結果

問題 No.2888 Mamehinata
ユーザー 👑 binap
提出日時 2024-09-13 21:34:23
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
WA  
実行時間 -
コード長 4,301 bytes
コンパイル時間 4,727 ms
コンパイル使用メモリ 271,768 KB
最終ジャッジ日時 2025-02-24 07:14:18
ジャッジサーバーID
（参考情報） 		judge5 / judge4
このコードへのチャレンジ
（要ログイン）
ファイルパターン 結果
sample AC * 3
other AC * 45 WA * 7
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include<bits/stdc++.h>
#include<atcoder/all>
#define rep(i,n) for(int i=0;i<n;i++)
using namespace std;
using namespace atcoder;
typedef long long ll;
typedef vector<int> vi;
typedef vector<long long> vl;
typedef vector<vector<int>> vvi;
typedef vector<vector<long long>> vvl;
typedef long double ld;
typedef pair<int, int> P;
ostream& operator<<(ostream& os, const modint& a) {os << a.val(); return os;}
template <int m> ostream& operator<<(ostream& os, const static_modint<m>& a) {os << a.val(); return os;}
template <int m> ostream& operator<<(ostream& os, const dynamic_modint<m>& a) {os << a.val(); return os;}
template<typename T> istream& operator>>(istream& is, vector<T>& v){int n = v.size(); assert(n > 0); rep(i, n) is >> v[i]; return is;}
template<typename U, typename T> ostream& operator<<(ostream& os, const pair<U, T>& p){os << p.first << ' ' << p.second; return os;}
template<typename T> ostream& operator<<(ostream& os, const vector<T>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : " "); return 
    os;}
template<typename T> ostream& operator<<(ostream& os, const vector<vector<T>>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : ""); 
    return os;}
template<typename T> ostream& operator<<(ostream& os, const set<T>& se){for(T x : se) os << x << " "; os << "\n"; return os;}
template<typename T> ostream& operator<<(ostream& os, const unordered_set<T>& se){for(T x : se) os << x << " "; os << "\n"; return os;}
template<typename S, auto op, auto e> ostream& operator<<(ostream& os, const atcoder::segtree<S, op, e>& seg){int n = seg.max_right(0, [](S){return 
    true;}); rep(i, n) os << seg.get(i) << (i == n - 1 ? "\n" : " "); return os;}
template<typename S, auto op, auto e, typename F, auto mapping, auto composition, auto id> ostream& operator<<(ostream& os, const atcoder
    ::lazy_segtree<S, op, e, F, mapping, composition, id>& seg){int n = seg.max_right(0, [](S){return true;}); rep(i, n) os << seg.get(i) << (i == n 
    - 1 ? "\n" : " "); return os;}
template<typename T> void chmin(T& a, T b){a = min(a, b);}
template<typename T> void chmax(T& a, T b){a = max(a, b);}
const long long INF = 1001001001001001;
using S = long long;
S _INF(INF);
S _ZERO(0LL);
using F = long long;
S apply(F f, S x){
    return f + x;
}
template<typename S, typename F>
struct Dijkstra{
    struct Edge{
        int from, to;
        F cost;
        Edge(int from, int to, F cost) : from(from), to(to), cost(cost) {};
    };
    int n, m;
    vector<bool> initialized;
    vector<Edge> E;
    vector<vector<int>> G;
    map<int, vector<S>> dist;
    map<int, vector<int>> idx;
    Dijkstra(int _n) : n(_n), m(0), initialized(n, false), G(n){}
    void add_edge(int from, int to, F cost){
        Edge e(from, to, cost);
        E.push_back(e);
        G[from].emplace_back(m);
        m++;
    }
    void calc(int s){
        initialized[s] = true;
        dist[s] = vector<S>(n, _INF);
        idx[s] = vector<int>(n, -1);
        priority_queue<tuple<S, int, int>, vector<tuple<S, int, int>>, greater<tuple<S, int, int>>> pq;
        pq.emplace(_ZERO, s, -1);
        while(pq.size()){
            auto [dist_from, from, index] = pq.top(); pq.pop();
            if(dist[s][from] <= dist_from) continue;
            dist[s][from] = dist_from;
            idx[s][from] = index;
            for(int index : G[from]){
                int to = E[index].to;
                S dist_to = apply(E[index].cost, dist_from);
                if(dist[s][to] <= dist_to) continue;
                pq.emplace(dist_to, to, index);
            }
        }
    }
    int farthest(int s){
        if(!initialized[s]) calc(s);
        int idx = 0;
        rep(i, n) if(dist[s][i] > dist[s][idx]) idx = i;
        return idx;
    }
    S get_dist(int s, int t){
        if(!initialized[s]) calc(s);
        return dist[s][t];
    }
    vector<int> restore(int s, int t){
        if(!initialized[s]) calc(s);
        if(dist[s][t] == _INF) return vector<int>(0);
        vector<int> res;
        while(idx[s][t] != -1){
            auto e = E[idx[s][t]];
            res.push_back(idx[s][t]);
            t = e.from;
        }
    reverse(res.begin(), res.end());
    return res;
    }
};
int main(){
    int n, m;
    cin >> n >> m;
    Dijkstra<long long, long long> graph(n);
    rep(i, m){
        int u, v;
        cin >> u >> v;
        u--; v--;
        graph.add_edge(u, v, 1);
        graph.add_edge(v, u, 1);
    }
    vector<long long> d(n, INF);
    rep(i, n) d[i] = graph.get_dist(0, i);
    vector<int> cnt(n + 1);
    rep(i, n){
        if(d[i] != INF) cnt[d[i]]++;
    }
    vector<int> p(2);
    rep(t, n + 1){
        p[t % 2] += cnt[t];
        if(t > 0) cout << p[t % 2] << "\n";
    }
    return 0;
}
הההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההה
XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX
0