結果
問題 | No.1324 Approximate the Matrix |
ユーザー | theory_and_me |
提出日時 | 2020-12-09 02:12:13 |
言語 | PyPy3 (7.3.15) |
結果 |
AC
|
実行時間 | 564 ms / 2,000 ms |
コード長 | 5,009 bytes |
コンパイル時間 | 213 ms |
コンパイル使用メモリ | 82,004 KB |
実行使用メモリ | 89,968 KB |
最終ジャッジ日時 | 2024-09-19 23:38:50 |
合計ジャッジ時間 | 9,547 ms |
ジャッジサーバーID (参考情報) |
judge3 / judge2 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 37 ms
53,684 KB |
testcase_01 | AC | 38 ms
54,440 KB |
testcase_02 | AC | 38 ms
53,800 KB |
testcase_03 | AC | 390 ms
89,816 KB |
testcase_04 | AC | 411 ms
89,880 KB |
testcase_05 | AC | 397 ms
89,560 KB |
testcase_06 | AC | 412 ms
89,612 KB |
testcase_07 | AC | 408 ms
89,740 KB |
testcase_08 | AC | 128 ms
79,304 KB |
testcase_09 | AC | 123 ms
78,876 KB |
testcase_10 | AC | 146 ms
79,940 KB |
testcase_11 | AC | 177 ms
81,292 KB |
testcase_12 | AC | 119 ms
78,920 KB |
testcase_13 | AC | 116 ms
78,428 KB |
testcase_14 | AC | 184 ms
82,128 KB |
testcase_15 | AC | 139 ms
79,668 KB |
testcase_16 | AC | 91 ms
76,956 KB |
testcase_17 | AC | 161 ms
80,328 KB |
testcase_18 | AC | 126 ms
78,916 KB |
testcase_19 | AC | 128 ms
78,304 KB |
testcase_20 | AC | 107 ms
78,052 KB |
testcase_21 | AC | 104 ms
77,100 KB |
testcase_22 | AC | 97 ms
77,464 KB |
testcase_23 | AC | 151 ms
79,424 KB |
testcase_24 | AC | 217 ms
82,412 KB |
testcase_25 | AC | 171 ms
80,476 KB |
testcase_26 | AC | 156 ms
80,360 KB |
testcase_27 | AC | 129 ms
78,848 KB |
testcase_28 | AC | 37 ms
53,940 KB |
testcase_29 | AC | 49 ms
63,132 KB |
testcase_30 | AC | 56 ms
67,420 KB |
testcase_31 | AC | 57 ms
67,864 KB |
testcase_32 | AC | 37 ms
54,488 KB |
testcase_33 | AC | 38 ms
54,732 KB |
testcase_34 | AC | 37 ms
54,532 KB |
testcase_35 | AC | 44 ms
62,472 KB |
testcase_36 | AC | 40 ms
55,428 KB |
testcase_37 | AC | 421 ms
89,968 KB |
testcase_38 | AC | 414 ms
89,656 KB |
testcase_39 | AC | 542 ms
89,720 KB |
testcase_40 | AC | 409 ms
89,948 KB |
testcase_41 | AC | 564 ms
89,596 KB |
testcase_42 | AC | 59 ms
71,432 KB |
testcase_43 | AC | 57 ms
71,044 KB |
testcase_44 | AC | 57 ms
71,056 KB |
ソースコード
#!/usr/local/bin/pypy # python 想定解 O(NK)本の辺を張り,下駄をはかせる ライブラリが速い import heapq class mcf_graph_int_cost: """ 頂点数、及び、costの総和が、4294967295 (== (1 << 32) - 1) を超えない前提下での高速な実装。 超えると動きません!!!!! これらが 4294967295 を超えるときはこっち使ってください。 https://atcoder.jp/contests/practice2/submissions/18032049 """ def __init__(self, n): self.n = n self.pos = [] self.g = [[] for _ in range(n)] def add_edge(self, from_, to, cap, cost): # assert 0 <= from_ < self.n # assert 0 <= to < self.n m = len(self.pos) self.pos.append((from_, len(self.g[from_]))) self.g[from_].append(self.__class__._edge(to, len(self.g[to]), cap, cost)) self.g[to].append(self.