結果
| 問題 |
No.2510 Six Cube Sum Counting
|
| コンテスト | |
| ユーザー |
nikoro256
|
| 提出日時 | 2023-10-20 23:09:22 |
| 言語 | PyPy3 (7.3.15) |
| 結果 |
TLE
|
| 実行時間 | - |
| コード長 | 5,349 bytes |
| コンパイル時間 | 210 ms |
| コンパイル使用メモリ | 82,304 KB |
| 実行使用メモリ | 280,588 KB |
| 最終ジャッジ日時 | 2024-09-20 22:12:26 |
| 合計ジャッジ時間 | 10,696 ms |
|
ジャッジサーバーID (参考情報) |
judge3 / judge1 |
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| ファイルパターン | 結果 |
|---|---|
| sample | TLE * 1 -- * 3 |
| other | -- * 26 |
ソースコード
# https://github.com/tatyam-prime/SortedSet/blob/main/SortedMultiset.py
import math
from bisect import bisect_left, bisect_right
from typing import Generic, Iterable, Iterator, List, Tuple, TypeVar, Optional
T = TypeVar('T')
class SortedMultiset(Generic[T]):
BUCKET_RATIO = 50
REBUILD_RATIO = 170
def _build(self, a: Optional[List[T]] = None) -> None:
"Evenly divide `a` into buckets."
if a is None: a = list(self)
size = len(a)
bucket_size = int(math.ceil(math.sqrt(size / self.BUCKET_RATIO)))
self.a = [a[size * i // bucket_size : size * (i + 1) // bucket_size] for i in range(bucket_size)]
def __init__(self, a: Iterable[T] = []) -> None:
"Make a new SortedMultiset from iterable. / O(N) if sorted / O(N log N)"
a = list(a)
self.size = len(a)
if not all(a[i] <= a[i + 1] for i in range(len(a) - 1)):
a = sorted(a)
self._build(a)
def __iter__(self) -> Iterator[T]:
for i in self.a:
for j in i: yield j
def __reversed__(self) -> Iterator[T]:
for i in reversed(self.a):
for j in reversed(i): yield j
def __eq__(self, other) -> bool:
return list(self) == list(other)
def __len__(self) -> int:
return self.size
def __repr__(self) -> str:
return "SortedMultiset" + str(self.a)
def __str__(self) -> str:
s = str(list(self))
return "{" + s[1 : len(s) - 1] + "}"
def _position(self, x: T) -> Tuple[List[T], int]:
"Find the bucket and position which x should be inserted. self must not be empty."
for a in self.a:
if x <= a[-1]: break
return (a, bisect_left(a, x))
def __contains__(self, x: T) -> bool:
if self.size == 0: return False
a, i = self._position(x)
return i != len(a) and a[i] == x
def count(self, x: T) -> int:
"Count the number of x."
return self.index_right(x) - self.index(x)
def add(self, x: T) -> None:
"Add an element. / O(√N)"
if self.size == 0:
self.a = [[x]]
self.size = 1
return
a, i = self._position(x)
a.insert(i, x)
self.size += 1
if len(a) > len(self.a) * self.REBUILD_RATIO:
self._build()
def _pop(self, a: List[T], i: int) -> T:
ans = a.pop(i)
self.size -= 1
if not a: self._build()
return ans
def discard(self, x: T) -> bool:
"Remove an element and return True if removed. / O(√N)"
if self.size == 0: return False
a, i = self._position(x)
if i == len(a) or a[i] != x: return False
self._pop(a, i)
return True
def lt(self, x: T) -> Optional[T]:
"Find the largest element < x, or None if it doesn't exist."
for a in reversed(self.a):
if a[0] < x:
return a[bisect_left(a, x) - 1]
def le(self, x: T) -> Optional[T]:
"Find the largest element <= x, or None if it doesn't exist."
for a in reversed(self.a):
if a[0] <= x:
return a[bisect_right(a, x) - 1]
def gt(self, x: T) -> Optional[T]:
"Find the smallest element > x, or None if it doesn't exist."
for a in self.a:
if a[-1] > x:
return a[bisect_right(a, x)]
def ge(self, x: T) -> Optional[T]:
"Find the smallest element >= x, or None if it doesn't exist."
for a in self.a:
if a[-1] >= x:
return a[bisect_left(a, x)]
def __getitem__(self, i: int) -> T:
"Return the i-th element."
if i < 0:
for a in reversed(self.a):
i += len(a)
if i >= 0: return a[i]
else:
for a in self.a:
if i < len(a): return a[i]
i -= len(a)
raise IndexError
def pop(self, i: int = -1) -> T:
"Pop and return the i-th element."
if i < 0:
for a in reversed(self.a):
i += len(a)
if i >= 0: return self._pop(a, i)
else:
for a in self.a:
if i < len(a): return self._pop(a, i)
i -= len(a)
raise IndexError
def index(self, x: T) -> int:
"Count the number of elements < x."
ans = 0
for a in self.a:
if a[-1] >= x:
return ans + bisect_left(a, x)
ans += len(a)
return ans
def index_right(self, x: T) -> int:
"Count the number of elements <= x."
ans = 0
for a in self.a:
if a[-1] > x:
return ans + bisect_right(a, x)
ans += len(a)
return ans
from collections import defaultdict
X=int(input())
rights=SortedMultiset()
for i in range(300,-1,-1):
for j in range(i,-1,-1):
for k in range(j,-1,-1):
rights.add(i**3+j**3+k**3)
ans=0
for limit in range(300):
#limitを左側のlimitとする。
for j in range(limit+1):
for k in range(j,limit+1):
ans_d=j**3+k**3+limit**3
ans+=rights.count(X-ans_d)
for j in range(limit,301):
for k in range(limit,301):
rights.discard(limit**3+j**3+k**3)
print(ans)
nikoro256