結果

問題 No.2882 Comeback
ユーザー dyktr_06dyktr_06
提出日時 2024-09-08 15:42:09
言語 C++17
(gcc 12.3.0 + boost 1.83.0)
結果
AC  
実行時間 156 ms / 2,000 ms
コード長 5,311 bytes
コンパイル時間 2,428 ms
コンパイル使用メモリ 212,868 KB
実行使用メモリ 7,780 KB
最終ジャッジ日時 2024-09-08 15:42:15
合計ジャッジ時間 4,998 ms
ジャッジサーバーID
（参考情報） 		judge3 / judge4
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 2 ms
6,816 KB
testcase_01 AC 1 ms
6,944 KB
testcase_02 AC 2 ms
6,944 KB
testcase_03 AC 2 ms
6,944 KB
testcase_04 AC 2 ms
6,944 KB
testcase_05 AC 5 ms
6,940 KB
testcase_06 AC 5 ms
6,940 KB
testcase_07 AC 5 ms
6,944 KB
testcase_08 AC 5 ms
6,940 KB
testcase_09 AC 5 ms
6,940 KB
testcase_10 AC 102 ms
7,388 KB
testcase_11 AC 89 ms
7,136 KB
testcase_12 AC 113 ms
7,648 KB
testcase_13 AC 122 ms
7,780 KB
testcase_14 AC 86 ms
7,264 KB
testcase_15 AC 118 ms
7,516 KB
testcase_16 AC 96 ms
7,392 KB
testcase_17 AC 96 ms
6,944 KB
testcase_18 AC 127 ms
7,396 KB
testcase_19 AC 110 ms
7,392 KB
testcase_20 AC 150 ms
7,776 KB
testcase_21 AC 146 ms
7,776 KB
testcase_22 AC 150 ms
7,776 KB
testcase_23 AC 156 ms
7,776 KB
testcase_24 AC 150 ms
7,648 KB
testcase_25 AC 2 ms
6,940 KB
testcase_26 AC 2 ms
6,940 KB
testcase_27 AC 2 ms
6,944 KB
testcase_28 AC 2 ms
6,944 KB
testcase_29 AC 2 ms
6,940 KB
testcase_30 AC 15 ms
6,940 KB
権限があれば一括ダウンロードができます

ソースコード

diff # 

#include <bits/stdc++.h>

using namespace std;

#define overload4(_1, _2, _3, _4, name, ...) name
#define rep1(n) for(int i = 0; i < (int)(n); ++i)
#define rep2(i, n) for(int i = 0; i < (int)(n); ++i)
#define rep3(i, a, b) for(int i = (a); i < (int)(b); ++i)
#define rep4(i, a, b, c) for(int i = (a); i < (int)(b); i += (c))
#define rep(...) overload4(__VA_ARGS__, rep4, rep3, rep2, rep1)(__VA_ARGS__)

#define rrep(i,n) for(int i = (int)(n) - 1; i >= 0; --i)
#define ALL(a) (a).begin(), (a).end()
#define Sort(a) (sort((a).begin(), (a).end()))
#define RSort(a) (sort((a).rbegin(), (a).rend()))
#define UNIQUE(a) (a.erase(unique((a).begin(), (a).end()), (a).end()))

typedef long long int ll;
typedef unsigned long long ul;
typedef long double ld;
typedef vector<int> vi;
typedef vector<long long> vll;
typedef vector<char> vc;
typedef vector<string> vst;
typedef vector<double> vd;
typedef vector<long double> vld;
typedef pair<long long, long long> P;

template<class T> long long sum(const T& a){ return accumulate(a.begin(), a.end(), 0LL); }
template<class T> auto min(const T& a){ return *min_element(a.begin(), a.end()); }
template<class T> auto max(const T& a){ return *max_element(a.begin(), a.end()); }

const long long MINF = 0x7fffffffffff;
const long long INF = 0x1fffffffffffffff;
const long long MOD = 998244353;
const long double EPS = 1e-9;
const long double PI = acos(-1);

template<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }
template<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }

