結果

問題 No.2844 Birthday Party Decoration
ユーザー ktr216ktr216
提出日時 2024-08-23 22:34:27
言語 C++14
(gcc 12.3.0 + boost 1.83.0)
結果
AC  
実行時間 8 ms / 2,000 ms
コード長 4,916 bytes
コンパイル時間 2,225 ms
コンパイル使用メモリ 184,260 KB
実行使用メモリ 10,412 KB
最終ジャッジ日時 2024-08-23 22:34:30
合計ジャッジ時間 2,613 ms
ジャッジサーバーID
(参考情報)
judge2 / judge4
このコードへのチャレンジ
(要ログイン)

テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 3 ms
9,668 KB
testcase_01 AC 8 ms
9,924 KB
testcase_02 AC 8 ms
10,412 KB
testcase_03 AC 7 ms
10,128 KB
testcase_04 AC 8 ms
10,284 KB
権限があれば一括ダウンロードができます

ソースコード

diff #

#include <bits/stdc++.h>
using namespace std;

#define double long double

using ll = long long;
using ull = unsigned long long;
using VB = vector<bool>;
using VVB = vector<VB>;
using VVVB = vector<VVB>;
using VC = vector<char>;
using VVC = vector<VC>;
using VI = vector<int>;
using VVI = vector<VI>;
using VVVI = vector<VVI>;
using VVVVI = vector<VVVI>;
using VL = vector<ll>;
using VVL = vector<VL>;
using VVVL = vector<VVL>;
using VVVVL = vector<VVVL>;
using VVVVVL = vector<VVVVL>;
using VD = vector<double>;
using VVD = vector<VD>;
using VVVD = vector<VVD>;
using VT = vector<string>;
using VVT = vector<VT>;
//using P = pair<int, int>;

#define REP(i, n) for (ll i = 0; i < (ll)(n); i++)
#define FOR(i, a, b) for (ll i = a; i < (ll)(b); i++)
#define ALL(a) (a).begin(),(a).end()

constexpr int INF = 1001001001;
constexpr ll LINF = 1001001001001001001ll;
//constexpr ll LINF = 8e18;
//constexpr int DX[] = {-1, -1, 0, 0, 1, 1};
//constexpr int DY[] = {-1, 0, -1, 1, 0, 1};
constexpr int DX[] = {1, 0, -1, 0, 0, 0};
constexpr int DY[] = {0, 1, 0, -1, 0, 0};
constexpr int DZ[] = {0, 0, 0,  0, 1, -1};

template< typename T1, typename T2>
inline bool chmax(T1 &a, T2 b) {return a < b && (a = b, true); }
template< typename T1, typename T2>
inline bool chmin(T1 &a, T2 b) {return a > b && (a = b, true); }

const ll MOD = 998244353;
//const ll MOD = 1000000007;

const int MAX_N = 200000;
int par[MAX_N];
int rnk[MAX_N];
int siz[MAX_N];

void init(int n) {
    REP(i,n) {
        par[i] = i;
        rnk[i] = 0;
        siz[i] = 1;
    }
}

int find(int x) {
    if (par[x] == x) {
        return x;
    } else {
        return par[x] = find(par[x]);
    }
}

void unite(int x, int y) {
    x = find(x);
    y = find(y);
    if (x == y) return;
    int s = siz[x] + siz[y];
    if (rnk[x] < rnk[y]) {
        par[x] = y;
    } else {
        par[y] = x;
        if (rnk[x] == rnk[y]) rnk[x]++;
    }
    siz[find(x)] = s;
}

bool same(int x, int y) {
    return find(x) == find(y);
}

int size(int x) {
    return siz[find(x)];
}

ll mod_pow(ll x, ll n, ll mod) {
    ll res = 1;
    x %= mod;
    while (n > 0) {
        if (n & 1) res = res * x % mod;
        x = x * x % mod;
        n >>= 1;
    }
    return res;
}

ll gcd(ll x, ll y) {
    if (y == 0) return x;
    return gcd(y, x % y);
}

typedef pair<ll, int> P0;
struct edge { int to; int cost; };

const int MAX_V = 200000;
//const ll LINF = 1LL<<60;

int V;
vector<edge> G[MAX_V];
ll D[MAX_V];

void dijkstra(ll s) {
    priority_queue<P0, vector<P0>, greater<P0> > que;
    fill(D, D + V, INF);
    D[s] = 0;
    que.push(P0(0, s));

    while (!que.empty()) {
        P0 p = que.top(); que.pop();
        int v = p.second;
        if (D[v] < p.first) continue;
        for (edge e : G[v]) {
            if (D[e.to] > D[v] + e.cost) {
                D[e.to] = D[v] + e.cost;
                que.push(P0(D[e.to], e.to));
            }
        }
    }
}

/*

double EPS = 1e-10;

double add(double a, double b) {
    if (abs(a + b) < EPS * (abs(a) + abs(b))) return 0;
    return a + b;
}

struct P {
    double x, y;
    P() {}
    P(double x, double y) : x(x), y(y) {
    }
    P operator + (P p) {
        return P(add(x, p.x), add(y, p.y));
    }
    P operator - (P p) {
        return P(add(x, -p.x), add(y, -p.y));
    }
    P operator * (double d) {
        return P(x * d, y * d);
    }
    double dot(P p) {
        return add(x * p.x, y * p.y);
    }
    double det(P p) {
        return add(x * p.y, -y * p.x);
    }
};

bool on_seg(P p1, P p2, P q) {
    return ()
}

P intersection(P p1, P p2, P q1, P q2) {
    return p1 + (p2 - p1) * ((q2 - q1).det(q1 - p1) / (q2 - q1).det(p2 - p1));
}

*/

/*

VL f(400010, 1);

ll C(ll n, ll k) {
    return f[n] * mod_pow(f[k], MOD - 2, MOD) % MOD * mod_pow(f[n - k], MOD - 2, MOD) % MOD;
}

*/

bool fcomp(VL x, VL y) {
    if (x[0] * y[1] > x[1] * y[0]) return true;
    return false;
}

// 拡張ユークリッドの互除法の実装例
// ax + by = \pm gcd(a, b) となるx,yを返す
pair<long long, long long> extgcd(long long a, long long b) {
  if (b == 0) return make_pair(1, 0);
  long long x, y;
  tie(y, x) = extgcd(b, a % b);
  y -= a / b * x;
  return make_pair(x, y);
}

void solve(int n, ll x, VI c) {
    ll l = x, r = x;
    REP(i, n) {
        if ((x >> c[i]) & 1) continue;
        chmin(l, x / (1LL << c[i]) * (1LL << c[i]) - 1);
        if (x / (1LL << c[i]) == 0) l = -LINF;
        chmax(r, x / (1LL << c[i]) * (1LL << c[i]) + (1LL << c[i]));
    }
    //cout << "l=" << l << " r=" << r << endl;
    cout << min(x - l, r - x) * 2 << endl;
}

int main() {
    ios::sync_with_stdio(false);
    std::cin.tie(nullptr);
    int t;
    cin >> t;
    VL n(t), x(t);
    VVI c(t);
    REP(i, t) {
        cin >> n[i] >> x[i];
        REP(j, n[i]) {
            c[i].push_back(0);
            cin >> c[i][j];
        }
    }
    REP(i, t) {
        solve(n[i], x[i], c[i]);
    }
}
0