結果

問題 No.2875 What is My Rank?
ユーザー 👑 binap
提出日時 2024-09-06 22:32:00
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 252 ms / 2,000 ms
コード長 2,755 bytes
コンパイル時間 3,987 ms
コンパイル使用メモリ 251,388 KB
最終ジャッジ日時 2025-02-24 04:35:47
ジャッジサーバーID
（参考情報） 		judge4 / judge5
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 32
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include<bits/stdc++.h>
#include<atcoder/all>
#define rep(i,n) for(int i=0;i<n;i++)
using namespace std;
using namespace atcoder;
typedef long long ll;
typedef vector<int> vi;
typedef vector<long long> vl;
typedef vector<vector<int>> vvi;
typedef vector<vector<long long>> vvl;
typedef long double ld;
typedef pair<int, int> P;
ostream& operator<<(ostream& os, const modint& a) {os << a.val(); return os;}
template <int m> ostream& operator<<(ostream& os, const static_modint<m>& a) {os << a.val(); return os;}
template <int m> ostream& operator<<(ostream& os, const dynamic_modint<m>& a) {os << a.val(); return os;}
template<typename T> istream& operator>>(istream& is, vector<T>& v){int n = v.size(); assert(n > 0); rep(i, n) is >> v[i]; return is;}
template<typename U, typename T> ostream& operator<<(ostream& os, const pair<U, T>& p){os << p.first << ' ' << p.second; return os;}
template<typename T> ostream& operator<<(ostream& os, const vector<T>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : " "); return 
    os;}
template<typename T> ostream& operator<<(ostream& os, const vector<vector<T>>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : ""); 
    return os;}
template<typename T> ostream& operator<<(ostream& os, const set<T>& se){for(T x : se) os << x << " "; os << "\n"; return os;}
template<typename T> ostream& operator<<(ostream& os, const unordered_set<T>& se){for(T x : se) os << x << " "; os << "\n"; return os;}
template<typename S, auto op, auto e> ostream& operator<<(ostream& os, const atcoder::segtree<S, op, e>& seg){int n = seg.max_right(0, [](S){return 
    true;}); rep(i, n) os << seg.get(i) << (i == n - 1 ? "\n" : " "); return os;}
template<typename S, auto op, auto e, typename F, auto mapping, auto composition, auto id> ostream& operator<<(ostream& os, const atcoder
    ::lazy_segtree<S, op, e, F, mapping, composition, id>& seg){int n = seg.max_right(0, [](S){return true;}); rep(i, n) os << seg.get(i) << (i == n - 
    1 ? "\n" : " "); return os;}
template<typename T> void chmin(T& a, T b){a = min(a, b);}
template<typename T> void chmax(T& a, T b){a = max(a, b);}
using mint = modint998244353;
int main(){
    int n;
    cin >> n;
    vector<int> l(n);
    vector<int> r(n);
    rep(i, n) cin >> l[i] >> r[i];
    vector<int> d(n);
    rep(i, n) d[i] = r[i] - l[i] + 1;
    auto f = [&](int i, int x) -> mint{
        if(x < l[i]) return mint(0);
        else if(x < r[i]){
            mint width = x - l[i] + 1;
            return width * (width + 1) / 2 / d[i];
        }
        {
            mint width = x - r[i];
            return mint(d[i] + 1) / 2 + width;
        }
    };
    mint ans = 1;
    for(int i = 1; i < n; i++){
        mint prob = 0;
        prob += f(i, r[0]);
        prob -= f(i, l[0] - 1);
        ans += mint(1) - prob / d[0];
//      cout << prob << "\n";
    }
    cout << ans << "\n";
    return 0;
}
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