結果

問題 No.674 n連勤
ユーザー titiatitia
提出日時 2024-08-16 04:19:07
言語 PyPy3
(7.3.15)
結果
AC  
実行時間 440 ms / 2,000 ms
コード長 5,774 bytes
コンパイル時間 394 ms
コンパイル使用メモリ 82,828 KB
実行使用メモリ 85,652 KB
最終ジャッジ日時 2024-08-16 04:19:12
合計ジャッジ時間 4,870 ms
ジャッジサーバーID
(参考情報)
judge3 / judge4
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 57 ms
69,516 KB
testcase_01 AC 59 ms
68,768 KB
testcase_02 AC 62 ms
69,060 KB
testcase_03 AC 59 ms
68,196 KB
testcase_04 AC 60 ms
69,032 KB
testcase_05 AC 57 ms
68,724 KB
testcase_06 AC 58 ms
67,972 KB
testcase_07 AC 59 ms
69,176 KB
testcase_08 AC 57 ms
69,336 KB
testcase_09 AC 60 ms
69,216 KB
testcase_10 AC 57 ms
68,776 KB
testcase_11 AC 127 ms
79,424 KB
testcase_12 AC 208 ms
80,532 KB
testcase_13 AC 112 ms
78,960 KB
testcase_14 AC 163 ms
79,772 KB
testcase_15 AC 263 ms
80,860 KB
testcase_16 AC 378 ms
85,340 KB
testcase_17 AC 351 ms
85,652 KB
testcase_18 AC 440 ms
85,096 KB
testcase_19 AC 164 ms
80,068 KB
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ソースコード

diff #

import sys
input = sys.stdin.readline

# https://github.com/tatyam-prime/SortedSet/blob/main/SortedSet.py
import math
from bisect import bisect_left, bisect_right
from typing import Generic, Iterable, Iterator, List, Tuple, TypeVar, Optional
T = TypeVar('T')

class SortedSet(Generic[T]):
    BUCKET_RATIO = 16
    SPLIT_RATIO = 24
    
    def __init__(self, a: Iterable[T] = []) -> None:
        "Make a new SortedSet from iterable. / O(N) if sorted and unique / O(N log N)"
        a = list(a)
        n = len(a)
        if any(a[i] > a[i + 1] for i in range(n - 1)):
            a.sort()
        if any(a[i] >= a[i + 1] for i in range(n - 1)):
            a, b = [], a
            for x in b:
                if not a or a[-1] != x:
                    a.append(x)
        n = self.size = len(a)
        num_bucket = int(math.ceil(math.sqrt(n / self.BUCKET_RATIO)))
        self.a = [a[n * i // num_bucket : n * (i + 1) // num_bucket] for i in range(num_bucket)]

    def __iter__(self) -> Iterator[T]:
        for i in self.a:
            for j in i: yield j

    def __reversed__(self) -> Iterator[T]:
        for i in reversed(self.a):
            for j in reversed(i): yield j
    
    def __eq__(self, other) -> bool:
        return list(self) == list(other)
    
    def __len__(self) -> int:
        return self.size
    
    def __repr__(self) -> str:
        return "SortedSet" + str(self.a)
    
    def __str__(self) -> str:
        s = str(list(self))
        return "{" + s[1 : len(s) - 1] + "}"

    def _position(self, x: T) -> Tuple[List[T], int, int]:
        "return the bucket, index of the bucket and position in which x should be. self must not be empty."
        for i, a in enumerate(self.a):
            if x <= a[-1]: break
        return (a, i, bisect_left(a, x))

    def __contains__(self, x: T) -> bool:
        if self.size == 0: return False
        a, _, i = self._position(x)
        return i != len(a) and a[i] == x

    def add(self, x: T) -> bool:
        "Add an element and return True if added. / O(√N)"
        if self.size == 0:
            self.a = [[x]]
            self.size = 1
            return True
        a, b, i = self._position(x)
        if i != len(a) and a[i] == x: return False
        a.insert(i, x)
        self.size += 1
        if len(a) > len(self.a) * self.SPLIT_RATIO:
            mid = len(a) >> 1
            self.a[b:b+1] = [a[:mid], a[mid:]]
        return True
    
    def _pop(self, a: List[T], b: int, i: int) -> T:
        ans = a.pop(i)
        self.size -= 1
        if not a: del self.a[b]
        return ans

    def discard(self, x: T) -> bool:
        "Remove an element and return True if removed. / O(√N)"
        if self.size == 0: return False
        a, b, i = self._position(x)
        if i == len(a) or a[i] != x: return False
        self._pop(a, b, i)
        return True
    
    def lt(self, x: T) -> Optional[T]:
        "Find the largest element < x, or None if it doesn't exist."
        for a in reversed(self.a):
            if a[0] < x:
                return a[bisect_left(a, x) - 1]

    def le(self, x: T) -> Optional[T]:
        "Find the largest element <= x, or None if it doesn't exist."
        for a in reversed(self.a):
            if a[0] <= x:
                return a[bisect_right(a, x) - 1]

    def gt(self, x: T) -> Optional[T]:
        "Find the smallest element > x, or None if it doesn't exist."
        for a in self.a:
            if a[-1] > x:
                return a[bisect_right(a, x)]

    def ge(self, x: T) -> Optional[T]:
        "Find the smallest element >= x, or None if it doesn't exist."
        for a in self.a:
            if a[-1] >= x:
                return a[bisect_left(a, x)]
    
    def __getitem__(self, i: int) -> T:
        "Return the i-th element."
        if i < 0:
            for a in reversed(self.a):
                i += len(a)
                if i >= 0: return a[i]
        else:
            for a in self.a:
                if i < len(a): return a[i]
                i -= len(a)
        raise IndexError
    
    def pop(self, i: int = -1) -> T:
        "Pop and return the i-th element."
        if i < 0:
            for b, a in enumerate(reversed(self.a)):
                i += len(a)
                if i >= 0: return self._pop(a, ~b, i)
        else:
            for b, a in enumerate(self.a):
                if i < len(a): return self._pop(a, b, i)
                i -= len(a)
        raise IndexError
    
    def index(self, x: T) -> int:
        "Count the number of elements < x."
        ans = 0
        for a in self.a:
            if a[-1] >= x:
                return ans + bisect_left(a, x)
            ans += len(a)
        return ans

    def index_right(self, x: T) -> int:
        "Count the number of elements <= x."
        ans = 0
        for a in self.a:
            if a[-1] > x:
                return ans + bisect_right(a, x)
            ans += len(a)
        return ans

D,Q=map(int,input().split())
S=SortedSet()
ANS=0
for i in range(Q):
    A,B=map(int,input().split())
    S.add((A,B))

    k=S.index((A,B))
    ANS=max(ANS,B-A+1)

    while k>=1:
        z,w=S[k-1]

        if A<=w+1:
            p=min(A,z)
            q=max(B,w)

            S.discard((A,B))
            S.discard((z,w))
            S.add((p,q))
            ANS=max(ANS,q-p+1)
            k-=1
            A=p
            B=q
        else:
            break

    k=S.index((A,B))
    ANS=max(ANS,B-A+1)

    while k<len(S)-1:
        z,w=S[k+1]

        if z<=B+1:
            p=min(A,z)
            q=max(B,w)

            S.discard((A,B))
            S.discard((z,w))
            S.add((p,q))
            ANS=max(ANS,q-p+1)
            A=p
            B=q
        else:
            break

    print(ANS)

    
0