結果
| 問題 |
No.901 K-ary εxtrεεmε
|
| コンテスト | |
| ユーザー |
|
| 提出日時 | 2024-09-04 17:21:13 |
| 言語 | C++23 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
AC
|
| 実行時間 | 362 ms / 3,000 ms |
| コード長 | 5,030 bytes |
| コンパイル時間 | 3,623 ms |
| コンパイル使用メモリ | 264,504 KB |
| 実行使用メモリ | 29,048 KB |
| 最終ジャッジ日時 | 2024-09-04 17:21:26 |
| 合計ジャッジ時間 | 13,337 ms |
|
ジャッジサーバーID (参考情報) |
judge1 / judge3 |
(要ログイン)
| ファイルパターン | 結果 |
|---|---|
| sample | AC * 1 |
| other | AC * 29 |
ソースコード
#include <bits/stdc++.h>
using namespace std;
template <typename T>
struct graph {
struct edge {
int from;
int to;
T cost;
};
vector<edge> edges;
vector<vector<int>> g;
int n;
graph(int _n) : n(_n) {
g.resize(n);
}
virtual int add(int from, int to, T cost) = 0;
};
template <typename T>
struct forest : graph<T> {
using graph<T>::edges;
using graph<T>::g;
using graph<T>::n;
forest(int _n) : graph<T>(_n) {}
int add(int from, int to, T cost = 1) {
assert(0 <= from && from < n && 0 <= to && to < n);
int id = (int)edges.size();
assert(id < n - 1);
g[from].push_back(id);
g[to].push_back(id);
edges.push_back({from, to, cost});
return id;
}
};
template <typename T>
struct dfs_forest : forest<T> {
using forest<T>::edges;
using forest<T>::g;
using forest<T>::n;
vector<int> pv;
vector<int> pe;
vector<int> order;
vector<int> pos;
vector<int> end;
vector<int> sz;
vector<int> root;
vector<int> depth;
vector<T> dist;
dfs_forest(int _n) : forest<T>(_n) {}
void init() {
pv = vector<int>(n, -1);
pe = vector<int>(n, -1);
order.clear();
pos = vector<int>(n, -1);
end = vector<int>(n, -1);
sz = vector<int>(n, 0);
root = vector<int>(n, -1);
depth = vector<int>(n, -1);
dist = vector<T>(n);
}
void clear() {
pv.clear();
pe.clear();
order.clear();
pos.clear();
end.clear();
sz.clear();
root.clear();
depth.clear();
dist.clear();
}
void dfs(int v, bool clear_order = false) {
if(pv.empty()) init(); else if(clear_order) order.clear();
do_dfs_from(v);
}
void dfs_all() {
init();
for(int v = 0; v < n; v++) {
if(depth[v] == -1) do_dfs_from(v);
}
assert((int)order.size() == n);
}
private:
void do_dfs(int v) {
pos[v] = (int) order.size();
order.push_back(v);
sz[v] = 1;
for (int id : g[v]) {
if(id == pe[v]) continue;
auto &e = edges[id];
int to = e.from ^ e.to ^ v;
depth[to] = depth[v] + 1;
dist[to] = dist[v] + e.cost;
pv[to] = v;
pe[to] = id;
root[to] = (root[v] != -1 ? root[v] : to);
do_dfs(to);
sz[v] += sz[to];
}
end[v] = (int) order.size() - 1;
}
void do_dfs_from(int v) {
depth[v] = 0;
dist[v] = T{};
root[v] = v;
pv[v] = pe[v] = -1;
do_dfs(v);
}
};
template <typename T>
struct lca_forest : dfs_forest<T> {
using dfs_forest<T>::edges;
using dfs_forest<T>::g;
using dfs_forest<T>::n;
using dfs_forest<T>::pv;
using dfs_forest<T>::pos;
using dfs_forest<T>::end;
using dfs_forest<T>::depth;
int h;
vector<vector<int>> pr;
lca_forest(int _n) : dfs_forest<T>(_n) {}
inline void build_lca() {
assert(!pv.empty());
int max_depth = 0;
for(int i = 0; i < n; i++) max_depth = max(max_depth, depth[i]);
h = 1;
while((1 << h) <= max_depth) h++;
pr.resize(n);
for(int i = 0; i < n; i++) {
pr[i].resize(h);
pr[i][0] = pv[i];
}
for(int j = 1; j < h; j++) {
for(int i = 0; i < n; i++) {
pr[i][j] = (pr[i][j - 1] == -1 ? -1 : pr[pr[i][j - 1]][j - 1]);
}
}
}
inline bool anc(int x, int y) {
return (pos[x] <= pos[y] && end[y] <= end[x]);
}
inline int go_up(int x, int up) {
assert(!pr.empty());
up = min(up, (1 << h) - 1);
for(int j = h - 1; j >= 0; j--) {
if(up & (1 << j)) {
x = pr[x][j];
if(x == -1) break;
}
}
return x;
}
inline int lca(int x, int y) {
assert(!pr.empty());
if(anc(x, y)) return x;
if(anc(y, x)) return y;
for(int j = h - 1; j >= 0; j--) {
if(pr[x][j] != -1 && !anc(pr[x][j], y)) x = pr[x][j];
}
return pr[x][0];
}
};
int main() {
int n; cin >> n;
lca_forest<long long> g(n);
for(int i = 1; i < n; i++) {
int u, v, w; cin >> u >> v >> w;
g.add(u, v, w);
}
g.dfs_all();
g.build_lca();
int q; cin >> q;
while(q--) {
int K; cin >> K;
vector<int> vs;
for(int i = 0; i < K; i++) {
int u; cin >> u;
vs.push_back(u);
}
sort(begin(vs), end(vs), [&](int u, int v) -> bool {
return g.pos[u] < g.pos[v];
});
vs.push_back(vs[0]);
long long ans = 0;
for(int i = 0; i < K; i++) {
ans += g.dist[vs[i]] + g.dist[vs[i + 1]] - 2 * g.dist[g.lca(vs[i], vs[i + 1])];
}
cout << ans/2 << endl;
}
}