__class__._edge(from_, len(self.g[from_]) - 1, 0, -cost)) return m class edge: def __init__(self, from_, to, cap, flow, cost): self.from_ = from_ self.to = to self.cap = cap self.flow = flow self.cost = cost def get_edge(self, i): _e = self.g[self.pos[i][0]][self.pos[i][1]] _re = self.g[_e.to][_e.rev] return self.__class__.edge(self.pos[i][0], _e.to, _e.cap + _re.cap, _re.cap, _e.cost) def edges(self): ret = [] for i in range(len(self.pos)): _e = self.g[self.pos[i][0]][self.pos[i][1]] _re = self.g[_e.to][_e.rev] ret.append(self.__class__.edge(self.pos[i][0], _e.to, _e.cap + _re.cap, _re.cap, _e.cost)) return ret def _dual_ref(self, s, t): self.dist = [4294967295] * self.n self.pv = [-1] * self.n self.pe = [-1] * self.n self.vis = [False] * self.n que = [s] # s == (0 << 32) + s self.dist[s] = 0 while que: v = heapq.heappop(que) & 4294967295 if self.vis[v]: continue self.vis[v] = True if v == t: break for i in range(len(self.g[v])): e = self.g[v][i] if self.vis[e.to] or e.cap == 0: continue cost = e.cost - self.dual[e.to] + self.dual[v] if self.dist[e.to] > self.dist[v] + cost: self.dist[e.to] = self.dist[v] + cost self.pv[e.to] = v self.pe[e.to] = i heapq.heappush(que, ((self.dist[e.to] << 32) + e.to)) if not self.vis[t]: return False for v in range(self.n): if not self.vis[v]: continue self.dual[v] -= self.dist[t] - self.dist[v] return True def slope(self, s, t, flow_limit=4294967295): # assert 0 <= s < self.n # assert 0 <= t < self.n # assert s != t self.dual = [0] * self.n self.dist = [4294967295] * self.n self.pv = [-1] * self.n self.pe = [-1] * self.n self.vis = [False] * self.n flow = 0 cost = 0 prev_cost = -1 result = [(flow, cost)] while flow < flow_limit: if not self._dual_ref(s, t): break c = flow_limit - flow v = t while v != s: c = min(c, self.g[self.pv[v]][self.pe[v]].cap) v = self.pv[v] v = t while v != s: e = self.g[self.pv[v]][self.pe[v]] e.cap -= c self.g[v][e.rev].cap += c v = self.pv[v] d = -self.dual[s] flow += c cost += c * d if prev_cost == d: result.pop() result.append((flow, cost)) prev_cost = cost return result def flow(self, s, t, flow_limit=4294967295): return self.slope(s, t, flow_limit)[-1] class _edge: def __init__(self, to, rev, cap, cost): self.to = to self.rev = rev self.cap = cap self.cost = cost import sys readline = sys.stdin.readline write = sys.stdout.write if __name__ == '__main__': BIG = 400 N, K = map(int, readline().split()) A = list(map(int, readline().split())) B = list(map(int, readline().split())) P = [] for i in range(N): P.append(list(map(int, readline().split()))) mcf = mcf_graph_int_cost(2*N+2) s = 2*N t = s+1 for i in range(N): mcf.add_edge(s, i, A[i], 0) S = 0 for i in range(N): for j in range(N): S += P[i][j] * P[i][j] for x in range(A[i]): mcf.add_edge(i, N+j, 1, 2*(x-P[i][j])+1+BIG) for i in range(N): mcf.add_edge(N+i, t, B[i], 0) print(mcf.flow(s, t, K)[1] + S - K*BIG)