結果
| 問題 |
No.2845 Birthday Pattern in Two Different Calendars
|
| コンテスト | |
| ユーザー |
👑 |
| 提出日時 | 2024-08-23 22:18:31 |
| 言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
AC
|
| 実行時間 | 379 ms / 2,000 ms |
| コード長 | 2,706 bytes |
| コンパイル時間 | 3,860 ms |
| コンパイル使用メモリ | 256,408 KB |
| 最終ジャッジ日時 | 2025-02-23 23:58:16 |
|
ジャッジサーバーID (参考情報) |
judge3 / judge3 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 1 |
| other | AC * 22 |
ソースコード
#include<bits/stdc++.h>
#include<atcoder/all>
#define rep(i,n) for(int i=0;i<n;i++)
using namespace std;
using namespace atcoder;
typedef long long ll;
typedef vector<int> vi;
typedef vector<long long> vl;
typedef vector<vector<int>> vvi;
typedef vector<vector<long long>> vvl;
typedef long double ld;
typedef pair<int, int> P;
ostream& operator<<(ostream& os, const modint& a) {os << a.val(); return os;}
template <int m> ostream& operator<<(ostream& os, const static_modint<m>& a) {os << a.val(); return os;}
template <int m> ostream& operator<<(ostream& os, const dynamic_modint<m>& a) {os << a.val(); return os;}
template<typename T> istream& operator>>(istream& is, vector<T>& v){int n = v.size(); assert(n > 0); rep(i, n) is >> v[i]; return is;}
template<typename U, typename T> ostream& operator<<(ostream& os, const pair<U, T>& p){os << p.first << ' ' << p.second; return os;}
template<typename T> ostream& operator<<(ostream& os, const vector<T>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : " "); return os;}
template<typename T> ostream& operator<<(ostream& os, const vector<vector<T>>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : ""); return os;}
template<typename T> ostream& operator<<(ostream& os, const set<T>& se){for(T x : se) os << x << " "; os << "\n"; return os;}
template<typename T> ostream& operator<<(ostream& os, const unordered_set<T>& se){for(T x : se) os << x << " "; os << "\n"; return os;}
template<typename S, auto op, auto e> ostream& operator<<(ostream& os, const atcoder::segtree<S, op, e>& seg){int n = seg.max_right(0, [](S){return true;}); rep(i, n) os << seg.get(i) << (i == n - 1 ? "\n" : " "); return os;}
template<typename S, auto op, auto e, typename F, auto mapping, auto composition, auto id> ostream& operator<<(ostream& os, const atcoder::lazy_segtree<S, op, e, F, mapping, composition, id>& seg){int n = seg.max_right(0, [](S){return true;}); rep(i, n) os << seg.get(i) << (i == n - 1 ? "\n" : " "); return os;}
template<typename T> void chmin(T& a, T b){a = min(a, b);}
template<typename T> void chmax(T& a, T b){a = max(a, b);}
int solve(){
int k, m, n;
cin >> k >> m >> n;
if(m == 1){
cout << "No\n";
return 0;
}
vector<int> ans;
set<int> t;
for(int x = 0; x < k; x++){
int y = x;
while(true){
if(t.find(y) == t.end() and t.find((y + m - 1) % k) == t.end()){
t.insert(y);
t.insert((y + m - 1) % k);
ans.push_back(y);
y += 2 * m - 2;
y %= k;
}else break;
}
}
if(int(ans.size()) >= n){
cout << "Yes\n";
rep(i, n) cout << ans[i] + 1 << ' ';
cout << "\n";
}else{
cout << "No\n";
}
return 0;
}
int main(){
int t;
cin >> t;
rep(_, t) solve();
return 0;
}