結果
問題 | No.1324 Approximate the Matrix |
ユーザー | tamato |
提出日時 | 2020-12-21 09:58:39 |
言語 | PyPy3 (7.3.15) |
結果 |
TLE
|
実行時間 | - |
コード長 | 3,010 bytes |
コンパイル時間 | 291 ms |
コンパイル使用メモリ | 82,432 KB |
実行使用メモリ | 269,528 KB |
最終ジャッジ日時 | 2024-09-21 12:42:36 |
合計ジャッジ時間 | 3,926 ms |
ジャッジサーバーID (参考情報) |
judge2 / judge4 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
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testcase_00 | AC | 47 ms
58,752 KB |
testcase_01 | AC | 43 ms
53,504 KB |
testcase_02 | AC | 46 ms
54,016 KB |
testcase_03 | TLE | - |
testcase_04 | -- | - |
testcase_05 | -- | - |
testcase_06 | -- | - |
testcase_07 | -- | - |
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testcase_42 | -- | - |
testcase_43 | -- | - |
testcase_44 | -- | - |
ソースコード
mod = 1000000007 eps = 10**-9 def main(): import sys input = sys.stdin.buffer.readline from heapq import heappush, heappop class Mincostflow(): def __init__(self, N): self.N = N self.adj = [[] for _ in range(N + 1)] self.inf = 1 << 60 def add_edge(self, fr, to, cap, cost): # [to, cap, cost, rev] forward = [to, cap, cost, None] backward = forward[3] = [fr, 0, -cost, forward] self.adj[fr].append(forward) self.adj[to].append(backward) def flow(self, s, t, f): N = self.N adj = self.adj inf = self.inf res = 0 H = [0] * (N + 1) prev_v = [0] * (N + 1) prev_e = [None] * (N + 1) dist0 = [inf] * (N + 1) dist = [inf] * (N + 1) while f: dist[:] = dist0 dist[s] = 0 pq = [(0, s)] while pq: d, v = heappop(pq) if d > dist[v]: continue r0 = dist[v] + H[v] for e in adj[v]: u, cap, cost, _ = e if cap > 0 and r0 + cost - H[u] < dist[u]: dist[u] = r = r0 + cost - H[u] heappush(pq, (r, u)) prev_v[u] = v prev_e[u] = e # flow f doesn't exist if dist[t] == inf: return None for i in range(1, N + 1): H[i] += dist[i] g = f v = t while v != s: g = min(g, prev_e[v][1]) v = prev_v[v] f -= g res += g * H[t] v = t while v != s: e = prev_e[v] e[1] -= g e[-1][1] += g v = prev_v[v] return res N, K = map(int, input().split()) A = list(map(int, input().split())) B = list(map(int, input().split())) P = [] for _ in range(N): P.append(list(map(int, input().split()))) s = N **2 + N*2 + 1 t = s + 1 mcf = Mincostflow(t) for i, a in enumerate(A): va = N**2 + i+1 mcf.add_edge(s, va, a, 0) for j in range(N): v = N * i + j + 1 mcf.add_edge(va, v, a, 0) for j, b in enumerate(B): vb = N**2 + N + j+1 mcf.add_edge(vb, t, b, 0) for i in range(N): v = N * i + j + 1 p = P[i][j] for f in range(b): mcf.add_edge(v, vb, 1, 40000 - (p - f)**2 + (p - f - 1)**2) ans = mcf.flow(s, t, K) - 40000 * K for i in range(N): for j in range(N): ans += P[i][j] ** 2 print(ans) if __name__ == '__main__': main()