template<typename T1, typename T2> istream &operator>>(istream &is, pair<T1, T2> &p){ is >> p.first >> p.second; return is; }
template<typename T1, typename T2> ostream &operator<<(ostream &os, const pair<T1, T2> &p){ os << "(" << p.first << ", " << p.second << ")"; return os; }
template<typename T> istream &operator>>(istream &is, vector<T> &v){ for(T &in : v) is >> in; return is; }
template<typename T> ostream &operator<<(ostream &os, const vector<T> &v){ for(int i = 0; i < (int) v.size(); ++i){ os << v[i] << (i + 1 != (int) v.size() ? " " : ""); } return os; }
template <typename T, typename S> ostream &operator<<(ostream &os, const map<T, S> &mp){ for(auto &[key, val] : mp){ os << key << ":" << val << " "; } return os; }
template <typename T> ostream &operator<<(ostream &os, const set<T> &st){ auto itr = st.begin(); for(int i = 0; i < (int)st.size(); ++i){ os << *itr << (i + 1 != (int)st.size() ? " " : ""); itr++; } return os; }
template <typename T> ostream &operator<<(ostream &os, const multiset<T> &st){ auto itr = st.begin(); for(int i = 0; i < (int)st.size(); ++i){ os << *itr << (i + 1 != (int)st.size() ? " " : ""); itr++; } return os; }
template <typename T> ostream &operator<<(ostream &os, queue<T> q){ while(q.size()){ os << q.front() << " "; q.pop(); } return os; }
template <typename T> ostream &operator<<(ostream &os, deque<T> q){ while(q.size()){ os << q.front() << " "; q.pop_front(); } return os; }
template <typename T> ostream &operator<<(ostream &os, stack<T> st){ while(st.size()){ os << st.top() << " "; st.pop(); } return os; }
template <class T, class Container, class Compare> ostream &operator<<(ostream &os, priority_queue<T, Container, Compare> pq){ while(pq.size()){ os << pq.top() << " "; pq.pop(); } return os; }

template<class T, class U> inline T vin(T& vec, U n) { vec.resize(n); for(int i = 0; i < (int) n; ++i) cin >> vec[i]; return vec; }
template<class T> inline void vout(T vec, string s = "\n"){ for(auto x : vec) cout << x << s; }
template<class... T> void in(T&... a){ (cin >> ... >> a); }
void out(){ cout << '\n'; }
template<class T, class... Ts> void out(const T& a, const Ts&... b){ cout << a; (cout << ... << (cout << ' ', b)); cout << '\n'; }
template<class T, class U> void inGraph(vector<vector<T>>& G, U n, U m, bool directed = false){ G.resize(n); for(int i = 0; i < m; ++i){ int a, b; cin >> a >> b; a--, b--; G[a].push_back(b); if(!directed) G[b].push_back(a); } }

template <typename T>
vector<tuple<T, T, T>> enumerate_quotients(const T &n){
    vector<tuple<T, T, T>> res;
    for(T l = 1; l <= n;){
        const T quotient = n / l;
        const T r = n / quotient + 1;

        // [l, r)
        res.emplace_back(l, r, quotient);
        l = r;
    }
    return res;
}

ll T;

void input(){
    in(T);
}

void solve(){
    ll a, b; in(a, b);
    using T = tuple<ll, ll, ll>;
    vector<T> ea = enumerate_quotients(a), eb = enumerate_quotients(b);
    ea.emplace_back(a + 1, b + 1, 0);
    ll ans = 0;
    for(auto [lb, rb, qb] : eb){
        auto iter = lower_bound(ALL(ea), T{lb + 1, 0, 0});
        if(iter != ea.begin()){
            iter--;
        }
        for(; iter != ea.end(); iter++){
            ll la, ra, qa;
            tie(la, ra, qa) = *iter;
            if(la > rb) break;
            ll l = max(la, lb), r = min(ra, rb);

            ll ok = r, ng = l - 1;
            while(abs(ok - ng) > 1){
                ll mid = (ok + ng) / 2;
                if(a % mid >= b % mid) ok = mid;
                else ng = mid;
            }
            ans += r - ok;
        }
    }
    out(ans);
}

int main(){
    ios::sync_with_stdio(false);
    cin.tie(nullptr);
    cout << fixed << setprecision(20);

    input();
    while(T--) solve();
}
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