結果

問題 No.996 Phnom Penh
ユーザー neterukunneterukun
提出日時 2020-02-21 22:57:35
言語 PyPy3
(7.3.15)
結果
WA  
実行時間 -
コード長 3,036 bytes
コンパイル時間 256 ms
コンパイル使用メモリ 82,048 KB
実行使用メモリ 72,704 KB
最終ジャッジ日時 2024-04-17 08:02:31
合計ジャッジ時間 2,284 ms
ジャッジサーバーID
(参考情報)
judge3 / judge4
このコードへのチャレンジ
(要ログイン)

テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 39 ms
51,968 KB
testcase_01 AC 37 ms
52,224 KB
testcase_02 AC 37 ms
52,480 KB
testcase_03 WA -
testcase_04 WA -
testcase_05 WA -
testcase_06 WA -
testcase_07 WA -
testcase_08 WA -
testcase_09 WA -
testcase_10 WA -
testcase_11 WA -
testcase_12 WA -
testcase_13 WA -
testcase_14 WA -
testcase_15 WA -
testcase_16 WA -
testcase_17 WA -
testcase_18 AC 36 ms
52,096 KB
testcase_19 WA -
testcase_20 AC 37 ms
52,608 KB
testcase_21 AC 37 ms
52,096 KB
testcase_22 AC 38 ms
52,096 KB
testcase_23 AC 38 ms
52,224 KB
testcase_24 AC 58 ms
66,176 KB
testcase_25 WA -
testcase_26 WA -
testcase_27 WA -
権限があれば一括ダウンロードができます

ソースコード

diff #

s = input()
n = len(s)

ans = 0
for i in range(n - 4):
    if s[i:i+4] == "penh":
        tmp = 0
        flag_o = False
        for j in range(i + 4, n):
            if s[j] == "h":
                continue
            if s[j] == "e":
                if tmp >= 1:
                    continue
                else:
                    ans = max(ans, tmp * 2 + 2)
                    break
            if s[j] == "o" and not flag_o:
                flag_o = True
                continue
            if s[j] == "m" and flag_o:
                flag_o = False
                tmp += 1
                continue
            else:
                ans = max(ans, tmp * 2 + 2)
                break
        else:
            ans = max(ans, tmp * 2 + 2)

for i in range(n - 5):
    if s[i:i+5] == "phnom":
        tmp = 0
        flag_o = False
        for j in range(i + 5, n):
            if s[j] == "h":
                continue
            if s[j] == "e":
                if tmp >= 1:
                    continue
                else:
                    ans = max(ans, tmp * 2 + 3)
                    break
            if s[j] == "o" and not flag_o:
                flag_o = True
                continue
            if s[j] == "m" and flag_o:
                flag_o = False
                tmp += 1
                continue
            else:
                ans = max(ans, tmp * 2 + 3)
                break
        else:
            ans = max(ans, tmp * 2 + 3)

if "h" in s:
    ans = max(ans, 1)
if "e" in s:
    ans = max(ans, 2)



s = s.replace("h", "")
s = s.replace("e", "h")
n = len(s)
for i in range(n - 4):
    if s[i:i+4] == "penh":
        tmp = 0
        flag_o = False
        for j in range(i + 4, n):
            if s[j] == "h":
                continue
            if s[j] == "e":
                if tmp >= 1:
                    continue
                else:
                    ans = max(ans, tmp * 2 + 3)
                    break
            if s[j] == "o" and not flag_o:
                flag_o = True
                continue
            if s[j] == "m" and flag_o:
                flag_o = False
                tmp += 1
                continue
            else:
                ans = max(ans, tmp * 2 + 3)
                break
        else:
            ans = max(ans, tmp * 2 + 3)

for i in range(n - 5):
    if s[i:i+5] == "phnom":
        tmp = 0
        flag_o = False
        for j in range(i + 5, n):
            if s[j] == "h":
                continue
            if s[j] == "e":
                if tmp >= 1:
                    continue
                else:
                    ans = max(ans, tmp * 2 + 4)
                    break
            if s[j] == "o" and not flag_o:
                flag_o = True
                continue
            if s[j] == "m" and flag_o:
                flag_o = False
                tmp += 1
                continue
            else:
                ans = max(ans, tmp * 2 + 4)
                break
        else:
            ans = max(ans, tmp * 2 + 4)


print(ans)
0