結果
| 問題 | 
                            No.996 Phnom Penh
                             | 
                    
| コンテスト | |
| ユーザー | 
                             neterukun
                         | 
                    
| 提出日時 | 2020-02-21 23:33:24 | 
| 言語 | PyPy3  (7.3.15)  | 
                    
| 結果 | 
                             
                                WA
                                 
                             
                            
                         | 
                    
| 実行時間 | - | 
| コード長 | 3,124 bytes | 
| コンパイル時間 | 298 ms | 
| コンパイル使用メモリ | 82,304 KB | 
| 実行使用メモリ | 72,064 KB | 
| 最終ジャッジ日時 | 2024-10-09 02:38:54 | 
| 合計ジャッジ時間 | 2,578 ms | 
| 
                            ジャッジサーバーID (参考情報)  | 
                        judge2 / judge3 | 
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| ファイルパターン | 結果 | 
|---|---|
| sample | AC * 3 | 
| other | AC * 18 WA * 7 | 
ソースコード
s = input()
n = len(s)
ans = 0
flag = False
for i in range(n - 3):
    if s[i:i+4] == "penh":
        flag = True
        tmp = 0
        flag_o = False
        for j in range(i + 4, n):
            if s[j] == "h":
                continue
            if s[j] == "e":
                if tmp >= 1:
                    continue
                else:
                    ans += tmp * 2
                    break
            if s[j] == "o" and not flag_o:
                flag_o = True
                continue
            if s[j] == "m" and flag_o:
                flag_o = False
                tmp += 1
                continue
            else:
                ans += tmp * 2
                break
        else:
            ans += tmp * 2
for i in range(n - 4):
    if s[i:i+5] == "phnom":
        tmp = 0
        flag_o = False
        flag = True
        for j in range(i + 5, n):
            if s[j] == "h":
                continue
            if s[j] == "e":
                if tmp >= 1:
                    continue
                else:
                    ans += tmp * 2 + 1
                    break
            if s[j] == "o" and not flag_o:
                flag_o = True
                continue
            if s[j] == "m" and flag_o:
                flag_o = False
                tmp += 1
                continue
            else:
                ans += tmp * 2 + 1
                break
        else:
            ans += tmp * 2 + 1
if flag:
    ans += 2
if "h" in s:
    ans = max(ans, 1)
if "e" in s:
    ans = max(ans, 2)
if ans == 0:
    print(ans)
    exit()
    
res = ans
ans = 1
s = s.replace("h", "")
s = s.replace("e", "h")
n = len(s)
flag = False
for i in range(n - 3):
    if s[i:i+4] == "penh":
        flag = True
        tmp = 0
        flag_o = False
        for j in range(i + 4, n):
            if s[j] == "h":
                continue
            if s[j] == "e":
                if tmp >= 1:
                    continue
                else:
                    ans += tmp * 2
                    break
            if s[j] == "o" and not flag_o:
                flag_o = True
                continue
            if s[j] == "m" and flag_o:
                flag_o = False
                tmp += 1
                continue
            else:
                ans += tmp * 2
                break
        else:
            ans += tmp * 2
for i in range(n - 4):
    if s[i:i+5] == "phnom":
        tmp = 0
        flag_o = False
        flag = True
        for j in range(i + 5, n):
            if s[j] == "h":
                continue
            if s[j] == "e":
                if tmp >= 1:
                    continue
                else:
                    ans += tmp * 2 + 1
                    break
            if s[j] == "o" and not flag_o:
                flag_o = True
                continue
            if s[j] == "m" and flag_o:
                flag_o = False
                tmp += 1
                continue
            else:
                ans += tmp * 2 + 1
                break
        else:
            ans += tmp * 2 + 1
if flag:
    ans += 2
print(max(res, ans))
            
            
            
        
            
neterukun