結果
| 問題 |
No.2874 Gunegune Tree
|
| コンテスト | |
| ユーザー |
amentorimaru
|
| 提出日時 | 2024-09-06 22:41:17 |
| 言語 | C++23 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
AC
|
| 実行時間 | 44 ms / 2,000 ms |
| コード長 | 4,780 bytes |
| コンパイル時間 | 4,226 ms |
| コンパイル使用メモリ | 234,476 KB |
| 実行使用メモリ | 25,060 KB |
| 最終ジャッジ日時 | 2024-09-06 22:41:31 |
| 合計ジャッジ時間 | 5,788 ms |
|
ジャッジサーバーID (参考情報) |
judge5 / judge2 |
(要ログイン)
| ファイルパターン | 結果 |
|---|---|
| sample | AC * 3 |
| other | AC * 30 |
ソースコード
#define ATCODER
#define _USE_MATH_DEFINES
#include<stdio.h>
#include<iostream>
#include<fstream>
#include<algorithm>
#include<vector>
#include<string>
#include <cassert>
#include <numeric>
#include <unordered_map>
#include <unordered_set>
#include <queue>
#include <math.h>
#include <climits>
#include <set>
#include <map>
#include <list>
#include <random>
#include <iterator>
#include <bitset>
#include <chrono>
#include <type_traits>
using namespace std;
using ll = long long;
using ld = long double;
using pll = pair<ll, ll>;
using pdd = pair<ld, ld>;
//template<claLR T> using pq = priority_queue<T, vector<T>, greater<T>>;
#define FOR(i, a, b) for(ll i=(a); i<(b);i++)
#define REP(i, n) for(ll i=0; i<(n);i++)
#define ROF(i, a, b) for(ll i=(b-1); i>=(a);i--)
#define PER(i, n) for(ll i=n-1; i>=0;i--)
#define REPREP(i,j,a,b) for(ll i=0;i<a;i++)for(ll j=0;j<b;j++)
#define VV(type) vector< vector<type> >
#define VV2(type,n,m,val) vector< vector<type> > val;val.resize(n);for(ll i;i<n;i++)val[i].resize(m)
#define vec(type) vector<type>
#define VEC(type,n,val) vector<type> val;val.resize(n)
#define VL vector<ll>
#define VVL vector< vector<ll> >
#define VP vector< pair<ll,ll> >
#define SZ size()
#define all(i) begin(i),end(i)
#define SORT(i) sort(all(i))
#define BITI(i) (1<<i)
#define BITSET(x,i) x | (ll(1)<<i)
#define BITCUT(x,i) x & ~(ll(1)<<i)
#define EXISTBIT(x,i) (((x>>i) & 1) != 0)
#define ALLBIT(n) (ll(1)<<n-1)
#define CHMAX(n,v) n=n<v?v:n
#define CHMIN(n,v) n=n>v?v:n
#define MP(a,b) make_pair(a,b)
#define DET2(x1,y1,x2,y2) (x1)*(y2)-(x2)*(y1)
#define DET3(x1,y1,z1,x2,y2,z2,x3,y3,z3) (x1)*(y2)*(z3)+(x2)*(y3)*(z1)+(x3)*(y1)*(z2)-(z1)*(y2)*(x3)-(z2)*(y3)*(x1)-(z3)*(y1)*(x2)
#define INC(a) for(auto& v:a)v++;
#define DEC(a) for(auto& v:a)v--;
#define SQU(x) (x)*(x)
#define L0 ll(0)
#ifdef ATCODER
#include <atcoder/all>
using namespace atcoder;
using mint = modint1000000007;
using mint2 = modint998244353;
#endif
template<typename T = ll>
vector<T> read(size_t n) {
vector<T> ts(n);
for (size_t i = 0; i < n; i++) cin >> ts[i];
return ts;
}
template<typename TV, const ll N> void read_tuple_impl(TV&) {}
template<typename TV, const ll N, typename Head, typename... Tail>
void read_tuple_impl(TV& ts) {
get<N>(ts).emplace_back(*(istream_iterator<Head>(cin)));
read_tuple_impl<TV, N + 1, Tail...>(ts);
}
template<typename... Ts> decltype(auto) read_tuple(size_t n) {
tuple<vector<Ts>...> ts;
for (size_t i = 0; i < n; i++) read_tuple_impl<decltype(ts), 0, Ts...>(ts);
return ts;
}
using val = ll;
using func = pair<ll, ll>;
val opm(val a, val b) {
return min(a, b);
}
val em() { return 1e18; }
val opM(val a, val b) {
return max(a, b);
}
val eM() { return 0; }
//val mp(func f, val a)
//{
// if (f.first < 0)
// return a;
// return f;
//}
//func comp(func f, func g) {
// if (g.first < 0)
// return f;
// return g;
//}
//
//func id() {
// return MP(-1, -1);
//}
ll di[4] = { 1,0,-1,0 };
ll dj[4] = { 0,1,0,-1 };
ll si[4] = { 0,3,3,0 };
ll sj[4] = { 0,0,3,3 };
//ll di[4] = { -1,-1,1,1 };
//ll dj[4] = { -1,1,-1,1 };
ll di8[8] = { 0,-1,-1,-1,0,1,1,1 };
ll dj8[8] = { -1,-1,0,1,1,1,0,-1 };
void solve() {
ll n;
cin >> n;
mint2 inv2 = mint2(2).inv();
mint2 inv3 = mint2(3).inv();
mint2 inv5 = mint2(5).inv();
//double inv2 = 1.0 / 2;
//double inv3 = 1.0 / 3;
//double inv5 = 1.0 / 5;
//vector tdp(n, vector(n + 1, vector<mint2>(5)));
//tdp[0][0][0] = mint2(5).inv();
//tdp[0][1][1] = mint2(5).inv();
//tdp[0][1][2] = mint2(5).inv();
//tdp[0][1][3] = mint2(5).inv();
//tdp[0][0][4] = mint2(5).inv();
//REP(i, n - 1) {
// REP(j, n) {
// REP(k, 5) {
// REP(k2, 5) {
// if (abs(k - k2) > 1)
// continue;
// ll nj = k2 == 0 || k2 == 4 ? j : j + 1;
// mint2 in = k == 0 || k == 4 ? inv2 : inv3;
// tdp[i + 1][nj][k2] += tdp[i][j][k] * in;
// }
// }
// }
//}
//mint2 tans = 0;
//REP(i, n + 1) {
// REP(j, 5) {
// tans += tdp[n - 1][i][j] * i;
// }
//}
//cout << tans.val();
//return;
vector dp(n, vector<mint2>(5));
auto dp2 = dp;
dp[0][1] = inv5;
dp[0][2] = inv5;
dp[0][3] = inv5;
REP(i, 5)
dp2[0][i] = inv5;
REP(i, n - 1) {
REP(j, 5) {
REP(k, 3) {
ll j2 = j + k - 1;
if (j2 < 0 || j2 >= 5)
continue;
auto mul = j == 0 || j == 4 ? inv2 : inv3;
dp[i + 1][j2] += dp[i][j] * mul;
dp2[i + 1][j2] += dp2[i][j] * mul;
}
}
FOR(j, 1, 4) {
dp[i + 1][j] += dp2[i + 1][j];
}
}
mint2 sum = 0, sum2 = 0;;
REP(i, 5) {
sum += dp[n - 1][i];
sum2 += dp2[n - 1][i];
}
cout << sum.val();
return;
}
int main() {
ll t = 1;
//cin >> t;
while (t--) {
solve();
}
return 0;
}
amentorimaru