結果
問題 | No.2294 Union Path Query (Easy) |
ユーザー | 草苺奶昔 |
提出日時 | 2024-09-12 03:29:24 |
言語 | Go (1.22.1) |
結果 |
WA
|
実行時間 | - |
コード長 | 11,212 bytes |
コンパイル時間 | 15,303 ms |
コンパイル使用メモリ | 222,860 KB |
実行使用メモリ | 6,948 KB |
最終ジャッジ日時 | 2024-09-12 03:29:47 |
合計ジャッジ時間 | 21,282 ms |
ジャッジサーバーID (参考情報) |
judge4 / judge2 |
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テストケース
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testcase_00 | WA | - |
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ソースコード
// Api: // - NewPotentializedUnionFind(n int32, e func() E, op func(E, E) E, inv func(E) E) *PotentializedUnionFind[E] // - (uf *PotentializedUnionFind[E]) Diff(a, b int32) (diff E, same bool) // !返回 P[a] - P[b] 以及是否在同一个集合中. // - (uf *PotentializedUnionFind[E]) Union(a, b int32, x E) bool // !合并a, b所在的集合, 并且满足 P[a] - P[b] = x. // - (uf *PotentializedUnionFind[E]) Find(v int32) (root int32, diff E) // !返回v所在集合的根节点, 以及 P[v] - P[root]. package main import ( "bufio" "fmt" "os" ) func main() { // dsl1B() // yuki1502() // yuki2294() demo() // abc280F() // yosupoUnionfindwithPotential() // yosupoUnionfindwithPotentialNonCommutativeGroup() } func demo() { // e, op, inv := func() int32 { return 0 }, func(a, b int32) int32 { return a + b }, func(a int32) int32 { return -a } e := func() int { return 0 } op := func(a, b int) int { return a ^ b } inv := func(a int) int { return a } uf := NewPotentializedUnionFind(10, e, op, inv) uf.Union(2, 1, 10) fmt.Println(uf.Find(0)) fmt.Println(uf.Find(1)) fmt.Println(uf.Find(2)) fmt.Println(uf.Diff(2, 1)) fmt.Println(uf.Diff(1, 2)) fmt.Println(uf.Find(3)) } // https://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=DSL_1_B // relate(x,y,z): A[y] = A[x] + z // diff(x,y): A[y] - A[x] func dsl1B() { in := bufio.NewReader(os.Stdin) out := bufio.NewWriter(os.Stdout) defer out.Flush() var n, q int32 fmt.Fscan(in, &n, &q) e := func() int { return 0 } op := func(a, b int) int { return a + b } inv := func(a int) int { return -a } uf := NewPotentializedUnionFind(n, e, op, inv) relate := func(x, y int32, z int) { uf.Union(y, x, z) } diff := func(x, y int32) (int, bool) { return uf.Diff(y, x) } for i := int32(0); i < q; i++ { var op int32 fmt.Fscan(in, &op) if op == 0 { var x, y int32 var z int fmt.Fscan(in, &x, &y, &z) relate(x, y, z) } else { var x, y int32 fmt.Fscan(in, &x, &y) res, same := diff(x, y) if same { fmt.Fprintln(out, res) } else { fmt.Fprintln(out, "?") } } } } // No.1502 Many Simple Additions // https://yukicoder.me/problems/no/1502 func yuki1502() { } // No.2294 Union Path Query (Easy,异或和距离,所有点对的异或和) // https://yukicoder.me/problems/no/2294 // 给定一张n个点的无向带权图.两点间的距离为异或和. // 给定一个初始点X0. // 给定q个查询,每个查询形如: // 1 v w: 将顶点v与顶点X0用一条边权为w的边连接.保证连接后的图中没有环. // 2 u v: 输出顶点u到顶点v的距离.如果无法到达,输出-1. // 3 v: 求v所在联通分量的所有点对距离异或和模998244353. // 4 add: 将X0增加add,然后对N取模. // N<=2e5.w<=1e9.q<=2e5. func yuki2294() { in := bufio.NewReader(os.Stdin) out := bufio.NewWriter(os.Stdout) defer out.Flush() const MOD int = 998244353 var N, X, Q int32 fmt.Fscan(in, &N, &X, &Q) const LOG int = 30 type V = [LOG][2]int // 每一位染黑/白 data := make([]V, N) for i := int32(0); i < N; i++ { for j := 0; j < LOG; j++ { data[i][j][0] = 1 data[i][j][1] = 0 } } // MonoidXor e := func() int { return 0 } op := func(a, b int) int { return a ^ b } inv := func(a int) int { return a } uf := NewPotentializedUnionFind(N, e, op, inv) link := func(a, b int32, w int) { ra, da := uf.Find(a) rb, db := uf.Find(b) if ra == rb { return } nd := da ^ db ^ w uf.Union2(a, b, w, func(big, small int32) { for i := 0; i < LOG; i++ { if (nd>>i)&1 == 1 { data[big][i][0] += data[small][i][1] data[big][i][1] += data[small][i][0] } else { data[big][i][0] += data[small][i][0] data[big][i][1] += data[small][i][1] } } }) } dist := func(a, b int32) (int, bool) { return uf.Diff(a, b) } pairDist := func(a int32) int { root, _ := uf.Find(a) res := 0 for i := 0; i < LOG; i++ { a, b := data[root][i][0], data[root][i][1] pair := a * b % MOD res += (1 << i) % MOD * pair % MOD res %= MOD } return res } for i := int32(0); i < Q; i++ { var op int32 fmt.Fscan(in, &op) if op == 1 { var u int32 var w int fmt.Fscan(in, &u, &w) link(u, X, w) } else if op == 2 { var u, v int32 fmt.Fscan(in, &u, &v) d, ok := dist(u, v) if !ok { fmt.Fprintln(out, -1) } else { fmt.Fprintln(out, d) X = int32((int(X) + d) % int(N)) } } else if op == 3 { var v int32 fmt.Fscan(in, &v) fmt.Fprintln(out, pairDist(v)) } else { var add int fmt.Fscan(in, &add) X = int32((int(X) + add) % int(N)) } } } // F - Pay or Receive (爬山,势能模型) // https://atcoder.jp/contests/abc280/tasks/abc280_f // 给定n个点和m条无向边. // 对每条边,从a->b, 可以获得c的收益,从b->a, 会获得-c的收益. // 给定q个查询,每个查询形如a->b. // 问从 a->b 可以获得的最大收益. // 如果无法到达,输出nan. // 如果可以获得无限收益,输出inf. // // 初始对每条边: // 如果不连通 -> 连通并附加约束 // 如果连通 -> 检查约束是否满足,不满足则在正环上 func abc280F() { in := bufio.NewReader(os.Stdin) out := bufio.NewWriter(os.Stdout) defer out.Flush() var n, m, q int32 fmt.Fscan(in, &n, &m, &q) e := func() int { return 0 } op := func(a, b int) int { return a + b } inv := func(a int) int { return -a } uf := NewPotentializedUnionFind(n, e, op, inv) inPosCycle := make([]bool, n) for i := int32(0); i < m; i++ { var a, b int32 var c int fmt.Fscan(in, &a, &b, &c) a, b = a-1, b-1 diff, same := uf.Diff(b, a) if !same { uf.Union(b, a, c) // P[b] - P[a] = c continue } if diff != c { inPosCycle[a] = true inPosCycle[b] = true } } // !transfer for i := int32(0); i < n; i++ { if inPosCycle[i] { root, _ := uf.Find(i) inPosCycle[root] = true } } for i := int32(0); i < q; i++ { var a, b int32 fmt.Fscan(in, &a, &b) a, b = a-1, b-1 diff, same := uf.Diff(b, a) if !same { fmt.Fprintln(out, "nan") } else { root, _ := uf.Find(a) if inPosCycle[root] { fmt.Fprintln(out, "inf") } else { fmt.Fprintln(out, diff) } } } } // UnionfindwithPotential // https://judge.yosupoUnionfindwithPotential.jp/problem/unionfind_with_potential // 0 u v x: 判断A[u]=A[v]+x(mod Mod)是否成立. 如果与现有信息矛盾,则不进行任何操作,否则将该条件加入. // 1 u v: 输出A[u]-A[v].如果不能确定,输出-1. func yosupoUnionfindwithPotential() { in := bufio.NewReader(os.Stdin) out := bufio.NewWriter(os.Stdout) defer out.Flush() const MOD int = 998244353 var n, q int32 fmt.Fscan(in, &n, &q) e := func() int { return 0 } op := func(a, b int) int { res := (a + b) % MOD if res < 0 { res += MOD } return res } inv := func(a int) int { res := -a % MOD if res < 0 { res += MOD } return res } uf := NewPotentializedUnionFind(n, e, op, inv) for i := int32(0); i < q; i++ { var op int32 fmt.Fscan(in, &op) if op == 0 { var u, v int32 var x int fmt.Fscan(in, &u, &v, &x) diff, same := uf.Diff(u, v) valid := !same || diff == x if valid { fmt.Fprintln(out, 1) } else { fmt.Fprintln(out, 0) } if !same { uf.Union(u, v, x) } } else { var u, v int32 fmt.Fscan(in, &u, &v) if diff, ok := uf.Diff(u, v); ok { fmt.Fprintln(out, diff) } else { fmt.Fprintln(out, -1) } } } } // 