結果
問題 | No.27 板の準備 |
ユーザー |
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提出日時 | 2024-10-10 21:37:26 |
言語 | C#(csc) (csc 3.9.0) |
結果 |
AC
|
実行時間 | 44 ms / 5,000 ms |
コード長 | 3,642 bytes |
コンパイル時間 | 1,074 ms |
コンパイル使用メモリ | 116,680 KB |
実行使用メモリ | 31,616 KB |
最終ジャッジ日時 | 2024-10-10 21:37:29 |
合計ジャッジ時間 | 2,579 ms |
ジャッジサーバーID (参考情報) |
judge4 / judge2 |
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ファイルパターン | 結果 |
---|---|
other | AC * 18 |
コンパイルメッセージ
Microsoft (R) Visual C# Compiler version 3.9.0-6.21124.20 (db94f4cc) Copyright (C) Microsoft Corporation. All rights reserved.
ソースコード
using System;using System.Collections.Generic;using System.Linq;class Program{static string InputPattern = "InputX";static List<string> GetInputList(){var WillReturn = new List<string>();if (InputPattern == "Input1") {WillReturn.Add("28 29 30 30");//4//A=28が1枚,B=29が1枚,C=30が2枚の計4枚必要}else if (InputPattern == "Input2") {WillReturn.Add("2 3 7 15");//6//A=2が3枚,B=3が2枚,C=15が1枚の計6枚必要。//7はAを2枚、Bを1枚でつなげて作れば良い。}else if (InputPattern == "Input3") {WillReturn.Add("3 6 11 20");//5}else {string wkStr;while ((wkStr = Console.ReadLine()) != null) WillReturn.Add(wkStr);}return WillReturn;}//必要な板の長さの配列static int[] NeedLenArr;static void Main(){List<string> InputList = GetInputList();NeedLenArr = InputList[0].Split(' ').Select(X => int.Parse(X)).ToArray();List<int[]> LenCombiArrList = DeriveLenCombiArrList(NeedLenArr.Max());int AnswerCnt = int.MaxValue;string AnswerItaCombi = "";foreach (int[] EachCombiArr in LenCombiArrList) {bool FoundAnswer;int MinItaCnt;DeriveNeedMinCnt(EachCombiArr, out FoundAnswer, out MinItaCnt);if (FoundAnswer == false) continue;if (AnswerCnt < MinItaCnt) continue;AnswerCnt = MinItaCnt;AnswerItaCombi = "";Array.ForEach(EachCombiArr, X => AnswerItaCombi += X.ToString() + ",");}Console.WriteLine(AnswerCnt);//Console.WriteLine("ABCの板の長さは{0}", AnswerItaCombi);}//長さの組み合わせを求めるstatic List<int[]> DeriveLenCombiArrList(int pMaxLen){var WillReturn = new List<int[]>();for (int A = 1; A <= pMaxLen; A++) {for (int B = A; B <= pMaxLen; B++) {for (int C = B; C <= pMaxLen; C++) {var wkList = new int[] { A, B, C };int[] WillAdd = wkList.Distinct().ToArray();WillReturn.Add(WillAdd);}}}return WillReturn;}//4つの長さを満たす、最小の板の枚数を動的計画法で求めるstatic void DeriveNeedMinCnt(int[] pLenCombiArr, out bool pFoundAnswer,out int pMinItaCnt){//最小の枚数[長さの合計]なDP表int UB = NeedLenArr.Max();Nullable<int>[] DPArr = new Nullable<int>[UB + 1];//初期設定DPArr[0] = 0;foreach (int EachLen in pLenCombiArr) {for (int I = 0; I <= UB; I++) { //123ナップサックなのでリバースループしない//長さの和を求めるif (DPArr[I] == null) continue;int wkSumLen = I + EachLen;if (wkSumLen > UB) break;//枚数の和を求めるint wkSumCnt = DPArr[I].Value + 1;//枚数の最小値で更新可能かを判定if (DPArr[wkSumLen] == null|| DPArr[wkSumLen] > wkSumCnt) {DPArr[wkSumLen] = wkSumCnt;}}}pFoundAnswer = Array.TrueForAll(NeedLenArr, X => DPArr[X] != null);pMinItaCnt = NeedLenArr.Sum(X => DPArr[X] ?? 0);}}