結果

問題 No.2888 Mamehinata
ユーザー 👑 binapbinap
提出日時 2024-09-13 21:34:23
言語 C++17
(gcc 12.3.0 + boost 1.83.0)
結果
WA  
実行時間 -
コード長 4,301 bytes
コンパイル時間 5,353 ms
コンパイル使用メモリ 284,452 KB
実行使用メモリ 31,312 KB
最終ジャッジ日時 2024-09-13 21:34:42
合計ジャッジ時間 14,690 ms
ジャッジサーバーID
(参考情報)
judge3 / judge4
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 2 ms
5,248 KB
testcase_01 AC 2 ms
5,248 KB
testcase_02 AC 2 ms
5,248 KB
testcase_03 AC 2 ms
5,376 KB
testcase_04 WA -
testcase_05 AC 2 ms
5,376 KB
testcase_06 AC 2 ms
5,376 KB
testcase_07 AC 3 ms
5,376 KB
testcase_08 AC 2 ms
5,376 KB
testcase_09 AC 2 ms
5,376 KB
testcase_10 AC 2 ms
5,376 KB
testcase_11 WA -
testcase_12 AC 2 ms
5,376 KB
testcase_13 AC 86 ms
9,676 KB
testcase_14 AC 38 ms
9,640 KB
testcase_15 WA -
testcase_16 AC 246 ms
20,732 KB
testcase_17 WA -
testcase_18 AC 145 ms
14,040 KB
testcase_19 AC 277 ms
22,332 KB
testcase_20 AC 238 ms
19,444 KB
testcase_21 AC 236 ms
19,412 KB
testcase_22 WA -
testcase_23 WA -
testcase_24 AC 220 ms
21,680 KB
testcase_25 AC 150 ms
20,868 KB
testcase_26 AC 160 ms
20,348 KB
testcase_27 AC 71 ms
16,136 KB
testcase_28 AC 34 ms
6,312 KB
testcase_29 AC 99 ms
11,228 KB
testcase_30 AC 273 ms
22,480 KB
testcase_31 AC 224 ms
19,340 KB
testcase_32 AC 152 ms
14,604 KB
testcase_33 AC 215 ms
18,844 KB
testcase_34 AC 171 ms
15,876 KB
testcase_35 AC 142 ms
14,188 KB
testcase_36 AC 300 ms
24,328 KB
testcase_37 AC 312 ms
24,900 KB
testcase_38 AC 65 ms
9,408 KB
testcase_39 AC 237 ms
20,676 KB
testcase_40 AC 287 ms
24,396 KB
testcase_41 AC 38 ms
7,248 KB
testcase_42 AC 230 ms
21,332 KB
testcase_43 AC 208 ms
26,312 KB
testcase_44 AC 238 ms
28,524 KB
testcase_45 AC 263 ms
31,312 KB
testcase_46 AC 29 ms
6,884 KB
testcase_47 AC 233 ms
28,040 KB
testcase_48 AC 211 ms
21,324 KB
testcase_49 AC 39 ms
7,368 KB
testcase_50 AC 139 ms
17,792 KB
testcase_51 AC 7 ms
5,376 KB
testcase_52 AC 3 ms
5,376 KB
testcase_53 AC 20 ms
5,376 KB
testcase_54 WA -
権限があれば一括ダウンロードができます

ソースコード

diff #

#include<bits/stdc++.h>
#include<atcoder/all>
#define rep(i,n) for(int i=0;i<n;i++)
using namespace std;
using namespace atcoder;
typedef long long ll;
typedef vector<int> vi;
typedef vector<long long> vl;
typedef vector<vector<int>> vvi;
typedef vector<vector<long long>> vvl;
typedef long double ld;
typedef pair<int, int> P;

