t j;
      for(j=2; j<n; j<<=1){
        if(is_primepower64(n-j)){
          break;
        }
      }
      if(j>=n) puts("No"); else puts("Yes");
    }
  }
  return 0;
}
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