結果
問題 | No.2901 Logical Sum of Substring |
ユーザー | 👑 binap |
提出日時 | 2024-09-21 06:01:01 |
言語 | C++17 (gcc 12.3.0 + boost 1.83.0) |
結果 |
WA
|
実行時間 | - |
コード長 | 3,816 bytes |
コンパイル時間 | 4,871 ms |
コンパイル使用メモリ | 277,384 KB |
実行使用メモリ | 95,472 KB |
最終ジャッジ日時 | 2024-09-21 06:01:16 |
合計ジャッジ時間 | 14,235 ms |
ジャッジサーバーID (参考情報) |
judge2 / judge5 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 2 ms
5,248 KB |
testcase_01 | AC | 2 ms
5,376 KB |
testcase_02 | WA | - |
testcase_03 | WA | - |
testcase_04 | WA | - |
testcase_05 | WA | - |
testcase_06 | WA | - |
testcase_07 | WA | - |
testcase_08 | WA | - |
testcase_09 | WA | - |
testcase_10 | WA | - |
testcase_11 | WA | - |
testcase_12 | WA | - |
testcase_13 | WA | - |
testcase_14 | WA | - |
testcase_15 | WA | - |
testcase_16 | WA | - |
testcase_17 | WA | - |
testcase_18 | WA | - |
testcase_19 | WA | - |
testcase_20 | WA | - |
testcase_21 | WA | - |
testcase_22 | WA | - |
testcase_23 | WA | - |
testcase_24 | WA | - |
testcase_25 | WA | - |
testcase_26 | WA | - |
testcase_27 | WA | - |
testcase_28 | WA | - |
testcase_29 | WA | - |
testcase_30 | WA | - |
testcase_31 | WA | - |
ソースコード
#include<bits/stdc++.h> #include<atcoder/all> #define rep(i,n) for(int i=0;i<n;i++) using namespace std; using namespace atcoder; typedef long long ll; typedef vector<int> vi; typedef vector<long long> vl; typedef vector<vector<int>> vvi; typedef vector<vector<long long>> vvl; typedef long double ld; typedef pair<int, int> P; ostream& operator<<(ostream& os, const modint& a) {os << a.val(); return os;} template <int m> ostream& operator<<(ostream& os, const static_modint<m>& a) {os << a.val(); return os;} template <int m> ostream& operator<<(ostream& os, const dynamic_modint<m>& a) {os << a.val(); return os;} template<typename T> istream& operator>>(istream& is, vector<T>& v){int n = v.size(); assert(n > 0); rep(i, n) is >> v[i]; return is;} template<typename U, typename T> ostream& operator<<(ostream& os, const pair<U, T>& p){os << '('<< p.first << ',' << p.second << ')'; return os;} template<typename T> ostream& operator<<(ostream& os, const vector<T>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : " "); return os;} template<typename T> ostream& operator<<(ostream& os, const vector<vector<T>>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : ""); return os;} template<typename T> ostream& operator<<(ostream& os, const set<T>& se){for(T x : se) os << x << " "; os << "\n"; return os;} template<typename T> ostream& operator<<(ostream& os, const unordered_set<T>& se){for(T x : se) os << x << " "; os << "\n"; return os;} template<typename S, auto op, auto e> ostream& operator<<(ostream& os, const atcoder::segtree<S, op, e>& seg){int n = seg.max_right(0, [](S){return true;}); rep(i, n) os << seg.get(i) << (i == n - 1 ? "\n" : " "); return os;} template<typename S, auto op, auto e, typename F, auto mapping, auto composition, auto id> ostream& operator<<(ostream& os, const atcoder::lazy_segtree<S, op, e, F, mapping, composition, id>& seg){int n = seg.max_right(0, [](S){return true;}); rep(i, n) os << seg.get(i) << (i == n - 1 ? "\n" : " "); return os;} template<typename T> void chmin(T& a, T b){a = min(a, b);} template<typename T> void chmax(T& a, T b){a = max(a, b);} int MAX; const int INF = 1001001001; struct S{ vector<pair<int, int>> left, right; int ans; int len; S(int x = -1){ ans = INF; len = 0; if(x == -1){ }else{ left = {{x, 1}}; right = {{x, 1}}; len++; if(x == MAX) ans = 1; } } int all(){ if(len == 0) return 0; return (left.back()).first; } }; S e(){ S res; return res; }; S op(S a, S b){ S res; res.left = a.left; res.right = b.right; res.len = a.len + b.len; if(a.len == 0) return b; if(b.len == 0) return a; res.ans = min(a.ans, b.ans); { int m = b.left.size(); int len = a.len; rep(i, m){ auto [val, time] = b.left[i]; int prod = a.all() | val; if(prod == MAX) chmin(res.ans, len + 1); if(a.all() == prod){ res.left.back().second += time; }else{ res.left.emplace_back(prod, time); } len += time; } } { int m = a.right.size(); int len = b.len; rep(i, m){ auto [val, time] = a.right[i]; int prod = val | b.all(); if(prod == MAX) chmin(res.ans, len + 1); if(b.all() == prod){ res.right.back().second += time; }else{ res.right.emplace_back(prod, time); } len += time; } } return res; }; int main(){ int n, k; cin >> n >> k; MAX = (1 << k) - 1; vector<int> a(n); cin >> a; int q; cin >> q; vector<S> init; rep(i, n) init.emplace_back(a[i]); segtree<S, op, e> seg(init); rep(_, q){ int t; cin >> t; if(t == 1){ int i, val; cin >> i >> val; i--; seg.set(i, S(val)); } if(t == 2){ int l, r; cin >> l >> r; l--; r--; auto res = seg.prod(l, r + 1); int ans = res.ans; if(ans == INF) cout << "-1\n"; else cout << ans << "\n"; } } return 0; }