結果

問題 No.1 道のショートカット
ユーザー MMRZ
提出日時 2024-10-08 00:23:00
言語 C++23
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 5 ms / 5,000 ms
コード長 2,958 bytes
コンパイル時間 4,210 ms
コンパイル使用メモリ 294,188 KB
実行使用メモリ 6,820 KB
最終ジャッジ日時 2024-10-08 00:23:08
合計ジャッジ時間 5,868 ms
ジャッジサーバーID
(参考情報)
judge3 / judge4
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 4
other AC * 40
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

·# include <bits/stdc++.h>
using namespace std;
using ll = long long;
using ull = unsigned long long;
const double pi = acos(-1);
template<class T>constexpr T inf() { return ::std::numeric_limits<T>::max(); }
template<class T>constexpr T hinf() { return inf<T>() / 2; }
template <typename T_char>T_char TL(T_char cX) { return tolower(cX); }
template <typename T_char>T_char TU(T_char cX) { return toupper(cX); }
template<class T> bool chmin(T& a,T b) { if(a > b){a = b; return true;} return false; }
template<class T> bool chmax(T& a,T b) { if(a < b){a = b; return true;} return false; }
int popcnt(unsigned long long n) { int cnt = 0; for (int i = 0; i < 64; i++)if ((n >> i) & 1)cnt++; return cnt; }
int d_sum(ll n) { int ret = 0; while (n > 0) { ret += n % 10; n /= 10; }return ret; }
int d_cnt(ll n) { int ret = 0; while (n > 0) { ret++; n /= 10; }return ret; }
ll gcd(ll a, ll b) { if (b == 0)return a; return gcd(b, a%b); };
ll lcm(ll a, ll b) { ll g = gcd(a, b); return a / g*b; };
ll MOD(ll x, ll m){return (x%m+m)%m; }
ll FLOOR(ll x, ll m) {ll r = (x%m+m)%m; return (x-r)/m; }
template<class T> using dijk = priority_queue<T, vector<T>, greater<T>>;
# define all(qpqpq) (qpqpq).begin(),(qpqpq).end()
# define UNIQUE(wpwpw) (wpwpw).erase(unique(all((wpwpw))),(wpwpw).end())
# define LOWER(epepe) transform(all((epepe)),(epepe).begin(),TL<char>)
# define UPPER(rprpr) transform(all((rprpr)),(rprpr).begin(),TU<char>)
# define rep(i,upupu) for(ll i = 0, i##_len = (upupu);(i) < (i##_len);(i)++)
# define reps(i,opopo) for(ll i = 1, i##_len = (opopo);(i) <= (i##_len);(i)++)
# define len(x) ((ll)(x).size())
# define bit(n) (1LL << (n))
# define pb push_back
# define exists(c, e) ((c).find(e) != (c).end())
struct INIT{
INIT(){
std::ios::sync_with_stdio(false);
std::cin.tie(0);
cout << fixed << setprecision(20);
}
}INIT;
namespace mmrz {
void solve();
}
int main(){
mmrz::solve();
}
#define debug(...) (static_cast<void>(0))
using namespace mmrz;
void SOLVE(){
int n;
cin >> n;
int c;
cin >> c;
int v;
cin >> v;
vector g(n, vector<tuple<int, int, int>>());
{
vector<int> s(v), t(v), y(v), m(v);
rep(i, v)cin >> s[i], s[i]--;
rep(i, v)cin >> t[i], t[i]--;
rep(i, v)cin >> y[i];
rep(i, v)cin >> m[i];
rep(i, v){
g[s[i]].pb(make_tuple(t[i], y[i], m[i]));
}
}
vector dp(n, vector(c+1, hinf<int>()));
dp[0][c] = 0;
dijk<tuple<int, int, int>> pq;
pq.push(make_tuple(0, 0, c));
while(not pq.empty()){
auto [dis, cur_i, cur_c] = pq.top();
pq.pop();
for(auto [to, cost, e] : g[cur_i]){
if(cur_c-cost >= 0 && chmin(dp[to][cur_c-cost], dp[cur_i][cur_c]+e)){
pq.push(make_tuple(dp[to][cur_c-cost], to, cur_c-cost));
}
}
}
int ans = hinf<int>();
rep(i, c+1){
chmin(ans, dp[n-1][i]);
}
cout << (ans == hinf<int>() ? -1 : ans) << endl;
}
void mmrz::solve(){
int t = 1;
//cin >> t;
while(t--)SOLVE();
}
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