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No.8038 Period of the Fibonacci Sequence

レベル : / AI推定難易度 : 2300 / 実行時間制限 : 1ケース 3.000秒 / メモリ制限 : 512 MB / 標準ジャッジ問題
タグ : (AC するまで非表示) / 解いたユーザー数 11
作問者 : testestest
お気に入りにしたユーザー ProblemId : 1314 / 自分の提出
問題文最終更新日: 2025-03-04 09:55:51
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Problem Statement

The sequence $\{F_i\}$ defined by $F_0=0,\ \ F_1=1, \ \ F_i=F_{i-1}+F_{i-2}\ (i\geq2)$ is called the Fibonacci sequence.
Find the period of the Fibonacci sequence $\bmod M$, modulo $10^9+7$.

Input

N
p_1 k_1
...
p_N k_N

$M$ is given in prime-factorized form, where $M=\prod p_i^{k_i}$.
$1\leq N\leq 1000$: integer
$2\leq p_i \leq 10^7$: prime numbers, pairwise distinct
$1\leq k_i \leq 1000$: integer

There are 25 test cases in total.
The 7 test cases whose names start with 1small satisfy $M\leq 10^7$ (about ★2)
The 9 test cases whose names start with 2med satisfy $N\leq 20$ and, for all $i$, $p_i\leq10^6,\ k_i=1$ (about ★3)
The 9 test cases whose names start with 3large have no additional constraints (about ★4)

Output

Output the period of the Fibonacci sequence $\bmod M$, modulo $10^9+7$.
Here, "the period of the Fibonacci sequence $\{F_i\}$ $\bmod M$" refers to the smallest positive integer $n$ satisfying the following condition.
Condition: there exists a non-negative integer $A$ such that $F_{B+n}=F_{B} \bmod M$ holds for every integer $B$ greater than or equal to $A$

Sample

Sample 1
Input
2
2 2
3 1
Output
24

We have $M=2^2 \cdot 3^1=12$. According to OEIS A001175, the period mod 12 is apparently 24.
Actually computing it gives $0,1,1,2,3,5,8,1,9,10,7,5,0,5,5,10,3,1,4,5,9,2,11,1,0,1,1,\ldots$, and indeed $F_{n+24}=F_n$ holds.
This case satisfies the additional constraints of small.

Sample 2
Input
2
97 1
103093 1
Output
10103212

The period mod 10^7+21 is apparently 10103212.
This case satisfies the additional constraints of med.

Sample 3
Input
2
9999937 2
9999761 2
Output
650542141

The period mod 9999396012131709055946713249 is apparently 96148038578019322985423540.

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