結果

問題 No.1324 Approximate the Matrix
ユーザー opt
提出日時 2020-12-08 20:42:20
言語 Python3
(3.13.1 + numpy 2.2.1 + scipy 1.14.1)
結果
TLE  
実行時間 -
コード長 2,303 bytes
コンパイル時間 84 ms
コンパイル使用メモリ 12,928 KB
実行使用メモリ 30,240 KB
最終ジャッジ日時 2024-09-19 23:38:05
合計ジャッジ時間 9,490 ms
ジャッジサーバーID
（参考情報） 		judge2 / judge4
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 36 TLE * 6
権限があれば一括ダウンロードができます

ソースコード

diff # 

#!/usr/local/bin/pypy
# python 想定解 O(NK)本の辺を張り，下駄をはかせる
from heapq import heappush, heappop

class MinCostFlow:
    INF = 10**18

    def __init__(self, N):
        self.N = N
        self.G = [[] for i in range(N)]

    def add_edge(self, fr, to, cap, cost):
        forward = [to, cap, cost, None]
        backward = forward[3] = [fr, 0, -cost, forward]
        self.G[fr].append(forward)
        self.G[to].append(backward)

    def flow(self, s, t, f):
        N = self.N; G = self.G
        INF = MinCostFlow.INF

        res = 0
        H = [0]*N
        prv_v = [0]*N
        prv_e = [None]*N

        d0 = [INF]*N
        dist = [INF]*N

        while f:
            dist[:] = d0
            dist[s] = 0
            que = [(0, s)]

            while que:
                c, v = heappop(que)
                if dist[v] < c:
                    continue
                r0 = dist[v] + H[v]
                for e in G[v]:
                    w, cap, cost, _ = e
                    if cap > 0 and r0 + cost - H[w] < dist[w]:
                        dist[w] = r = r0 + cost - H[w]
                        prv_v[w] = v; prv_e[w] = e
                        heappush(que, (r, w))
            if dist[t] == INF:
                return None

            for i in range(N):
                H[i] += dist[i]

            d = f; v = t
            while v != s:
                d = min(d, prv_e[v][1])
                v = prv_v[v]
            f -= d
            res += d * H[t]
            v = t
            while v != s:
                e = prv_e[v]
                e[1] -= d
                e[3][1] += d
                v = prv_v[v]
        return res

import sys
readline = sys.stdin.readline
write = sys.stdout.write
BIG = 1000
N, K = map(int, readline().split())
A = list(map(int, readline().split()))
B = list(map(int, readline().split()))
P = []
for i in range(N):
    P.append(list(map(int, readline().split())))

mcf = MinCostFlow(2*N+2)
s = 2*N
t = s+1

for i in range(N):
    mcf.add_edge(s, i, A[i], 0)

S = 0

for i in range(N):
    for j in range(N):
        S += P[i][j] * P[i][j]
        for x in range(A[i]):
            mcf.add_edge(i, N+j, 1, 2*(x-P[i][j])+1+BIG)

for i in range(N):
    mcf.add_edge(N+i, t, B[i], 0)

print(mcf.flow(s, t, K) + S - K*BIG)
0