結果
問題 | No.2797 Square Tile |
ユーザー |
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提出日時 | 2024-09-22 22:41:19 |
言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
結果 |
WA
|
実行時間 | - |
コード長 | 2,974 bytes |
コンパイル時間 | 1,709 ms |
コンパイル使用メモリ | 175,460 KB |
実行使用メモリ | 6,944 KB |
最終ジャッジ日時 | 2024-09-22 22:41:26 |
合計ジャッジ時間 | 3,051 ms |
ジャッジサーバーID (参考情報) |
judge1 / judge5 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 2 |
other | AC * 14 WA * 7 |
コンパイルメッセージ
main.cpp:20:17: warning: integer constant is so large that it is unsigned 20 | const ll llMIN=-9223372036854775808LL; | ^~~~~~~~~~~~~~~~~~~~~
ソースコード
#include "bits/stdc++.h"#include <atcoder/modint>using namespace std;using namespace atcoder;#define REP(i, n) for(ll i = 0;i < n;i++)#define ll long long//#define MOD 998244353LL#define MOD 1000000007LL//using mint = modint998244353;//using mint = modint1000000007;#define chmax(a,b) if ((a)<(b))a=(b);#define chmin(a,b) if ((a)>(b))a=(b);#define doublecout(a) cout<<setprecision(16)<<a<<endl;using vi = vector<ll>; // intの1次元の型に vi という別名をつけるusing vvi = vector<vi>; // intの2次元の型に vvi という別名をつけるusing vvvi = vector<vvi>; // intの2次元の型に vvi という別名をつけるconst ll llMAX=9223372036854775807LL;const ll llMIN=-9223372036854775808LL;#ifdef LOCAL#define dbg(x_) cerr << "?" << __LINE__ << ":" << #x_ << ":\t" << x_ << endl;#define print1(a0_) cerr << "?" << __LINE__ << ":" << #a0_ << "=" << a0_ << endl;#define print2(a0_,a1_) cerr << "?" << __LINE__ << ":" << #a0_ << "=" << a0_ << "," << #a1_ << "=" << a1_ << endl;#define print3(a0_,a1_,a2_) cerr << "?" << __LINE__ << ":" << #a0_ << "=" << a0_ << "," << #a1_ << "=" << a1_ << "," << #a2_ << "=" << a2_ << endl;#define print4(a0_,a1_,a2_,a3_) cerr << "?" << __LINE__ << ":" << #a0_ << "=" << a0_ << "," << #a1_ << "=" << a1_ << "," << #a2_ << "=" << a2_ << ","<< #a3_ << "=" << a3_ << endl;#define print5(a0_,a1_,a2_,a3_,a4_) cerr << "?" << __LINE__ << ":" << #a0_ << "=" << a0_ << "," << #a1_ << "=" << a1_ << "," << #a2_ << "=" << a2_ <<"," << #a3_ << "=" << a3_ << "," << #a4_ << "=" << a4_ << endl;#else#define dbg(...)#define print1(...)#define print2(...)#define print3(...)#define print4(...)#define print5(...)#endiftemplate<typename T1, typename T2>ostream &operator<<(ostream &s, const pair<T1, T2> &p) { return s<<"("<<p.first<<","<<p.second<<")"; }// vectortemplate<typename T>ostream &operator<<(ostream &s, const vector<T> &v) {int len=v.size();for(int i=0; i<len; ++i) {s<<v[i];if (i<len-1) s<<"\t";}return s;}// 2 dimentional vectortemplate<typename T>ostream &operator<<(ostream &s, const vector<vector<T> > &vv) {s<<endl;int len=vv.size();for(int i=0; i<len; ++i) s<<vv[i]<<endl;return s;}template<typename T1, typename T2>ostream &operator<<(ostream &s, const map<T1,T2> &mp) {int len=mp.size();for(auto t:mp) s<<t<<" ";return s;}void No() {cout << "-1" << endl;exit(0);}ll n,k,x,y;int main(){ll ans=0,a,b;cin >> a >> b;ll n=a*a+b*b;if (a==b){REP(i,a*2){REP(j,a*2){cout<<a*i<<" "<<a*j<<endl;}}return 0;}string ans1="";string ans2="";ll x=0,y=0;ll aa=a,bb=b;if (b>a)swap(aa,bb);ll x2=aa-bb,y2=aa;REP(i,n){ans1+=""+to_string(x)+" "+to_string(y)+"\n";ans2+=""+to_string(x2)+" "+to_string(y2)+"\n";x=(x+aa)%n;y=(y+bb)%n;x2=(x2+aa)%n;y2=(y2+bb)%n;}if (b>a)swap(ans1,ans2);cout<<ans1<<ans2;return 0;}