結果

問題 No.2852 Yakitori Optimization Problem
ユーザー ルク
提出日時 2024-08-25 13:45:54
言語 C++17(gcc12)
(gcc 12.3.0 + boost 1.87.0)
結果
AC  
実行時間 92 ms / 2,000 ms
コード長 2,165 bytes
コンパイル時間 23,329 ms
コンパイル使用メモリ 357,944 KB
最終ジャッジ日時 2025-02-24 00:56:06
ジャッジサーバーID
(参考情報)
judge2 / judge4
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ファイルパターン 結果
other AC * 17
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#pragma GCC target("avx2")
#pragma GCC optimize("O3")
#pragma GCC optimize("unroll-loops")
#include <bits/stdc++.h>
#if __has_include(<atcoder/all>)
#include <atcoder/all>
using namespace atcoder;
#endif
#if __has_include("./cpp-dump/cpp-dump.hpp")
#include "./cpp-dump/cpp-dump.hpp"
#endif
#include <chrono>
#include <unistd.h>
using namespace std;
using namespace chrono;
#define rep(i, n) for (ll i = 0; i < (n); ++i)
#define rep1(i, n) for (ll i = 1; i <= (n); ++i)
#define rrep(i, n) for (ll i = n; i > 0; --i)
#define bitrep(i, n) for (ll i = 0; i < (1 << n); ++i)
#define all(a) (a).begin(), (a).end()
#define yesNo(b) ((b) ? "Yes" : "No")
using ll = long long;
using ull = unsigned long long;
using ld = long double;
using mint = modint998244353;
using MINT = modint1000000007;
string alphabet = "abcdefghijklmnopqrstuvwxyz";
string ALPHABET = "ABCDEFGHIJKLMNOPQRSTUVWXYZ";
constexpr double pi = 3.141592653589793;
constexpr ll smallMOD = 998244353;
constexpr ll bigMOD = 1000000007;
constexpr ll dx[] = {1, 0, -1, 0, 1, -1, -1, 1};
constexpr ll dy[] = {0, 1, 0, -1, 1, 1, -1, -1};
struct Init
{
Init()
{
ios::sync_with_stdio(0);
cin.tie(0);
cout << fixed << setprecision(15);
}
} init;
template <typename T>
ostream &operator<<(ostream &os, const vector<T> &vec)
{
os << "[";
rep(i, vec.size())
{
os << vec[i];
if (i != vec.size() - 1)
os << ", ";
}
os << "]";
return os;
}
template <typename T>
ostream &operator<<(ostream &os, const vector<vector<T>> &vec)
{
os << "[";
rep(i, vec.size())
{
os << vec[i];
if (i != vec.size() - 1)
os << ", ";
}
os << "]";
return os;
}
int main()
{
ll n, m;
cin >> n >> m;
vector<ll> a(n), b(n), c(n);
rep(i, n) cin >> a[i];
rep(i, n) cin >> b[i];
rep(i, n) cin >> c[i];
ll sm = accumulate(all(a), 0LL) + accumulate(all(b), 0LL);
ll k = 0;
vector<ll> diff(n);
rep(i, n)
{
diff[i] = c[i] - b[i];
}
sort(all(diff), greater<ll>());
rep(i, n - m)
{
sm += diff[i];
}
cout << sm << endl;
return 0;
}
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