結果

問題 No.274 The Wall
ユーザー prin_kemkemprin_kemkem
提出日時 2023-05-11 21:26:53
言語 PyPy3
(7.3.15)
結果
TLE  
実行時間 -
コード長 3,128 bytes
コンパイル時間 191 ms
コンパイル使用メモリ 82,180 KB
実行使用メモリ 592,772 KB
最終ジャッジ日時 2024-05-05 17:50:45
合計ジャッジ時間 11,697 ms
ジャッジサーバーID
（参考情報） 		judge3 / judge5
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 94 ms
79,824 KB
testcase_01 AC 92 ms
80,128 KB
testcase_02 AC 92 ms
79,616 KB
testcase_03 AC 958 ms
361,892 KB
testcase_04 AC 91 ms
79,768 KB
testcase_05 AC 94 ms
80,352 KB
testcase_06 AC 92 ms
80,000 KB
testcase_07 AC 93 ms
80,064 KB
testcase_08 AC 94 ms
80,024 KB
testcase_09 AC 95 ms
80,072 KB
testcase_10 AC 94 ms
80,244 KB
testcase_11 TLE -
testcase_12 AC 142 ms
81,480 KB
testcase_13 AC 113 ms
80,768 KB
testcase_14 AC 146 ms
82,232 KB
testcase_15 AC 185 ms
82,164 KB
testcase_16 AC 1,172 ms
315,292 KB
testcase_17 AC 1,149 ms
316,748 KB
testcase_18 AC 1,250 ms
316,632 KB
testcase_19 AC 224 ms
83,212 KB
testcase_20 AC 230 ms
83,592 KB
testcase_21 AC 208 ms
83,300 KB
testcase_22 AC 224 ms
82,844 KB
testcase_23 AC 223 ms
83,204 KB
testcase_24 AC 225 ms
83,332 KB
testcase_25 AC 221 ms
83,196 KB
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ソースコード

diff # 

from collections import defaultdict, deque, Counter
import copy
from itertools import combinations, permutations, product, accumulate, groupby
from heapq import heapify, heappop, heappush
import math
import bisect
from pprint import pprint
import sys
# sys.setrecursionlimit(700000)
input = lambda: sys.stdin.readline().rstrip('\n')
inf = float('inf')
mod1 = 10**9+7
mod2 = 998244353
def ceil_div(x, y): return -(-x//y)

#################################################

def sccd(adj):
    n = len(adj)
    been = [False]*n
    P = []
    for s in range(n):
        if been[s]: continue
        stack = [s]
        while stack:
            now = stack.pop()
            if now >= 0:
                if been[now]: continue
                been[now] = True
                stack.append(~now)
                for nxt in adj[now]:
                    if been[nxt]: continue
                    stack.append(nxt)
            else:
                P.append(~now)
    radj = [[] for _ in range(n)]
    for i, neighbor in enumerate(adj):
        for j in neighbor:
            radj[j].append(i)
    scc_prev = []
    scc_idx = [None]*n
    for s in reversed(P):
        if not been[s]: continue
        been[s] = False
        stack = [s]
        scc = []
        while stack:
            now = stack.pop()
            scc_idx[now] = (len(scc_prev), len(scc))
            scc.append(now)
            for nxt in radj[now]:
                if not been[nxt]: continue
                been[nxt] = False
                stack.append(nxt)
        scc_prev.append(scc)
    return scc_idx

class Two_SAT:
    def __init__(self, n) -> None:
        self.n = n
        self.adj = [[] for _ in range(2*n)]
    def add(self, x, y): # 否定したいときは~xを入れる
        if x >= 0 and y >= 0:
            self.adj[self.n+x].append(y)
            self.adj[self.n+y].append(x)
        elif x >= 0:
            y = ~y
            self.adj[self.n+x].append(self.n+y)
            self.adj[y].append(x)
        elif y >= 0:
            x = ~x
            self.adj[x].append(y)
            self.adj[self.n+y].append(self.n+x)
        else:
            x = ~x; y = ~y
            self.adj[x].append(self.n+y)
            self.adj[y].append(self.n+x)
    def solve(self):
        scc_idx = sccd(self.adj)
        ret = [False]*self.n
        for x in range(self.n):
            i, j = scc_idx[x][0], scc_idx[self.n+x][0]
            if i == j:
                return None
            ret[x] = i > j
        return ret

def is_intersect(li, ri, lj, rj):
    if li > lj: li, ri, lj, rj = ri, rj, li, lj
    return lj <= ri

N, M = map(int, input().split())
blocks = [tuple(map(int, input().split())) for _ in range(N)]
sat = Two_SAT(N)
for i in range(N):
    li, ri = blocks[i]
    for j in range(i+1, N):
        lj, rj = blocks[j]
        if is_intersect(li, ri, lj, rj): sat.add(~i, ~j)
        if is_intersect(li, ri, M-1-rj, M-1-lj): sat.add(~i, j)
        if is_intersect(M-1-ri, M-1-li, lj, rj): sat.add(i, ~j)
        if is_intersect(M-1-ri, M-1-li, M-1-rj, M-1-lj): sat.add(i, j)
del blocks
ans = sat.solve()
print("YNEOS"[ans is None::2])
0