ostream& operator<<(ostream& os, const modint& a) {os << a.val(); return os;}
template <int m> ostream& operator<<(ostream& os, const static_modint<m>& a) {os << a.val(); return os;}
template <int m> ostream& operator<<(ostream& os, const dynamic_modint<m>& a) {os << a.val(); return os;}
template<typename T> istream& operator>>(istream& is, vector<T>& v){int n = v.size(); assert(n > 0); rep(i, n) is >> v[i]; return is;}
template<typename U, typename T> ostream& operator<<(ostream& os, const pair<U, T>& p){os << p.first << ' ' << p.second; return os;}
template<typename T> ostream& operator<<(ostream& os, const vector<T>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : " "); return os;}
template<typename T> ostream& operator<<(ostream& os, const vector<vector<T>>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : ""); return os;}
template<typename T> ostream& operator<<(ostream& os, const set<T>& se){for(T x : se) os << x << " "; os << "\n"; return os;}
template<typename T> ostream& operator<<(ostream& os, const unordered_set<T>& se){for(T x : se) os << x << " "; os << "\n"; return os;}
template<typename S, auto op, auto e> ostream& operator<<(ostream& os, const atcoder::segtree<S, op, e>& seg){int n = seg.max_right(0, [](S){return true;}); rep(i, n) os << seg.get(i) << (i == n - 1 ? "\n" : " "); return os;}
template<typename S, auto op, auto e, typename F, auto mapping, auto composition, auto id> ostream& operator<<(ostream& os, const atcoder::lazy_segtree<S, op, e, F, mapping, composition, id>& seg){int n = seg.max_right(0, [](S){return true;}); rep(i, n) os << seg.get(i) << (i == n - 1 ? "\n" : " "); return os;}

template<typename T> void chmin(T& a, T b){a = min(a, b);}
template<typename T> void chmax(T& a, T b){a = max(a, b);}

const long long INF = 1001001001001001;
using S = long long;
S _INF(INF);
S _ZERO(0LL);
using F = long long;
S apply(F f, S x){
	return f + x;
}

template<typename S, typename F>
struct Dijkstra{
	struct Edge{
		int from, to;
		F cost;
		Edge(int from, int to, F cost) : from(from), to(to), cost(cost) {};
	};
	int n, m;
	vector<bool> initialized;
	vector<Edge> E;
	vector<vector<int>> G;
	map<int, vector<S>> dist;
	map<int, vector<int>> idx;
	Dijkstra(int _n) : n(_n), m(0), initialized(n, false), G(n){}
	void add_edge(int from, int to, F cost){
		Edge e(from, to, cost);
		E.push_back(e);
		G[from].emplace_back(m);
		m++;
	}
	void calc(int s){
		initialized[s] = true;
		dist[s] = vector<S>(n, _INF);
		idx[s] = vector<int>(n, -1);
		priority_queue<tuple<S, int, int>, vector<tuple<S, int, int>>, greater<tuple<S, int, int>>> pq;
		pq.emplace(_ZERO, s, -1);
		while(pq.size()){
			auto [dist_from, from, index] = pq.top(); pq.pop();
			if(dist[s][from] <= dist_from) continue;
			dist[s][from] = dist_from;
			idx[s][from] = index;
			for(int index : G[from]){
				int to = E[index].to;
				S dist_to = apply(E[index].cost, dist_from);
				if(dist[s][to] <= dist_to) continue;
				pq.emplace(dist_to, to, index);
			}
		}
	}
	int farthest(int s){
		if(!initialized[s]) calc(s);
		int idx = 0;
		rep(i, n) if(dist[s][i] > dist[s][idx]) idx = i;
		return idx;
	}
	S get_dist(int s, int t){
		if(!initialized[s]) calc(s);
		return dist[s][t];
	}
	vector<int> restore(int s, int t){
		if(!initialized[s]) calc(s);
		if(dist[s][t] == _INF) return vector<int>(0);
		vector<int> res;
		while(idx[s][t] != -1){
			auto e = E[idx[s][t]];
			res.push_back(idx[s][t]);
			t = e.from;
		}
	reverse(res.begin(), res.end());
	return res;
	}
};
int main(){
	int n, m;
	cin >> n >> m;
	Dijkstra<long long, long long> graph(n);
	rep(i, m){
		int u, v;
		cin >> u >> v;
		u--; v--;
		graph.add_edge(u, v, 1);
		graph.add_edge(v, u, 1);
	}
	vector<long long> d(n, INF);
	rep(i, n) d[i] = graph.get_dist(0, i);
	vector<int> cnt(n + 1);
	rep(i, n){
		if(d[i] != INF) cnt[d[i]]++;
	}
	vector<int> p(2);
	rep(t, n + 1){
		p[t % 2] += cnt[t];
		if(t > 0) cout << p[t % 2] << "\n";
	}
	return 0;
}
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