結果
問題 | No.2558 中国剰余定理 |
ユーザー | Magentor |
提出日時 | 2024-09-18 16:32:42 |
言語 | C++23 (gcc 12.3.0 + boost 1.83.0) |
結果 |
AC
|
実行時間 | 92 ms / 2,000 ms |
コード長 | 3,967 bytes |
コンパイル時間 | 5,634 ms |
コンパイル使用メモリ | 317,028 KB |
実行使用メモリ | 6,944 KB |
最終ジャッジ日時 | 2024-09-18 16:32:49 |
合計ジャッジ時間 | 7,181 ms |
ジャッジサーバーID (参考情報) |
judge4 / judge1 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 2 ms
6,816 KB |
testcase_01 | AC | 2 ms
6,944 KB |
testcase_02 | AC | 24 ms
6,940 KB |
testcase_03 | AC | 2 ms
6,944 KB |
testcase_04 | AC | 92 ms
6,944 KB |
testcase_05 | AC | 2 ms
6,940 KB |
testcase_06 | AC | 2 ms
6,944 KB |
testcase_07 | AC | 2 ms
6,940 KB |
testcase_08 | AC | 21 ms
6,944 KB |
testcase_09 | AC | 3 ms
6,944 KB |
testcase_10 | AC | 9 ms
6,944 KB |
testcase_11 | AC | 14 ms
6,940 KB |
testcase_12 | AC | 4 ms
6,944 KB |
testcase_13 | AC | 2 ms
6,940 KB |
testcase_14 | AC | 2 ms
6,944 KB |
testcase_15 | AC | 5 ms
6,940 KB |
testcase_16 | AC | 25 ms
6,944 KB |
testcase_17 | AC | 3 ms
6,944 KB |
testcase_18 | AC | 28 ms
6,940 KB |
testcase_19 | AC | 37 ms
6,944 KB |
testcase_20 | AC | 8 ms
6,940 KB |
testcase_21 | AC | 18 ms
6,944 KB |
testcase_22 | AC | 2 ms
6,940 KB |
testcase_23 | AC | 3 ms
6,944 KB |
testcase_24 | AC | 28 ms
6,944 KB |
testcase_25 | AC | 29 ms
6,944 KB |
testcase_26 | AC | 4 ms
6,940 KB |
testcase_27 | AC | 3 ms
6,940 KB |
testcase_28 | AC | 18 ms
6,940 KB |
testcase_29 | AC | 2 ms
6,944 KB |
testcase_30 | AC | 10 ms
6,940 KB |
testcase_31 | AC | 5 ms
6,940 KB |
ソースコード
#include <bits/stdc++.h> using namespace std; #include <atcoder/all> using namespace atcoder; template<typename T> inline bool chmax(T &a, T b) { return ((a < b) ? (a = b, true) : (false)); } template<typename T> inline bool chmin(T &a, T b) { return ((a > b) ? (a = b, true) : (false)); } #define rep(i, n) for (long long i = 0; i < (long long)(n); i++) #define rep2(i, m ,n) for (int i = (m); i < (long long)(n); i++) #define REP(i, n) for (long long i = 1; i < (long long)(n); i++) typedef long long ll; #define updiv(N,X) (N + X - 1) / X #define l(n) n.begin(),n.end() #define mat vector<vector<ll>> #define YesNo(Q) Q==1?cout<<"Yes":cout<<"No" using P = pair<long long, long long>; const int MOD = 998244353LL; const ll INF = 999999999999999999LL; vector<long long> fact, fact_inv, inv; /* init_nCk :二項係数のための前処理 計算量:O(n) */ template <typename T> void input(vector<T> &v){ rep(i,v.size()){cin>>v[i];} return; } void init_nCk(int SIZE) { fact.resize(SIZE + 5); fact_inv.resize(SIZE + 5); inv.resize(SIZE + 5); fact[0] = fact[1] = 1; fact_inv[0] = fact_inv[1] = 1; inv[1] = 1; for (int i = 2; i < SIZE + 5; i++) { fact[i] = fact[i - 1] * i % MOD; inv[i] = MOD - inv[MOD % i] * (MOD / i) % MOD; fact_inv[i] = fact_inv[i - 1] * inv[i] % MOD; } } /* nCk :MODでの二項係数を求める(前処理 int_nCk が必要) 計算量:O(1) */ long long nCk(int n, int k) { assert(!(n < k)); assert(!(n < 0 || k < 0)); return fact[n] * (fact_inv[k] * fact_inv[n - k] % MOD) % MOD; } long long modpow(long long a, long long n, long long mod) { long long res = 1; while (n > 0) { if (n & 1) res = res * a % mod; a = a * a % mod; n >>= 1; } return res; } ll POW(ll a,ll n){ long long res = 1; while (n > 0) { if (n & 1) res = res * a; a = a * a; n >>= 1; } return res; } struct unionfind{ vector<int> par,siz; void reset(int n){par.resize(n);siz.resize(n);rep(i,n){par[i]=-1;siz[i]=1;}} int leader(int x){ if(par[x]==-1){return x;} else{return par[x] = leader(par[x]);} } bool same(int x,int y){ return leader(x)==leader(y); } bool merge(int x,int y){ x = leader(x);y=leader(y); if(x == y){return false;} if(siz[x] < siz[y]){swap(x,y);} par[y] = x; siz[x] += siz[y]; return true; } int size(int x){ return siz[leader(x)]; } }; struct graph{ vector<vector< pair<int,ll> > > val; void print(){ rep(i,val.size()){ rep(j,val[i].size()){ cout << val[i][j].first<<"/" <<val[i][j].second << " "; } cout << endl; } } void resize(int n){ val.resize(n); } void add(int n,int k,ll cost){ assert((int)(val.size())>k);val[ n ].push_back( pair(k,cost) ); } void add2(int n,int k,ll cost){ val[ n ].push_back( pair(k,cost) ); val[ k ].push_back( pair(n,cost) );} vector<ll> dfs_basic(int a){ vector<ll>seen(val.size(),-1); queue<int> q;q.push(a);seen[a]=0; while(!q.empty()){ int wc=q.front(); q.pop(); rep(i,val[wc].size()){ if(-1==seen[val[wc][i].first]){q.push(val[wc][i].first);seen[val[wc][i].first]=seen[wc]+val[wc][i].second;} } } return seen; } vector<ll>dijkstra(int r){ vector<ll> d(val.size(), INF); d[r] = 0; priority_queue<P, vector<P>, greater<P>> pq; pq.push(P(0, r)); while (!pq.empty()) { P p = pq.top(); pq.pop(); int dist = p.first, u = p.second; if (dist > d[u]) continue; for (ll i = 0LL; i < (int)(val[u].size()); i++) { int v = val[u][i].first, w = val[u][i].second; if (d[v] > d[u] + w) { d[v] = d[u] + w; pq.push(P(d[v], v)); } } } return d; } }; int main() { ll a,b,c,d;cin>>a>>b>>c>>d; rep(i,a*b){ if(i%a==c&&i%b==d){ cout << i << endl;return 0; } } }