結果
問題 | No.2510 Six Cube Sum Counting |
ユーザー | nikoro256 |
提出日時 | 2023-10-20 23:09:22 |
言語 | PyPy3 (7.3.15) |
結果 |
TLE
|
実行時間 | - |
コード長 | 5,349 bytes |
コンパイル時間 | 210 ms |
コンパイル使用メモリ | 82,304 KB |
実行使用メモリ | 280,588 KB |
最終ジャッジ日時 | 2024-09-20 22:12:26 |
合計ジャッジ時間 | 10,696 ms |
ジャッジサーバーID (参考情報) |
judge3 / judge1 |
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テストケース
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testcase_00 | TLE | - |
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ソースコード
# https://github.com/tatyam-prime/SortedSet/blob/main/SortedMultiset.py import math from bisect import bisect_left, bisect_right from typing import Generic, Iterable, Iterator, List, Tuple, TypeVar, Optional T = TypeVar('T') class SortedMultiset(Generic[T]): BUCKET_RATIO = 50 REBUILD_RATIO = 170 def _build(self, a: Optional[List[T]] = None) -> None: "Evenly divide `a` into buckets." if a is None: a = list(self) size = len(a) bucket_size = int(math.ceil(math.sqrt(size / self.BUCKET_RATIO))) self.a = [a[size * i // bucket_size : size * (i + 1) // bucket_size] for i in range(bucket_size)] def __init__(self, a: Iterable[T] = []) -> None: "Make a new SortedMultiset from iterable. / O(N) if sorted / O(N log N)" a = list(a) self.size = len(a) if not all(a[i] <= a[i + 1] for i in range(len(a) - 1)): a = sorted(a) self._build(a) def __iter__(self) -> Iterator[T]: for i in self.a: for j in i: yield j def __reversed__(self) -> Iterator[T]: for i in reversed(self.a): for j in reversed(i): yield j def __eq__(self, other) -> bool: return list(self) == list(other) def __len__(self) -> int: return self.size def __repr__(self) -> str: return "SortedMultiset" + str(self.a) def __str__(self) -> str: s = str(list(self)) return "{" + s[1 : len(s) - 1] + "}" def _position(self, x: T) -> Tuple[List[T], int]: "Find the bucket and position which x should be inserted. self must not be empty." for a in self.a: if x <= a[-1]: break return (a, bisect_left(a, x)) def __contains__(self, x: T) -> bool: if self.size == 0: return False a, i = self._position(x) return i != len(a) and a[i] == x def count(self, x: T) -> int: "Count the number of x." return self.index_right(x) - self.index(x) def add(self, x: T) -> None: "Add an element. / O(√N)" if self.size == 0: self.a = [[x]] self.size = 1 return a, i = self._position(x) a.insert(i, x) self.size += 1 if len(a) > len(self.a) * self.REBUILD_RATIO: self._build() def _pop(self, a: List[T], i: int) -> T: ans = a.pop(i) self.size -= 1 if not a: self._build() return ans def discard(self, x: T) -> bool: "Remove an element and return True if removed. / O(√N)" if self.size == 0: return False a, i = self._position(x) if i == len(a) or a[i] != x: return False self._pop(a, i) return True def lt(self, x: T) -> Optional[T]: "Find the largest element < x, or None if it doesn't exist." for a in reversed(self.a): if a[0] < x: return a[bisect_left(a, x) - 1] def le(self, x: T) -> Optional[T]: "Find the largest element <= x, or None if it doesn't exist." for a in reversed(self.a): if a[0] <= x: return a[bisect_right(a, x) - 1] def gt(self, x: T) -> Optional[T]: "Find the smallest element > x, or None if it doesn't exist." for a in self.a: if a[-1] > x: return a[bisect_right(a, x)] def ge(self, x: T) -> Optional[T]: "Find the smallest element >= x, or None if it doesn't exist." for a in self.a: if a[-1] >= x: return a[bisect_left(a, x)] def __getitem__(self, i: int) -> T: "Return the i-th element." if i < 0: for a in reversed(self.a): i += len(a) if i >= 0: return a[i] else: for a in self.a: if i < len(a): return a[i] i -= len(a) raise IndexError def pop(self, i: int = -1) -> T: "Pop and return the i-th element." if i < 0: for a in reversed(self.a): i += len(a) if i >= 0: return self._pop(a, i) else: for a in self.a: if i < len(a): return self._pop(a, i) i -= len(a) raise IndexError def index(self, x: T) -> int: "Count the number of elements < x." ans = 0 for a in self.a: if a[-1] >= x: return ans + bisect_left(a, x) ans += len(a) return ans def index_right(self, x: T) -> int: "Count the number of elements <= x." ans = 0 for a in self.a: if a[-1] > x: return ans + bisect_right(a, x) ans += len(a) return ans from collections import defaultdict X=int(input()) rights=SortedMultiset() for i in range(300,-1,-1): for j in range(i,-1,-1): for k in range(j,-1,-1): rights.add(i**3+j**3+k**3) ans=0 for limit in range(300): #limitを左側のlimitとする。 for j in range(limit+1): for k in range(j,limit+1): ans_d=j**3+k**3+limit**3 ans+=rights.count(X-ans_d) for j in range(limit,301): for k in range(limit,301): rights.discard(limit**3+j**3+k**3) print(ans)