不可交换群. // https://judge.yosupo.jp/problem/unionfind_with_potential_non_commutative_group func yosupoUnionfindwithPotentialNonCommutativeGroup() { in := bufio.NewReader(os.Stdin) out := bufio.NewWriter(os.Stdout) defer out.Flush() const MOD int = 998244353 var n, q int32 fmt.Fscan(in, &n, &q) type E = [2][2]int // 群为矩阵乘法,不可交换. e := func() E { return E{{1, 0}, {0, 1}} } op := func(a, b E) E { v00 := a[0][0]*b[0][0] + a[0][1]*b[1][0] v01 := a[0][0]*b[0][1] + a[0][1]*b[1][1] v10 := a[1][0]*b[0][0] + a[1][1]*b[1][0] v11 := a[1][0]*b[0][1] + a[1][1]*b[1][1] v00, v01, v10, v11 = v00%MOD, v01%MOD, v10%MOD, v11%MOD return E{{v00, v01}, {v10, v11}} } inv := func(a E) E { v00, v01, v10, v11 := a[0][0], a[0][1], a[1][0], a[1][1] v00, v01, v10, v11 = v11, -v01, -v10, v00 if v01 < 0 { v01 += MOD } if v10 < 0 { v10 += MOD } return E{{v00, v01}, {v10, v11}} } uf := NewPotentializedUnionFind(n, e, op, inv) for i := int32(0); i < q; i++ { var op int32 fmt.Fscan(in, &op) if op == 0 { var u, v int32 var v00, v01, v10, v11 int fmt.Fscan(in, &u, &v, &v00, &v01, &v10, &v11) x := E{{v00, v01}, {v10, v11}} diff, same := uf.Diff(u, v) // !注意非交换性 P[u] = P[v] * x valid := !same || diff == x if valid { fmt.Fprintln(out, 1) } else { fmt.Fprintln(out, 0) } if !same { uf.Union(u, v, x) } } else { var u, v int32 fmt.Fscan(in, &u, &v) if diff, ok := uf.Diff(u, v); ok { v00, v01, v10, v11 := diff[0][0], diff[0][1], diff[1][0], diff[1][1] fmt.Fprintln(out, v00, v01, v10, v11) } else { fmt.Fprintln(out, -1) } } } } // 势能并查集/距离并查集. type PotentializedUnionFind[E any] struct { n, Part int32 parents []int32 sizes []int32 values []E e func() E op func(E, E) E inv func(E) E } func NewPotentializedUnionFind[E any](n int32, e func() E, op func(E, E) E, inv func(E) E) *PotentializedUnionFind[E] { values, parents, sizes := make([]E, n), make([]int32, n), make([]int32, n) for i := int32(0); i < n; i++ { parents[i] = i sizes[i] = 1 values[i] = e() } return &PotentializedUnionFind[E]{n: n, Part: n, parents: parents, sizes: sizes, values: values, e: e, op: op, inv: inv} } // P[a] - P[b] = x func (uf *PotentializedUnionFind[E]) Union(a, b int32, x E) bool { v1, x1 := uf.Find(b) v2, x2 := uf.Find(a) if v1 == v2 { return false } if uf.sizes[v1] < uf.sizes[v2] { v1, v2 = v2, v1 x1, x2 = x2, x1 x = uf.inv(x) } x = uf.op(x1, x) x = uf.op(x, uf.inv(x2)) uf.values[v2] = x uf.parents[v2] = v1 uf.sizes[v1] += uf.sizes[v2] uf.Part-- return true } // 返回根节点root, 以及 diff = P[v] - P[root] func (uf *PotentializedUnionFind[E]) Find(v int32) (root int32, diff E) { diff = uf.e() vs, ps := uf.values, uf.parents for v != ps[v] { diff = uf.op(vs[v], diff) diff = uf.op(vs[ps[v]], diff) vs[v] = uf.op(vs[ps[v]], vs[v]) ps[v] = ps[ps[v]] v = ps[v] } root = v return } // Diff(a, b) = P[a] - P[b] func (uf *PotentializedUnionFind[E]) Diff(a, b int32) (E, bool) { ru, xu := uf.Find(b) rv, xv := uf.Find(a) if ru != rv { return uf.e(), false } return uf.op(uf.inv(xu), xv), true } // P[a] - P[b] = x func (uf *PotentializedUnionFind[E]) Union2(a, b int32, x E, beforeUnion func(big, small int32)) bool { v1, x1 := uf.Find(b) v2, x2 := uf.Find(a) if v1 == v2 { return false } if uf.sizes[v1] < uf.sizes[v2] { v1, v2 = v2, v1 x1, x2 = x2, x1 x = uf.inv(x) } if beforeUnion != nil { beforeUnion(v1, v2) } x = uf.op(x1, x) x = uf.op(x, uf.inv(x2)) uf.values[v2] = x uf.parents[v2] = v1 uf.sizes[v1] += uf.sizes[v2] uf.Part-- return true }