結果
問題 | No.2874 Gunegune Tree |
ユーザー | 👑 binap |
提出日時 | 2024-09-06 22:02:33 |
言語 | C++17 (gcc 12.3.0 + boost 1.83.0) |
結果 |
AC
|
実行時間 | 226 ms / 2,000 ms |
コード長 | 2,650 bytes |
コンパイル時間 | 4,335 ms |
コンパイル使用メモリ | 265,580 KB |
実行使用メモリ | 6,944 KB |
最終ジャッジ日時 | 2024-09-06 22:02:45 |
合計ジャッジ時間 | 7,707 ms |
ジャッジサーバーID (参考情報) |
judge1 / judge4 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 2 ms
6,816 KB |
testcase_01 | AC | 2 ms
6,940 KB |
testcase_02 | AC | 2 ms
6,944 KB |
testcase_03 | AC | 19 ms
6,944 KB |
testcase_04 | AC | 99 ms
6,940 KB |
testcase_05 | AC | 35 ms
6,940 KB |
testcase_06 | AC | 3 ms
6,944 KB |
testcase_07 | AC | 216 ms
6,944 KB |
testcase_08 | AC | 104 ms
6,944 KB |
testcase_09 | AC | 10 ms
6,944 KB |
testcase_10 | AC | 179 ms
6,944 KB |
testcase_11 | AC | 143 ms
6,944 KB |
testcase_12 | AC | 46 ms
6,940 KB |
testcase_13 | AC | 211 ms
6,940 KB |
testcase_14 | AC | 169 ms
6,940 KB |
testcase_15 | AC | 30 ms
6,940 KB |
testcase_16 | AC | 217 ms
6,940 KB |
testcase_17 | AC | 26 ms
6,940 KB |
testcase_18 | AC | 27 ms
6,940 KB |
testcase_19 | AC | 20 ms
6,940 KB |
testcase_20 | AC | 27 ms
6,940 KB |
testcase_21 | AC | 72 ms
6,940 KB |
testcase_22 | AC | 108 ms
6,940 KB |
testcase_23 | AC | 69 ms
6,944 KB |
testcase_24 | AC | 92 ms
6,940 KB |
testcase_25 | AC | 159 ms
6,940 KB |
testcase_26 | AC | 92 ms
6,944 KB |
testcase_27 | AC | 213 ms
6,944 KB |
testcase_28 | AC | 51 ms
6,940 KB |
testcase_29 | AC | 127 ms
6,940 KB |
testcase_30 | AC | 100 ms
6,940 KB |
testcase_31 | AC | 78 ms
6,944 KB |
testcase_32 | AC | 226 ms
6,944 KB |
ソースコード
#include<bits/stdc++.h> #include<atcoder/all> #define rep(i,n) for(int i=0;i<n;i++) using namespace std; using namespace atcoder; typedef long long ll; typedef vector<int> vi; typedef vector<long long> vl; typedef vector<vector<int>> vvi; typedef vector<vector<long long>> vvl; typedef long double ld; typedef pair<int, int> P; ostream& operator<<(ostream& os, const modint& a) {os << a.val(); return os;} template <int m> ostream& operator<<(ostream& os, const static_modint<m>& a) {os << a.val(); return os;} template <int m> ostream& operator<<(ostream& os, const dynamic_modint<m>& a) {os << a.val(); return os;} template<typename T> istream& operator>>(istream& is, vector<T>& v){int n = v.size(); assert(n > 0); rep(i, n) is >> v[i]; return is;} template<typename U, typename T> ostream& operator<<(ostream& os, const pair<U, T>& p){os << p.first << ' ' << p.second; return os;} template<typename T> ostream& operator<<(ostream& os, const vector<T>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : " "); return os;} template<typename T> ostream& operator<<(ostream& os, const vector<vector<T>>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : ""); return os;} template<typename T> ostream& operator<<(ostream& os, const set<T>& se){for(T x : se) os << x << " "; os << "\n"; return os;} template<typename T> ostream& operator<<(ostream& os, const unordered_set<T>& se){for(T x : se) os << x << " "; os << "\n"; return os;} template<typename S, auto op, auto e> ostream& operator<<(ostream& os, const atcoder::segtree<S, op, e>& seg){int n = seg.max_right(0, [](S){return true;}); rep(i, n) os << seg.get(i) << (i == n - 1 ? "\n" : " "); return os;} template<typename S, auto op, auto e, typename F, auto mapping, auto composition, auto id> ostream& operator<<(ostream& os, const atcoder::lazy_segtree<S, op, e, F, mapping, composition, id>& seg){int n = seg.max_right(0, [](S){return true;}); rep(i, n) os << seg.get(i) << (i == n - 1 ? "\n" : " "); return os;} template<typename T> void chmin(T& a, T b){a = min(a, b);} template<typename T> void chmax(T& a, T b){a = max(a, b);} using mint = modint998244353; int main(){ int n; cin >> n; vector<mint> dp(5); mint ans = mint(3) / 5; rep(i, 5) dp[i] = mint(1) / 5; rep(i, n - 1){ vector<mint> dp_old(5); swap(dp, dp_old); rep(from, 5){ vector<int> cand; for(int to = max(from - 1, 0); to <= min(from + 1, 4); to++){ cand.push_back(to); } mint p = mint(1) / cand.size(); for(int to : cand){ if(to >= 1 and to <= 3) ans += dp_old[from] * p; dp[to] += dp_old[from] * p; } } } cout << ans << "\n"; return 0; }